similar to: diagonal lines in legends of ggplot2

Hi all, I want to plot the grouped means of some variables. The dependent variables and the grouping factor are stored in different columns. I want to draw a simple line-plot of means, in which the x-axis represents the variables and y-axis represents the means. The means of the groups should be connected by lines. So far, the only function that I could find comes closest to what I'm

Dear R-users, In a randomized placebo-controlled within-subject design, subjects recieved a psycho-active drug and placebo. Subjects filled out a questionnaire containing 15 scales on four different time points after drug administration. In order to detect drug effects on each time point, I compared scale values between placebo and drug for all time conditions and scales, which sums up to

Hi I have a dataframe in which some subjects appear in more than one row. I want to extract the subject-rows which have the minimum date per subject. I tried the following aggregate function. attach(dataframe.xy) aggregate(Date,list(SubjectID),min) Unfortunately, the format of the Date-column changes to numeric, when I'm applying this function. How can I preserve the date format? Thanks

Sorry, for asking the same question again, but I got no reactions the last time. Maybe it was just overseen by the experts. I'm using the xtable function with Sweave and Lyx and I would like to know how to get automatic line breaks for long strings in a column of the table. I've learned from the Lyx wiki that the Latex command \linebreak produces table cells with multiple lines. I tried to

Hello I would like to pass a model formula as an argument to the with.mids function from the mice package. The with.mids functon fits models to multiply imputed data sets. Here's a simple example library(mice) #Create multiple imputations on the nhanes data contained in the mice package. imp <- mice(nahnes) #Fitting a linear model with each imputed data set the regular way works

Hi, I have the follow ggplot2 code I am running: ggplot(data=bb.res.math,aes(x=factor(id.bb),y=bb.math.comb,fill=BB)) + geom_bar() + facet_grid(BB~.) + scale_fill_brewer(pal="Set1") + ylab("Average Student Residual (Math)") + xlab("Student ID") The number of unique id.bb is 2207 and so my X-axis has a couple of thousands, indistinguishable tick marks that correspond

I'm trying to reproduce the 3rd graph on the page of this site: http://learnr.wordpress.com/2009/03/17/ggplot2-barplots/ . However, the data below produces a ggplot with the stacks sorted in alphabetical order from the bottom up. I'd like the stacks to be in the order "Europe", "Asia", "Americas, "Africa", "Oceania". Is there an easy way to

Dear R-users Is it possible to adjust two y-axis in a ggplot differently? - First y axis (0-60) - Second y axis (0-2500) ### Figure 1 ggplot(Fig1,aes(BFF,Wert,fill=Studien_Flaeche))+ geom_bar(stat="identity",position='dodge')+ scale_y_continuous(name="First Axis", sec.axis=sec_axis(trans=~.*50, name="Second Axis"))+

Hi Sibylle, For that kind of data with two different scales, I generally use two graphs that I name gg1 and gg2 and join them using gridExtra::grid.arrange(gg1, gg2). This way, the red part of your graph is easier to interpret. Have a nice day, Charles-?douard -----Message d'origine----- De?: R-help <r-help-bounces at r-project.org> De la part de sibylle.stoeckli at gmx.ch Envoy??:

Hola, Estoy haciendo un gráfico con: ############################################################################# ## GRAFICO BARRAS : VALORES AL DEBE MENSUALIZADO ggplot(Diario_S2, aes(x=mes_AAA, by = MES , y=ARS_DEB))+ # ASIGNAR VARIABLES geom_bar(stat="identity", width=0.7, # ANCHO BARRAS colour="grey", fill="darkgreen", #

Hello, R friends,   I'm trying to change colors of my horizontal bars so that they show a sequence. I chose the ColorBrewer palette "Blues". However the resulting plot doesn't show any changes to the default. I tried several places of "+ scale_colour_brewer(type="seq", pal = "Blues")" with no effect. This is my code:   p <- ggplot(data, aes(x =

Hi, I don't know the axis mecanism well enough in ggplot but using the original barplot function you can add an axis on the right using the axis function. Here is an example: test <- as.table(matrix(c(2,10,3,11), 2,2)) barplot(test, beside = TRUE, col = scales::brewer_pal(palette = 1)(2)) axis(4, at = c(0, 5, 10), labels = c(0,50,100)) -----Message d'origine----- De?:

Hi All, I have trying to do what I thought was a reasonably simple graph but I think I'm now going in circles with the colour. Attached is a picture of where I'm up to. The line creating this is: qplot(ageincgraph$age, ageincgraph$rate, position="dodge", stat="identity", geom="bar" ) + aes( colour=ageincgraph$era) +

Dear Charles-Edouard Thanks a lot. Yes indeed barplot sounds excellent. Unfortunately, the scale of the smaller axis is fixed, even If I am able to draw to axes. The idea is to expand the scale to the scale to the second axis for comparison. F1 <- as.table(matrix(c(50,11,6,17,16,3,1,2237,611,403,240,280,0,0), 2,7)) barplot(F1, beside = TRUE, col = c("blue", "grey"))

Aloha all, I love using ggplot. It took a while to get used to the grammar of graphics, but it is starting to get easy now that I am thinking in a more structured way. A question. I'm making a wind rose that I'd like to be oriented with due north straight up. I've discovered that the orientation is sensitive to how north is represented. When north is represented as 0,

Hi, Just find a scaling factor that would make the two sets of data comparable. Here I divided the second row by 5 and did the same for the second axis. Charles-?douard F1 <- as.table(matrix(c(50,11,6,17,16,3,1,2237,611,403,240,280,0,0), 2,7)) barplot(F1, beside = TRUE, col = c("blue", "grey")) axis(2, at=c(0,10,20,30,40,50,60, labels=c(0,10,20,30,40,50,60))) axis(4, at =

Hello, I was fiddling with TableGen (for a use that has nothing to do with a compiler but it's doesn't matter) and TableGen triggers an assertion failure on this code (I reduced the case to the minimum, it's a parsing bug): class Bli<string _t> { string t = _t; } class Bla<list<Bli> _bli> : Bli<!car(_bli).t> { } #0 0x00007ffff6ebda75 in *__GI_raise

On Sep 1, 2010, at 4:35 AM, Amaury Pouly wrote: > Hello, > I was fiddling with TableGen (for a use that has nothing to do with a compiler but it's doesn't matter) and TableGen triggers an assertion failure on this code (I reduced the case to the minimum, it's a parsing bug): David, can you take a look? This is related to your lisp interpreter :) -Chris > > class

Hello, I try this : in application_helper.rb ----------------------- def lnk bla return link_to bla, { :controller => bli , :action => "blo" , :id => "blu" } end in file.rhtml ----------- <%= lnk "yo!" %> This return an error. There is a way to do this or something similar, or this is completly impossible ? Thanks

How do I create a legend with ggplot? I think should be getting the FuelTypeNum in the legend. Plot: http://r.789695.n4.nabble.com/file/n4632471/Rplot.jpeg My code is: ggplot(data=tempTable, aes(x=Bands8, y=SubPercent, fill=FuelTypeNum)) + geom_bar(position="stack", stat="identity") + scale_colour_hue('my legend', breaks = levels(tempTable$FuelTypeNum),