similar to: Question about the RWEKA package

Hello List, I`m trying to make prediction using a bagged tree with the package ipred. I tried to follow the manual but I`m getting an error message. Also browsing through the list-archive I didn`t find any hint. Maybe someone can help me? selbag <- bagging(SOIL_UNIT ~., data=traindat.bin, coob=TRUE) Error in dimnames(X) <- list(dn[[1L]], unlist(collabs, use.names = FALSE)) :

Hi list, I´m working on a predictive modeling task using the caret package. I found the best model parameters using the train() and trainControl() command. Now I want to evaluate my model and make predictions on a test dataset. I tried to follow the instructions in the manual and the vignettes but unfortunately I´m getting an error message I can`t figure out. Here is my code: rfControl <-

Dear All, I am finding trouble trying to guild a Wrapper using random forest to evaluate the subsets: I do: nombi <- make_Weka_filter("weka/filters/supervised/attribute/AttributeSelection") datbin<- nombi(gene ~., data=X1X2X4X5W, control =Weka_control( S=list("weka.attributeSelection.GeneticSearch"), E=list("weka.attributeSelection.WrapperSubsetEval"),B

Hello, I want to draw 3D cylinder objects in R. Given is the length and the diameter of the cylinder. Has anybody an example? Thank you very much! Best regards -- ---------------------- Dr. Hans-Joachim Klemmt Forstoberrat Organisationsprogrammierer IHK Bayerische Landesanstalt f?r Wald und Forstwirtschaft zugewiesen an Lehrstuhl f?r Waldwachstumskunde Technische Universit?t M?nchen

Dear all, I am trying to construct a wrapper that uses random forest to evaluate the subsets using RWeka and when I do: nombi <- make_Weka_filter("weka/attributeSelection/WrapperSubsetEval") datbin<- nombi(gene ~., data=X1X2X3X4W, control =Weka_control( B = list("weka.classifiers.trees.RandomForest"))) I also have tried with an other induction algorithm:

The data frame is lwf that records the survival of bushes over an 8 year period. Years are called bouts. Dead bushes are recorded as zeros, and live bushes as "1." str(lwf) 'data.frame': 638 obs. of 9 variables: $ bushno: int 1 2 3 4 5 6 7 8 9 10 ... $ bout1 : int 0 1 0 1 1 1 0 1 0 1 ... $ bout2 : int 0 1 0 0 0 0 0 0 0 1 ... $ bout3 : int 0 1 0 0 0 0 0 0 0 1 ... $

Hi, I use a mboost model to predict my dependent variable on new data. I get the following warning message: In bs(mf[[i]], knots = args$knots[[i]]$knots, degree = args$degree, : some 'x' values beyond boundary knots may cause ill-conditioned bases The new predicted values are partly negative although the variable in the training data ranges from 3 to 8 on a numeric scale. In order to

Hi List, Im new to postfix-dovecot and im mystified by the following results in ubuntu 10.04lts :~$ dovecot -n # 1.2.9: /etc/dovecot/dovecot.conf Error: ssl_key_file: Can't use /etc/ssl/private/ssl-mail.key: Permission denied Fatal: Invalid configuration in /etc/dovecot/dovecot.conf ~$ sudo ls -dl /etc/ssl/private/ssl-mail.key lrwxrwxrwx 1 root root 38 2013-11-27 08:35

Dear List, I´m working on a classification problem. My response has 60 levels. I`m very interested in boosted trees like AdaBoost or gradient boosting machine as implemented in the package "gbm". Unfortunately gbm is only applicable for 2-class problems. Is anybody out there who can help me? Is there a way to use gbm() for multi-class problems? Maybe there is a way to transform my

Hello, I came across a problem when building a randomForest model. Maybe someone can help me. I have a training- and a testdataset with a discrete response and ten predictors (numeric and factor variables). The two datasets are similar in terms of number of predictor, name of variables and datatype of variables (factor, numeric) except that only one predictor has got 20 levels in the training

Dear list, I have found a thread dealing with similar problems with a Mac, but somehow I cannot get it to work and the problem is slightly different: I am using the shell() command to execute a program from within R. The problem is that I need to execute SDKShell.bat file first that sets the environment variables for the program ogr2ogr.exe: shell(cmd =

I have a data set something like this: "YYYY", "Value" 1972 , 117 1984 , 73 1969 , 92 1976 , 113 1999 , 80 1996 , 78 1976 , 98 1984 , 106 1976 , 99 it could be created with: > dafSamp <- data.frame(cbind(c(1972,1984,1969,1976,1999,1996,1976,1984,1976),c(117,73,92,113,80,78,98,106,99))) The real dataset is of cause much larger, app. 100.000 samples

Gracias, Jorge le echo un vistazo al link y te digo algo Un saludo Date: Wed, 11 Mar 2015 16:22:11 +0100 Subject: Re: [R-es] Pregunta sobre Simplificación de Poligonales con R From: jayusor en gmail.com To: fjroar en hotmail.com CC: r-help-es en r-project.org Hola, Esto lo hice algún tiempo para no hacer tan pesado los dibujos, si buscar por "R simplify shp" encuentras cosas, por

Hi, under the new version R 2.7.1 I can't use WinEdt. It seems that there is a bug in that version. To use older versions of the package RWinEdt doens't bring success. The Use of R 2.7.0 doesn't cause that Problem. Regards, Hans-J?rgen Auinger -- ---------------------------------------------- Hans-J?rgen Auinger Lehrstuhl f?r Pflanzenz?chtung Wissenschaftszentrum Weihenstephan

Hello together, I am working on liquid water profiles of clouds and would like to describe these profiles in relation to a reference profile. What is the best way to do this ? RMSE would equal positiv and negativ deviations. Is it better to use a correlation coefficient ? What is the best way, espacially when I want to find out profiles with the same behaviour / shape, which are just more or less

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 On Thu, 6 Feb 2014, Phil wrote: > Im new to postfix-dovecot and Unix/Linux, too? > and im mystified by the following results in ubuntu > 10.04lts > > :~$ dovecot -n > # 1.2.9: /etc/dovecot/dovecot.conf > Error: ssl_key_file: Can't use /etc/ssl/private/ssl-mail.key: Permission > denied >

Hi guys i need some help to build choropleth. Basically i am trying to colour regions on the map by population. I possess the shape file of the country, and also the population data, however, i am having trouble to create the plot, below is my code: population=read.csv("nz2.csv") population names(population) nz=readShapeSpatial((sprintf('nz-geodetic-marks',tmp_dir)))

This e-mail - summarizes some of the responses/suggestions to using R for 13 year olds from my query on this list - discusses some additional investigation I did - the approach I am currently using (which will likely incorporate your suggestions for R) SUGGESTIONS - find relationship between monthly heating bills and temperature. For data see

Hi. I enabled policies with pdbedit. Password must be changed every 90 days and must contain at least 8 characters. I enabled password history too. After that (I tried it in samba 3.4.3 and 3.0.25 with same behaviour) every time a user try to log in the domain using Windows receives a "Your password expires today. Do you want to change it now ?" message box. If the password is changed,

Hi all, Probably a simple question, but I just can't find a simple answear in the older threads or anywhere else. I've added some new vectors as columns in a data frame using cbind(). As they're all put as the last columns inte the data frame, I would like to move them to specific positions. How do you do to change the position of a column in a data frame? I know I can use