similar to: X11 is not availble

Dear list, I have been working on a report with around 60 images in it, and everything has been fine, until now. I find that the image output that is produced by odfWeave produces images that are NOT readable by OpenOffice or NeoOffice. I get empty boxes with Read-Error written in them. While generating the file using odfWeave, I can see them being generated on the screen, and they all seem fine.

Dear list, Sorry for asking this very silly question on the list, but I seem to have made my life complicated by going into string manipulation in vectors. What I need is to get the last part of a sting (the two last tokens, separated by a space), and of course, this should be done for all strings in a vector, creating a new vector of exual size. So, a <- c(" %L H*L L*H H%",

Dear list, I need to convert this data.frame > names(codesM) [1] "key" "AMR.pa1.M" "AMR.pa2.M" "AMR.pa3.M" "AMR.pa4.M" [6] "AMR.pa5.M" "AMR.pa6.M" "AMR.pa7.M" "AMR.pa8.M" "AMR.pa9.M" [11] "AMR.pa10.M" "AMR.ta1.M" "AMR.ta2.M" "AMR.ta3.M"

Dear list, I'm working on a panel function where I would like to be able to visualise data grouped by the category of the data, and then also changes in summary descriptives from one condition to another in the same scatter plot. Like the figure attached, but with one polygon for each subset of the data set given by a second variable (with colours still coming from the variable specified in

Dear list, I've been using plotmeans {gplots} a lot before, and found the "connect" argument to be quite useful. I've moved to ggplot for several reasons, but would still like to connect lines conditionally, somehow. Is it possible to do? Small example: df <- data.frame(cat=LETTERS[1:4],num=rnorm(4)) ggplot(df, aes(x=cat, y=num)) + geom_point() +

Dear list, Sorry for asking this question, but has something changed in the syntax for bwplot in Lattice? In an old publication, I used > bwplot( VOTMS ~gender |type * group, data=merge(vot,words,by="ord"), nint=30, horizontal=F, layout=c(3,3), box.ratio=0.8) which produced a lovelly 3x3 lattice plot with one

Dear list, The output of my embedded code sections come out in the style "ttBlue" wich is Times New Roman and Blue when I open document. I would like to change this to a fixed witdth font, smaller and less blue by using style definitions in the document, but it really does not affect the output. I tried including getStyleDefs() -> styl styl$ttBlue$fontname <- "Courier"

Dear list, I have been struggling to find how I would go about changing the bakground colors of groups in a lattice barchart in a way so that the auto.key generated also does the right thing and pick it up for the key. I have used the "col" argument (which I guess is sent to par()) in a way so that the colors are like I would want them, but now I guess I need to know which part part of

Dear list, I am trying to construct a report function that would go through all the object in the current environment and print them in HTML form. What I have got is: dataReport <- function(){ #First tables tabs <- ls(sys.frame(), pattern=".*table") for(currT in tabs){ cat("\n\n") print(currT) if(length(dim(get(currT))) > 2){ #We have to use ftable

Dear list, I am leaving my old position and now need to convert my R data frames into a format that can be used by an SPSS user replacing me, without running into conversion problems. The data set consists of strings in UTF8 encoding and values in double precision floats. The data set is not terribly large, but I had bit problems getting it into R due to the large number of unfortunate characters

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Dear list, This seems like a very simple problem, but I am failing to loose a dimension (I think). I have list, like this: ... [2072] "!H*L" "L%" "%L" "H*L" "L%" "%L" "H*L" "H*L" "L%" "%L" "H*L" "!H*L" "L%" "%L" "%L"

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Dear list, I am sorry for asking you this, but I am trying to do again what I thought I have done before, although this time it does not work. So, given the data set: > testdf <- data.frame(grfak=sample(c("One","Two"),size=100,replace=TRUE), panfak= sample(c("Yes","No"),size=100,replace=TRUE), xfak=

Hi all, I've got at really basic Q for you all: How do I produce a 3D plot in R? Like the one in the screenshot on the R-project wab-page. What is the command? /Fredrik -- ----------------------------------------------------------------- Fredrik Karlsson, Research Student Department of Philosophy and Linguistics Ume? University S-901 87 UME? SWEDEN Tel: +46 90 786 56 84 Web:

Hi all This seems like a very easy question, but I have not found a simple answer to it: If you have a dataframe, how to you plot two of then in different colors depending on a third variable? All help appreciated! /Fredrik -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send

Dear list, I have a two character vector with two different values in them (two each, that is). Naturally, when I use these vectors as grouping factors in a lattice plot, I get four panels. Now, one of the possible four combinations will never have data, so one panel will always be empty. So now my question is: can I force R / Lattice not to print it, and give me only the 3 filled panels? I have

Dear list, I would like to create histograms for up to three groups, with distincive colour/pattern, in a trellis panel. However, I have not been able to find a way to do this. histogram does not seem to have a group argument. Please help. /Fredrik

Hi all, I'm a potential new user of R and have to know this before I start using it: SPSS does not let you do a Post Hoc analysis on repeated measures data. This is a problem for me, since that is what I will have to do. Will R let me do this? /Fredrik -- ----------------------------------------------------------------- Fredrik Karlsson, Research Student Department of Philosophy and