similar to: R badly lags matlab on performance?

Dear all, Playing with a toy problem, I wondered how much it costs to generate `internal' objects in a function that are not strictly needed. An example: mean(apply(t(matrix(as.vector(x) - x0 / h, , nrow=nrow(x), ncol=ncol(x))), c(2) epakern, dim)) / h^dim It would be more _readable_ if I defined the object inside the apply(), stick it there and rm() after, but my feeling is that creating

Hello, I am a undergraduate student at DA-IICT,India pursuing Btech in Information and Communication Technology.Major field of my Research is Information Retrieval and Natural Language processing. xapain being an powerful Information retrieval library have attracted me towards implementing stuff learned in class for this project.I have worked on entity search on RDF data,SMS based FAQ

Hello Group, I'd like to hear your thoughts for the following design. To implement a Voice Gateway solution with atleast 2 PRI (60 channel) capacity, is it better to implement - 1 Grunty Server with a BiPRI card (TE205P, 210P) / Quad PRI (TE405P, TE410P) or - 2 Normal Servers (Dell 420/430 with 2 Gig RAM and 80 Gig SATA) with Single PRI (TE110P) or BiPRI (TE205P, 210P) and Load balance

On 12/09/2015 11:45 AM, m.roth at 5-cent.us wrote: > I'm sure it's *far* too much work for, say, the fedora development team to > put out once a quarter a notice to upstream, and maybe CentOS, Scientific > Linux, and whatever other main user groups to inform them of major > changes, and see the feedback.... Someone just needs to spend the time to do it. So who is that someone?

I'd echo a lot of what has been said about this by the folk who have been making R work so well. One of the main difficulties is that the environment of computations affects relative performance. e.g., what settings did a distro package builder choose. I note that my 3 GHz Dual Core machine running Ubuntu 8.04 gets octave 3.0.0 octave:6> tic; a = a + 1; toc Elapsed time is 0.120027

I have two matrices (see example below) and I want the differences for the matching row numbers, but the row numbers are not identical in the two matrices. There are probably many ways to do this. Anyone know of any easy way to do this? I could loop over them, but you know what they say about for loops... Thanks, Roger > out.r[1:5, 1:3] 1 2 3 1100 -0.0992 -0.0802 -0.0653 1200 -0.1242

On 10/27/2013 05:57 PM ken wrote: > One laptop I'm looking at buying offers these CPU options: > > * 4 Generation Intel? Core? i7-4700MQ Processor ( 2.4 GHz 6MB L3 Cache - > 4 Cores plus Hyperthreading ) > > * 4th Generation Intel? Core? i7-4800MQ Processor ( 2.7 GHz 6MB L3 Cache > - 4 Cores plus Hyperthreading ) > > * 4th Generation Intel? Core? i7-4900MQ Processor

> On Sep 9, 2016, at 3:27 PM, Steve Canon via llvm-dev <llvm-dev at lists.llvm.org> wrote: > > > > Sent from my iPhone > > On Sep 9, 2016, at 6:21 PM, Abe Skolnik <a.skolnik at samsung.com <mailto:a.skolnik at samsung.com>> wrote: > >> On 09/09/2016 04:31 PM, Stephen Canon wrote: >> >>> Gating this on -Owhatever is dangerous, .

I have a very simple kernel that is generating very very bad code. The basic kernel pseudo-code is as follows: forloop(1 to n) { forloop(0 to j) { A } B } C It is generating very ugly and inefficient code for a vector system similar to the following pseudo-code: if (n > 1) { if (j) { forloop(1 to n) { forloop(0 to j) {

On Oct 6, 2009, at 4:28 PM, Villmow, Micah wrote: > I have a very simple kernel that is generating very very bad code. > > The basic kernel pseudo-code is as follows: > forloop(1 to n) { > forloop(0 to j) { > A > } > B > } > C > > It is generating very ugly and inefficient code for a vector system > similar to the following pseudo-code: > if (n >

I'm trying to get a data.restore function to work on functions. One thing I can't figure out: how do you construct a function from it's component parts? For example, I can construct a for loop as forloop <- as.call(list(as.name('for'),as.name('i'),1,as.call(list(as.name('junk'))))) which results in for (i in 1) junk() But how do I put that in a

On 20/04/2020 17:49, Andrea Cucciarre' via samba wrote: > Does the "password server" setting in the smb.conf achieve it? No, you shouldn't use this, you should allow Samba to choose the best DC to use. > > On 4/20/2020 6:40 PM, Andrea Cucciarre' wrote: >> Hello, >> >> Is there a way to provide a list of DC that Samba should try to join? >> I

I have one data frame with a column of dates and I want to fill another data frame with one column of dates, one of years, one of months, one of a unique combination of year and month, and one of days, but R seems to have some problems with this. My initial data frame looks like this (ignore the NAs in the other fields): > mans[1:10,] date loc snow.new prcp tmin snow.dep tmax 1

On Wed, Mar 23, 2016 at 3:52 AM, Rui Ueyama <ruiu at google.com> wrote: > On Tue, Mar 22, 2016 at 10:33 PM, David Blaikie <dblaikie at gmail.com> > wrote: > >> >> >> On Tue, Mar 22, 2016 at 1:29 PM, Rui Ueyama <ruiu at google.com> wrote: >> >>> On Tue, Mar 22, 2016 at 9:19 PM, David Blaikie <dblaikie at gmail.com> >>>

Hello R Community, I don't post to these things often so excuse me if I stumble on my forum etiquette. This is a complex problem for me, which may require two forum entries, but I will try my best to be concise. Also, I am a self taught coder, so if my code is not to convention, your constructive criticism is always welcome. I need to split up a data frame by participant (gpsarc -

On Tue, December 8, 2015 11:05, Matthew Miller wrote: > >> I have been bitten by things done in Fedora that only have any use >> on >> a laptop and that should never have been allowed into a server >> distribution. But I cannot see how I would have been aware of them >> until they manifested themselves on equipment under my care. By >> which > > ^

Hi R, Please solve my problem........... I am extracting Bloomberg data from R, in a loop. R is getting fatigued by doing this process and gives some errors. I introduced sleep function. Doing this sometimes I get the results and sometimes not. I even noticed that if I give complete rest for R (don't open R window) for 1 day and then run my code with the sleep function, then the

Message: 63 Date: Wed, 26 Jan 2005 04:28:51 +0000 (UTC) From: Gabor Grothendieck <ggrothendieck at myway.com> Subject: Re: [R] chron: parsing dates into a data frame using a forloop To: r-help at stat.math.ethz.ch Message-ID: <loom.20050126T052153-333 at post.gmane.org> Content-Type: text/plain; charset=us-ascii Benjamin M. Osborne <Benjamin.Osborne <at> uvm.edu>

On Wed, 22 Nov 2000 13:08:26 +0100, Kurt Hornik wrote: . >>>>> Duncan Murdoch writes: >> I'm trying to get a data.restore function to work on functions. One >> thing I can't figure out: how do you construct a function from it's >> component parts? ... >> forloop <- >>

This is causing me great consternation, and I've spent too much time floundering around on it. My data is in the form of columns in Excel, with the first column being in m/dd/yyyy hh:mm format. The spreadsheet is complicated (headers, merged cells, lines w/o data); so I've tried various ways of exporting the data into a text file for the R processing - CSV, spaced, etc. For example: