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More information: When I try to access the share by "smbclient //server_ip_address/share_name -d 10" from another Linux box, I saw some errors(warnings?) like "Doing spnego session setup (blob length=16) server didn't supply a full spnego negprot" Juer -----Original Message----- From: Juerlee (PLS CN) [mailto:jlee@plasmon.cn] Sent: Tuesday, November 29, 2005 17:14 To:

I'm not an expert on that, but did you tried the following settings on smb.conf for your share : admin users = NTDOMAIN+Administrator valid users = ..... I think this is necessary to use ACL with samba and ntdomain... -----Urspr?ngliche Nachricht----- Von: Gerald (Jerry) Carter [mailto:jerry@samba.org] Gesendet: Montag, 28. Februar 2005 16:43 An: Juer Lee Cc: samba@lists.samba.org Betreff:

A late friday afternoon coding question. I'm having a hard time thinking of the correct search terms for what I want to do. If I have a df like this: a <- data.frame(name=c(rep('a',10),rep('b',15)),year=c(1971:1980,1971:1985),amount=1:25) name year amount 1 a 1971 1 2 a 1972 2 3 a 1973 3 4 a 1974 4 5 a 1975 5 6 a 1976

Hi all: I'm struggling with getting my data re-formatted using functions in reshape/reshape2 to get from: 1957 0.862500000 1958 0.750000000 1959 0.300000000 1960 0.287500000 1963 0.675000000 1964 0.937500000 1965 0.025000000 1966 0.387500000 1969 0.087500000 1970 0.275000000 1973 0.500000000 1974 0.362500000 1976 0.925000000 1978 0.712500000 1979 0.337500000 1980 0.700000000 1981 0.425000000

Hello, We are looking to adjust the font size of the axis annotation on the graph that results from use of the metaplot() function. Metaplot seems to respond to cex and cex.lab to change those graphical parameters, but it doesn't respond to cex.axis. Is there a way to work around this by creating a customized x-axis, and if so, how? Thanks for all your help. Syntax is below. Best, Dawn

Hello all! I have a problem with ggplot2 library. I want to do an heat map and the y variables are the year months. If I use the following code, he y values are in alphabetical order, but I want it in month order. The code is: library(reshape) library(ggplot2) library(scales) p <- ggplot(data.m, aes(variable, Month)) + geom_tile(aes(fill = value),

This does not use reshape/reshape2, but it is pretty straightforward. Assuming X is your example data: > Y <- split(X[, 2], X[, 1]) > vals <- sapply(Y, length) > pad <- max(vals) - vals > Y2 <- lapply(seq_along(Y), function(x) c(Y[[x]], rep(NA, pad[x]))) > names(Y2) <- names(Y) > X2 <- do.call(cbind, Y2) > X2[, 1:6] 1957 1958 1959

The reason it doesn't work easily with reshape/reshape2 is that the order of the rows is not determined. Your answer could be 1957 1958 ... 1985 1986 0.8625000 0.7500000 ... 0.7307692 0.23750000 0.0733945 0.6435644 ... NA 0.05769231 0.5096154 NA ... NA 0.65137615 or 1957 1958 ... 1985 1986 0.0733945 0.6435644 ... NA

Hi Tom, Or perhaps: #assume the data frame is named "tadf" library(prettyR) stretch_df(tadf,1,2) Jim On Thu, Jul 6, 2017 at 6:50 AM, Ista Zahn <istazahn at gmail.com> wrote: > The reason it doesn't work easily with reshape/reshape2 is that the > order of the rows is not determined. Your answer could be > > 1957 1958 ... 1985 1986 >

Hello, I could need some help on this one: >From the data.frame "Test.dataset2" below (TSCS data for 151 "countries.to.map" for "year" 1973-95; each "country.to.map" is described by a unique code), I would like to extract a vector "color" that for each "country.to.map" takes on the value of "dv" (a categorical variable with

Hi, again i am stuck in my presentation, and i have never learn R before in my life but need this to be done, so please help me out for a favour: http://www.nabble.com/file/p20333155/kew.dat kew.dat run this in R and these comes up: Month Year Rain 1 Jan 1900 74.400000 2 Feb 1900 80.500000 3 Mar 1900 23.600000 4 Apr 1900 23.600000 5 May 1900 25.100000 6

Dear R-users, I have a complex line by xy-values (ordered by z). And I would like to get interpolated y-values on the positions of x = 0:600. How do I get the correct points? x=c(790,790,790,790,790,786,783,778,778,766,763,761,761,761,715,628,521,350,160,134,134,129,108,101,93,111,161,249,288,243,139,45,7)

*Call for Papers* *IEEE Computing in Science & Engineering* ** *Special Issue on Cloud Computing in Science & Engineering* http://www.computer.org/portal/web/computingnow/cise ** *Submissions due: November 04, 2012* *Estimated Publication date: July/August, 2013* Cloud computing has emerged as a dominant paradigm that has been widely adopted by enterprises. Clouds provide on-demand

*Call for Papers* *IEEE Computing in Science & Engineering* ** *Special Issue on Cloud Computing in Science & Engineering* http://www.computer.org/portal/web/computingnow/cise ** *Submissions due: November 04, 2012* *Estimated Publication date: July/August, 2013* Cloud computing has emerged as a dominant paradigm that has been widely adopted by enterprises. Clouds provide on-demand

Hello all! I have a problem to extract values greater that for example 1820. I try this code: x[x[,1]>1820,]->x1 Please help me! Thank you! The data structure is: structure(c(2.576, 1.728, 3.434, 2.187, 1.928, 1.886, 1.2425, 1.23, 1.075, 1.1785, 1.186, 1.165, 1.732, 1.517, 1.4095, 1.074, 1.618, 1.677, 1.845, 1.594, 1.6655, 1.1605, 1.425, 1.099, 1.007, 1.1795, 1.3855, 1.4065, 1.138, 1.514,

Hello, how do you create a histogram with a data frame? year snow.cover 1970 6.5 1971 12.0 1972 14.9 1973 10.0 1974 10.7 1975 7.9 ... mydata=data.frame(year=c(1970,...),snow.cover=c(6.5,...)) hist(mydata) does not work. Many thanks. PR

I am trying to extract only the winters (defined to be 01-Dec through 28-Feb) of daily data from 1948-2002. There are 90 days in each winter season. I wrote the following code to gather the winter dates into a single vector: DJF <- NULL for(year in 1949:1999) { temp.begin <- strptime(paste("01/12", year-1, sep="/"), "%d/%m/%Y") temp.end <-

Hello all! I have a problem with R. I try to merge data like this: structure(c(2.1785, 1.868, 2.1855, 2.5175, 2.025, 2.435, 1.809, 1.628, 1.327, 1.3485, 1.4335, 2.052, 2.2465, 2.151, 1.7945, 1.79, 1.6055, 1.616, 1.633, 1.665, 2.002, 2.152, 1.736, 1.7985, 1.9155, 1.7135, 1.548, 1.568, 1.713, 2.079, 1.875, 2.12, 2.072, 1.906, 1.4645, 1.3025, 1.407, 1.5445, 1.437, 1.463, 1.5235, 1.609, 1.738, 1.478,

Hi Experts, I would like to present time series data in meaningful way in building some graphics. I've tried: (1) plot(ts(mbaye3)) and (2) plot(ts(mbaye3), start=1990) But I always get this error-message: Fehler [error] in plotts(x = x, y = y, plot.type = plot.type, xy.labels = xy.labels, : cannot plot more than 10 series as "multiple" my data: mbaye3

I''m looking at possibly going with Image Science (http:// seattlerb.rubyforge.org/ImageScience.html) for an application in development. I''ve heard that it is a lot less overhead than RMagick and we really don''t have any complex image requirements. Are there any folks out there using Image Science that could chime in with some feedback? Also, I have a couple specific