similar to: Randomly remove condition-selected rows from a matrix

Following Duncan's suggestion, I forward the below to R-devel. vQ -------- Original Message -------- Subject: Re: [R] Randomly remove condition-selected rows from a matrix Date: Fri, 02 Jan 2009 10:34:52 -0500 From: Duncan Murdoch <murdoch at stats.uwo.ca> To: Wacek Kusnierczyk <Waclaw.Marcin.Kusnierczyk at idi.ntnu.no> CC: R help <R-help at stat.math.ethz.ch>

Hello, I create this array: x <- cbind(c(1:4, rep(0,10)), c(rep(0,4), 1:2, rep(3,6), 4,5)) [,1] [,2] [1,] 1 0 [2,] 2 0 [3,] 3 0 [4,] 4 0 [5,] 0 1 [6,] 0 2 [7,] 0 3 [8,] 0 3 [9,] 0 3 [10,] 0 3 [11,] 0 3 [12,] 0 3 [13,] 0 4 [14,] 0 5 I would like to do the following in vector syntax:

Hello, I'm running a PB G4 with Mac OS 10.4.1. I have downloaded the latest version R-2.1.0a.dmg. It appears that R does not work. It launches itself, but the window never gets ready, there is written "Loading R..." and a small progress wheel keeps turning indefinitely. Could someone help or suggest something? THANKS !! Guillaume

Hi, I'm unable to find a way to smooth data for a persp() graph. Example, suppose that I have data x,y,z like this: x <- 1:10 y <- 1:10 k <- 20 z <- outer(x, y, "*") + matrix( k*runif(100, -1, 1), 10, 10) persp(x, y, z, theta = 35, phi = 25) The graph is not very nice. Is there a way to smooth the z data so that at the end the graph would look more like something

Hello, This code builds a simple example of 2 wireframes : require(lattice) x <- c(1:10) y <- c(1:10) g <- expand.grid(x = 1:10, y = 1:10, gr = 1:2) g$z <- c(as.vector(outer(x,y,"*")), rep(50,100)) wireframe(z ~ x * y, data = g, groups = gr, scales = list(arrows = FALSE)) However, the intersection between the wireframes is not properly drawn. Is there a way to fix this

Hi list, I'm running R CMD check for a package and I would like to save the .tex file that generates later the pdf documentation. I have only seen it appearing and disappearing quickly in a tmp folder but I have not been able to save it. I could not find any option to the check command to save it. Any idea how I can save this tex file? Thanks Guillaume

given what ?identical says, i find the following odd: x = 1:10 y = 1:10 all.equal(x,y) [1] TRUE identical(x,y) [1] TRUE y[11] = 11 y = y[1:10] all.equal(x,y) [1] TRUE identical(x,y) [1] FALSE y [1] 1 2 3 4 5 6 7 8 9 10 length(y) [1] 10 looks like a bug. platform i686-pc-linux-gnu arch i686 os linux-gnu system

the following is a trivialized version of some functional code i tried to use in r: (funcs = lapply(1:5, function(i) function() i)) # a list of no-parameter functions, each with its own closure environment, # each supposed to return the corresponding index when applied to no arguments sapply(funcs, function(func) func()) # supposed to return c(1,2,3,4,5) there is absolutely nothing unusual in

m = matrix(1:4, 2) apply(m, 1, cat, '\n') # 1 2 # 3 4 # NULL why the null? vQ

Dear R Gurus: How do I find the functions which are primitives, please? Thanks, Edna Bell

Hi all I have the following regular expression problem: I want to find complete elements of a vector that end in a repeated character but where the repetition doesn't make up the whole word. That is, for the vector vec: vec<-c("aaaa", "baaa", "bbaa", "bbba", "baamm", "aa") I would like to get "baaa" "bbaa"

Dear R Gurus: I read somewhere that functions are considered vectors. Is this true, please? thanks Edna Bell

Full_Name: Wacek Kusnierczyk Version: 2.10.0 r48365 OS: Ubuntu 8.04 Linux 32bit Submission from: (NULL) (129.241.110.141) sprintf has a documented limit on strings included in the output using the format '%s'. It appears that there is a limit on the length of strings included with, e.g., the format '%d' beyond which surprising things happen (output modified for conciseness):

Full_Name: Wacek Kusnierczyk Version: 2.8.0 and 2.10.0 r48242 OS: Ubuntu 8.04 Linux 32 bit Submission from: (NULL) (129.241.110.161) In the following code: duplicated(data.frame(), incomparables=NA) # Error in if (!is.logical(incomparables) || incomparables) .NotYetUsed("incomparables != FALSE") : # missing value where TRUE/FALSE needed the raised error is clearly not the

Full_Name: Wacek Kusnierczyk Version: 2.10.0 r48269 OS: Ubuntu 8.04 Linux 32 bit Submission from: (NULL) (129.241.199.164) In the following example (and many other cases): quote(a=1) # 1 the argument matching is apparently incorrect wrt. the documentation (The R Language Definition, v 2.8.1, sec. 4.3.2, p. 23), which specifies the following algorithm for argument matching: 1. Attempt to

Hello Samba team ! I'am in a very delicate situation. After an upgrade to debian Stretch my DRS stopped working. I have three DCs (fichdc, fichds01, fichds02), all Debian Stretch, all with the same problem. Everything seems to be fine except DRS. -> File shares works -> DNS (with bind9 DLZ) works -> "kinit administrator" works -> "kinit -k FICHDC$" works ->

21.06.2017 11:45, L.P.H. van Belle via samba пишет: > I suggest before you upgrade do a very good read here. > > https://wiki.samba.org/index.php/Updating_Samba#Notable_Enhancements_and_Changes > > https://wiki.samba.org/index.php/Samba_Features_added/changed_(by_release) > And a summerize version for with all parameter changes as of upgrade from 4.2 up to 4.6 >

I was wondering why the following doesn't work: > a=c(1,2) > names(a)=c("one","two") > a one two 1 2 > > names(a[2]) [1] "two" > > names(a[2])="too" > names(a) [1] "one" "two" > a one two 1 2 I must not be understanding some basic concept here. Why doesn't the 2nd name change to

I was wondering why the following doesn't work: > a=c(1,2) > names(a)=c("one","two") > a one two 1 2 > > names(a[2]) [1] "two" > > names(a[2])="too" > names(a) [1] "one" "two" > a one two 1 2 I must not be understanding some basic concept here. Why doesn't the 2nd name change to

On Tue, 20 Jun 2017 22:31:02 +1200 Andrew Bartlett via samba <samba at lists.samba.org> wrote: > On Tue, 2017-06-20 at 11:13 +0200, L.P.H. van Belle via samba wrote: > > Now choose, of > > dedicated keytab file = /etc/krb5.keytab > > To be clear, this parameter is not used in the AD DC. > > Thanks, > > Andrew Bartlett > Shouldn't that be