similar to: Dates in Common

Taking the Grunfeld data, which is built-in in R, for example, (1)How can I construct a dataset (or dataframe) that consists of the data of all firms in 1951? (2)How can I calculate the average capital in each form over the period 1951-1954? What I can imagine is to categorize the data by firm, and then select the data between 1951 and 1954 for each firm, but how can I do it? Thanks, Miao

Hello, i have following problem and I hope you can help me a little bit My dataframe looks like: df a m d typ value 1950 1 1 5 -4.1 1950 1 2 9 2.7 1950 1 3 3 -1.3 1950 1 4 5 -1.9 1950 1 5 2 0.2 1950 1 6 8 0.5 1951 1 1 4 1.3 .... It consists by daily observations from 1950- 2009. Now, I get with.... for (i

Assume that I have the dataframe "data1", which is listed at the end of this message. I want count the number of lines that each person has for each year. For example, the person with ID=213 has 15 entries (NinYear) for 1953. The following bit of code calculates NinYear: for (i in 1:length(data1$ID)) { data1$NinYear[i] <- length(data1[data1$Year==data1$Year[i] &

R-help users, Thanks in advance for any assistance ... I truly appreciate your expertise. I searched help and could not figure this out, and think you can probably offer some helpful tips. I apologize if I missed something, which I'm sure I probably did. I have data for many "samples". (e.g. 1950, 1951, 1952, etc.) For each "sample", I have many data-frames.

Hi there, I have a data.frame (pwt6) which I would like to transform: country year gdp MEX 1950 2 MEX 1951 5 BOL 1950 4 BOL 1951 12 ITA 1950 45 ITA 1951 2 This should be the result: year MEX.gdp BOL.gdp ITA.gdp 1950 2 4 45 1951 5 12 2 Right now I have this code (better - no code): country.label<-names(table(pwt6$country)) result<-data.frame(year=NULL) for(i in country.label) ?

Dear R experts, I'm reading data from an online database via API and it gets delivered in this messy comma separated structure, > RAW.API <-

Dear all, I am trying to read in and assign data from 50 tables in an automated fashion. I have the following code, which I created with the help of textbooks and the internet, but it only seems to read in the final data file over and over again. For example, when I type:> table_1951 I get the same values in the table as when I type> table_2000 despite the values in the source tables

Dear R-users, I have a complex line by xy-values (ordered by z). And I would like to get interpolated y-values on the positions of x = 0:600. How do I get the correct points? x=c(790,790,790,790,790,786,783,778,778,766,763,761,761,761,715,628,521,350,160,134,134,129,108,101,93,111,161,249,288,243,139,45,7)

https://bugzilla.mindrot.org/show_bug.cgi?id=1951 Bug #: 1951 Summary: Add home directory facility for chrooted environments Classification: Unclassified Product: Portable OpenSSH Version: -current Platform: All OS/Version: All Status: NEW Severity: enhancement Priority: P2 Component: sshd

Dear R-users, I would like to ask whether it's possible (for sure it would be), to plot each rows (or columns) in different graphs and in the same figure region without using the function "par" and then struggling around with "axes" and labels etc. Luckily, I would always have "rows + columns = even number" and the same "ylim". The next one could be a

If I create a bivariate ts series with 3 time points and run na.omit on it expecting it to reduce it to a one point ts series instead I get the following error messasge: R> hh <- ts(matrix(c(NA,1:4,NA),3), start = c(1951,8), freq=12) R> hh Series 1 Series 2 Aug 1951 NA 3 Sep 1951 1 4 Oct 1951 2 NA R> na.omit(hh) Error in

hi, i am new to using r .so if you can pls tell me how to read "1951-52" ,"1952-52" date format in r [[alternative HTML version deleted]]

Dear Rui and UseRs,[a text file has also been attached, in case the format of my email is difficult to get]I am extremely sorry that I am bothering you once again, but I?ll have to get to the bottom of it. The following command sp <- lapply(split(agg, agg$st), function(x) x[order(x$year, x$month), ]) gave me an output with monthly mean of population(as under). i am not able to apply

Dear all, I am trying to manually re-sort rows in a number of tables. The rows aren't sorted on any particular values but are simply ordered by user choice (as shown by the row numbers in the code). I have been able to carry out each re-arrangement without the use of the 'for' loop, but cannot seem to successfully execute the statements when incorporated into the loop. The code I have

Dear Sirs, Anybody ever tried running SIP up against Voicepulse? On their http://connect.voicepulse.com they claim they support both SIP and IAX, but I can't seem to get SIP running. I have as mentioned before on this list - huge problems getting any timing devices running on some of my machines, so IAX is not really an option right now. If I try I get a "Service Unavailable"

Hi, I use the ROracle interface in the R 64bit version. When I fetch a large number of rows from the database I get alternating 250 rows of what I want to see and than 250 rows junk and so on. It does not matter whether I use the fetch command or dbGetquery or whatever. My fetch_default_rec = 500 and I can not change it by setting it explicitly in Oracle(). Any idea what's the problem

Hi, again i am stuck in my presentation, and i have never learn R before in my life but need this to be done, so please help me out for a favour: http://www.nabble.com/file/p20333155/kew.dat kew.dat run this in R and these comes up: Month Year Rain 1 Jan 1900 74.400000 2 Feb 1900 80.500000 3 Mar 1900 23.600000 4 Apr 1900 23.600000 5 May 1900 25.100000 6

Hello all! I have a problem to extract values greater that for example 1820. I try this code: x[x[,1]>1820,]->x1 Please help me! Thank you! The data structure is: structure(c(2.576, 1.728, 3.434, 2.187, 1.928, 1.886, 1.2425, 1.23, 1.075, 1.1785, 1.186, 1.165, 1.732, 1.517, 1.4095, 1.074, 1.618, 1.677, 1.845, 1.594, 1.6655, 1.1605, 1.425, 1.099, 1.007, 1.1795, 1.3855, 1.4065, 1.138, 1.514,

Hello! According to ActiveRecord transactions documentation, User.transaction do User.create(:username => ''Kotori'') User.transaction(:requires_new => true) do User.create(:username => ''Nemu'') raise ActiveRecord::Rollback end end User.find(:all) # => Returns only Kotori But I get both records in database (tested on

Hi Ron, I don't remember right now, but you can try this command: cli> manager set debug off Cheers El 26 mar. 2017 3:58, "Telium Technical Support" <support at telium.ca> escribi?: I somehow cause AMI events to appear as output in the CLI, and I can?t figure out how to turn them off. Can someone offer a command which will suppress AMI events/commands from showing in