similar to: Delete Dates from a vector.

Dear R-users, How do I obtain a sequence of dates consisting of only weekdays without the weekends in R? In S, I can do the following: timeSeq(from="12/17/2007", to="8/25/2008", by="weekdays") I tried using looking at timeSequence (fSeries package) and seq.Date (base package) but I do not know if I can specify "weekdays" rather than "day".

Hello All: I am trying to generate a sequence of dates using library(chron). Using the following code, I got most of what I want, dts <- seq.dates("01/02/1998", "01/10/2001", by="day") dts <- dts[!is.weekend(dts)] a sequence of weekdays only (no weekend dates), with first observation appearing as 01/02/98 and the last 01/10/01. But I would

Hello, I have a dataset which has fields giving both calendar date and weekday. I know better functions are now available, but I am still using chron because of the is.holiday() function and a homemade (even Heath Robinson would be ashamed) is.daylight() function. As a check for typos in the data input, I checked that the dates matched the weekdays. I'm getting some confusing results

Running R 2.13.1 on Windows XP. I would like to get week of the year (1-52) for each date. library(chron) dts <- dates(c("02/27/92", "02/27/92", "01/14/92","02/28/92", "02/01/92")) dts dts.chron <- as.chron(dts) dts.chron class(dts.chron) # all of these component extractions work: months(dts.chron) weekdays(dts.chron) years(dts.chron)

Hi, I am trying to count weekday of the month using R. For example, 1/4/2001 is the 4th weekday of Jan, and 1/5/2001 is the 5th weekday of the month, and 1/8/2001 is the 6th weekday of the month, etc. I get as far as extracting the weekdays from a sequence of dates (see below). But I have not yet figured out a fast way of counting without using a For Loop. Does anyone know how to do such counting

Hi All, I am iterating through dated materials, with variable start and end dates, and would like to skip procedures everytime I encounter a weekend or holiday. To do this, I thought the easiest way would be to create a TRUE/FALSE vector corresponding to each day where it is TRUE if a workday, and FALSE if a weekend or holiday. So far I have been able to do this for weekdays: startDate <-

Hello R-List, I have a question about recoding from a date time object.  I have tried using as.POSIXct objects and Chron Objects, but I can get the what I want. I need to create a new variable from a date-time object, adding "Office Time" for those events that happens between 08:00:00 to 18:00:00 and "Out of Office" all the others, but not including weekends. I have created a

I know that this is correct: library(chron) x = dates("01-03-04", format="d-m-y", out.format="day mon year") print(x) It gives me the string "01 Mar 2004" which is correct. I also know that I can say: print(day.of.week(3,1,2004)) in which case he says 1, for today is monday. My question is: How do I combine these two!? :-) I have a

This is mostly a RFC [but *not* about the many extra packages, please..]: Noticing to my chagrin how my students work in a project, googling for R code and cut'n'pasting stuff together, accumulating this and that package on the way all just for simple daily time series (though with partly missing parts), using chron, zoo, lubridate, ... all for things that are very easy in base R *IF*

Hi, how it's possible to extract the year and the number of days from Julian date. i'm little confused about the last two functions and ?years . EDATE comes from sqlQuery with as.is=T EDATE <- as.POSIXlt(datvears$ENROLLDAY) Many thanks, Christian > EDATE[1:5] [1] "2000-06-30 11:25:01" "2000-06-30 11:39:55" "2000-06-30 12:11:11" [4]

Hi, all Here I created a data frame like mydates<- seq(as.Date("2010-05-29"), length = 43, by = "day") myvalues<-runif(43,0,1) myframe<-data.frame(dates=mydates, day=weekdays(dates), value=myvalues) dates day value 1 2010-05-29 Saturday 0.14576143 2 2010-05-30 Sunday 0.37669604 3 2010-05-31 Monday 0.74813943 4 2010-06-01 Tuesday

Hello, I am trying to do a loop with dates, but when I try to use the index is not a date. Fcorte <- as.Date('2008/11/30',format = "%Y/%m/%d") fini <- Fcorte + 1 ffin <- seq(fini,by='months',length=2)[2] - 1 for (i in seq(fini,to = ffin, by='days')) print (weekdays(i)) # i doesn't a date How can I do a loop with dates and get the

Hello, I have some unbalanced panel data that is measured on weekdays only (i.e., excluding Saturday and Sunday). I would like to get the number of days between dates such that the number of days between a Friday and a Monday is 1 (and not 3). Here is some code to illustrate my problem: library('Hmisc'); DATE <-

Full_Name: Kem Phillips Version: 2.7.1 (2008-06-23) OS: Windows Xp professional Submission from: (NULL) (98.221.200.108) The Hmisc function describe fails, giving the error message: Error in formatDateTime(dd, atx, !timeUsed) : could not find function "format.dates" Loading the chron package, where function dates apparently resides, does not fix the problem. Note

Proper calendar dates in R are great for plotting and calculating. However for the non-wonks among us, they can be very frustrating. I have recently discussed the pains that people in my lab have had with dates in R. Especially the frustration of bringing date data into R from Excel, which we have to do a lot. Please find below a simple analgesic for R date importation that I discovered over

I am trying to do some basic regression and ANOVA on cycle times (numeric vectors) across weekdays (character vector), where I have simply labelled my days as: days<- c("mon","tue","wed"...etc). (NOTE: There are actually multiple instances of each day, and the data is read-in from a .dat file.) I have no trouble at all with the actual number crunching, It is the

I built R 2.2.0 from source on my debian machine yesterday and updated all packages. My problem is that "dates" function from its, that my code heavely uses is now masked by "dates" from chron. How can I specify tehat I want to use dates from its or how can I prevent it from being masked? > library(its) Loading required package: Hmisc Hmisc library by Frank E Harrell Jr

Hello R users, I have to import a file with one column containing dates written in French short format, such as: 7-d?c-07 11-d?c-07 14-d?c-07 18-d?c-07 21-d?c-07 24-d?c-07 26-d?c-07 28-d?c-07 31-d?c-07 2-janv-08 4-janv-08 7-janv-08 9-janv-08 11-janv-08 14-janv-08 16-janv-08 18-janv-08 There are other columns for other (numeric) variables in the

Dear all I use aggregate with variables of type numeric and dates. For type numeric functions, such as sum() are very fast, but similar simple functions, such as min() are much slower for the variables of type 'dates'. The difference gets bigger the larger the 'id' var is - but see this sample code: dts <- dates(c("02/27/92", "02/27/92",

Hi all, I have problems with years of dates using "chron" package. I don't understand why R by this istruction: > dates("01/02/29",out.format="d/m/year") [1] 02/Jan/2029 > dates("01/02/30",out.format="d/m/year") [1] 02/Jan/1930 reads "29" as 2029 and "30" as 1930. How could I change to read "00" to