similar to: obtaining null components of a list

Dear R experts: I've seen that it's possible to make a sort of "slideshow" with several R-plots (each slide is activated by a click on the mouse). How can I put this on a R-script??? Regards. D. [[alternative HTML version deleted]]

Hello R experts! Last week I run in to a lot a problems triyng to fit an ARIMA model to a time series. The problem is that the internal process of the arima function call function "optim" to estimate the model parameters, so far so good... but my data presents a problem with the default method "BFGS" of the optim function, the output error looks like this: Error en

Hello experts! Is there a way to send an internal variable from a function to the workspace????, besides the function output, of course Thanks!! D. [[alternative HTML version deleted]]

Hello everybody! I have an ARIMA model for a time series. This model was obtained through an auto.arima function. The resulting model is a ARIMA(2,1,4)(2,0,1)[12] with drift (my time series has monthly data). Then I perform a 12-step ahead forecast to the cited model... so far so good... but when I look the plot of my forecast I see that the result is really far from the behavior of my time

Hello R experts! I'm running a FOR loop in which at every step an arima model is generated. The problem is some series produces numeric problems with optim. My question is if there is a way of telling to R that at every critical error of optim jumps to the next series instead of stopping the calculations. Or better yet, tell it to run another arima fit but with a different optmization

Dear R-folks: I have a group of data ('x' and 'y' axis), but I'd like to know how to draw a graph which would fits my data in a better way, I also need its equation. Could you give me any R-rutine ideas?. I thank you in advance for your kind support. [[alternative HTML version deleted]]

examples: 1) Fails to report that components 2 and 3 differ all.equal(list(1,2,3,zap=1),list(1,3,4,zap=2)) [1] "Component zap: Mean relative difference: 1 2) Incorrectly asserts all are equal when components 2 and 3 differ > all.equal(list(1,2,3,zap=1),list(1,3,4,zap=1)) [1] TRUE 3) Removing named component reveals differences: > all.equal(list(1,2,3,1),list(1,3,4,1)) [1]

Hi, If I do the following I can have a NULL in a list > x <- list( 1, list(3,NULL,4), 5 ) > x [[1]] [1] 1 [[2]] [[2]][[1]] [1] 3 [[2]][[2]] NULL [[2]][[3]] [1] 4 [[3]] [1] 5 This is a good thing for me as it can be passed through into C++ where I can know the value is missing. (Can't seem to detect a NA from C++ for some reason. There is RF_isNull in the API but no RF_isNA

>Date: Wed, 17 Jul 2002 07:39:06 +0100 (BST) >From: Prof Brian D Ripley <ripley at stats.ox.ac.uk> >Subject: Re: [R] R GUI and object browser > >This may be appealing, but > >1) R objects such as lists have shared components. You get the creation >date of the object, not of it components, and in any case I suspect you >want the last modification date. Do you mean

Dear All, I manage a Debian Squeeze GNU/Linux (with kernel 2.6.32-5-686 #1 SMP) with Samba 3.5.6 (samba 2:3.5.6~dfsg-3squeeze8 package is installed). I have a "test" directory with native Linux ACL permissions. getfacl test's output: # file: test # owner: akos # group: grp # flags: -s- user::rwx group::rwx group:read:r-x mask::rwx other::--- default:user::rwx default:group::rwx

Dear list, Utils::modifyList() drops NULL components in its second argument, instead of adding them to the first argument. Compare: > modifyList(x=list(A=1), val=list(B=2, C=3)) $A [1] 1 $B [1] 2 $C [1] 3 > modifyList(x=list(A=1), val=list(B=NULL, C=3)) $A [1] 1 $C [1] 3 To me this seems inconsistent with the documentation ("Elements in 'val' which are missing from

Hi how do I extract those components of a list that satisfy a certain requirement? If jj <- list(list(a=1,b=4:7),list(a=5,b=3:6),list(a=10,b=4:5)) I want just the components of jj that have b[1] ==4 which in this case would be the first and third of jj, viz list (jj[[1]],jj[[3]]). How to do this efficiently? My only idea was to loop through jj, and set unwanted components to NULL,

Dear all, I have a question about deleting components of a list. For example, I have a list that looks like this: [[1]] var1 var2 var3 1 3 4 2 2 1 [[2]] var1 var2 var3 2 5 1 2 1 7 [[3]] var1 var2 var3 1 6 7 3 8 4 How to delete, say, the first columns of the list or the second rows? Thank in advance. Lisa -- View

I get a list object from an iterative function. I'm trying to figure out the most efficient way to calculate the mean of one element, across all components of the overall list. I've tried output <- mean (listobject[[1:5]]$element) to get the mean of "element" in the first five components? It doesn't like the $. I'm suspect one of the "apply" functions

> On 2016-Jan-15, at 06:46, Keno Fischer <kfischer at college.harvard.edu> wrote: > > Looking at this again, I think I was under the mistaken impression that the DISubprogram's scope would have to be the compile unit, but it seems we also currently allow it to be a DIFile (or any other kind of scope). In that case, I suppose the behavior that the backend expects is that every

like this, the list is below, I want to remove the last one . not using newlist[-2], but using the function detect its component is numeric(0) and then remove it from the list. newlist [[1]] [1] 2 3 [[2]] [1] numeric(0) [[3]] [1] 7 [[alternative HTML version deleted]]

Dear R-users, How can I detect a NULL in a recursive list? For a regular list I could use lapply: > lapply(list(x=NULL), is.null) $x [1] TRUE However that doesn't work for structures like list(list(x=NULL)). I tried rapply but it treats NULL as a list and discards them: > rapply(list(a=1, b=list(x=NULL)), is.null) a FALSE Any suggestion? Thank you for your help, Vadim Note:

I'm attempting to generalise a function that reads individual list components, in this case they are matrices, and converts them into 3 dimensional array. I can input each matrix individually, but want to do it for about 1,000 of them ... This works array2 <- abind(list1[[1]],list1[[2]],list1[[3]],along=3) This doesn't array2 <- abind(list1[[1:3]],along=3) This doesn't either

On Fri, Jan 15, 2016 at 11:24 AM, David Blaikie <dblaikie at gmail.com> wrote: > Diego: To include line/col info for backend diagnostics, we produced debug > info but omitted the llvm.dbg.cu entry, right? So there are subprogram > debug info descriptions that are not referenced from a CU in llvm.dbg.cu, > yes? > Yes, that and for sample PGO. Omitting llvm.dbg.cu prevents

rutine -> routine Also MSVC complains that FLAC__uint32* (unsigned int*) is not of the same type as unsigned long* --- a\src\libFLAC\include\private\bitmath.h 2013-08-13 13:30:24.000000000 +0400 +++ b\src\libFLAC\include\private\bitmath.h 2013-08-14 10:20:51.484053700 +0400 @@ -78,12 +78,12 @@ return _bit_scan_reverse(v) ^ 31U; #elif defined(__GNUC__) && (__GNUC__ >= 4 ||