similar to: Sorting a date vector

Hi, Suppose I have following dataset : mat <- matrix(rnorm(100), 50) Now I want to put 2nd column in the place of 1st and 1st column in the place of 2nd. Is there any "quick" way to do that? Thanks and regards, -- View this message in context: http://www.nabble.com/Altering-columns-tp24099597p24099597.html Sent from the R help mailing list archive at Nabble.com.

Dear R-help I am using R version 2.6.2. I am trying to subtract specific values from a larger data frame. I feel this should be straightforward, but I am struggling. I have a dataframe "Bk" as follows: DateTime cumPrecip 01/01/2008 00:00 348 01/01/2008 01:00 348 01/01/2008 02:00 348 01/01/2008 03:00 347 01/01/2008 04:00 348 01/01/2008 05:00 348 01/01/2008 06:00 349

Is there any function in R to clear values from all variables stored in current and previous sessions? R site search do not give the desired result at all, all results are about to clear screen only not variables. Thanks, -- View this message in context: http://www.nabble.com/How-to-Clear-all-variables-stored-in-current-and-previous-sessions-tp20604724p20604724.html Sent from the R help mailing

Please consider the following : > expand.grid(rep(list(c(1:3)), 3)) Var1 Var2 Var3 1 1 1 1 2 2 1 1 3 3 1 1 4 1 2 1 5 2 2 1 6 3 2 1 7 1 3 1 8 2 3 1 9 3 3 1 10 1 1 2 11 2 1 2 12 3 1 2 13 1 2 2 14 2 2 2 15 3 2 2 16 1 3 2 17 2 3 2 18

Hi, suppose I have following codes : library(zoo); library(ggplot2) dat <- matrix(rnorm(500*2), 500); dat <- zooreg(dat, start = as.Date("01/01/01", "%m/%d/%y"), frequency=1); plot(dat) head(dat); month.no <- format(index(dat), "%m"); dat1 <- cbind(coredata(dat), as.numeric(month.no)) x <- dat1[,1]; y <- dat1[,2]; z <- dat1[,3] Now I draw a

Hello everyone, I would like to create a "dynamic" array to keep storing number in it for (i in c(2:length(final))){ myarray <-final[i]-final[i-1] myarray2<-2*final[i] } At the end I would like to use myarray as the x values of an array and the myarray2 as the yvalues of the same array. I tried cbind but it didnot work. Could you please help me with that? Best

Running R 2.13.1 on Windows XP. I would like to get week of the year (1-52) for each date. library(chron) dts <- dates(c("02/27/92", "02/27/92", "01/14/92","02/28/92", "02/01/92")) dts dts.chron <- as.chron(dts) dts.chron class(dts.chron) # all of these component extractions work: months(dts.chron) weekdays(dts.chron) years(dts.chron)

Dear List, I am unsure if this is specifically a R question or a stats question? I thought i would ask here and if i get no replies it will answer that! I am trying to calculate Gini coefficients in R, based on a slight modification of the typical equation that i have seen in a paper. -------------- next part -------------- A non-text attachment was scrubbed... Name: PastedGraphic-2.pdf Type:

Hello, I'm trying to get percentiles (PERCENTRANK for excel users) by factor in the following data.frame: myExample <- data.frame(Ret=seq(-2, 2.5, by=0.5),PE=seq(10,19),Sectors=rep(c("Financial","Industrial"),5)) myExample <- na.omit(myExample) Thanks to Patrick I I managed to put together the following lines which does it for the "Ret" column: myecdf

Dear readers of the list, I have a problem a comparison of two data from a vector. The comparison yields FALSE but should be TRUE. I have checked for mode(), length() and attributes(). See the following code (R2.10.0): ----------------------------------------------- # data vector of 66 double data X =

Hi All, I want to take a matrix (or data frame) and winsorize each variable. So I can, for example, correlate the winsorized variables. The code below will winsorize a single vector, but when applied to several vectors, each ends up sorted independently in ascending order so that a given observation is no longer on the same row for each vector. So I need to winsorize the variable but

I am pretty much a newbie at CentOS, and Linux on client side, I would like to help out occasionally by helping the web development crew in their endeavors and by sorting out some stuff. such as repairing broken links, or just scanning for content and maybe even doing a little bit of consulting. Eric R. Clark Dynamic Technology Systems US Phone: (817) 704-4109 US Cell: (817) 706-8856 Email is

I was trying to dw data from Economagic [http://www.economagic.com/em-cgi/data.exe/libor/day-ussnon], using following code : library(fimport) dat2 = economagicSeries("libor/day-ussnon", frequency = "daily") Here I see that data is not complete, downloaded data starts from "2007-12-31 ", whereas actual data is available from 2001. secondly, how I convert that data

Hi, guys I don't understand why I can apply as.Date to a single item in the list: > as.Date(alldays[4]) [1] "29-03-20" but when I try to lapply as.Date to all the items, i got a sequence of neg numbers: > sapply(alldays[1:4], FUN=as.Date) 03-04-2012 02-04-2012 30-03-2012 29-03-2012 -718323 -718688 -708492 -708857 does anyone know what's wrong here? i am

Hi all, I'm working on a loop function for a large dataset which contains 1000 different groups. I would like to reconstruct the order of events within each group by using a loop function in R. (Currently the order of events are based on the ascending order of prev_event within the group) A demo data frame: event prev_event group 845 0 5360 926 153

Undoubtedly a simple question: I've looked at order() and sort() in the help pages for R1.7.1. It doesn't appear that these functions are immediately suited to doing the same thing as PROC SORT DATA = BLAH; BY X Y Z; RUN; in SAS. I have also checked Frank Harrell's Hmisc library. Could someone point me in the right direction so I can sort by the levels of Z within the levels of

Dear friends, I want to sort a dataset according to one or two variables in the dataset, i thought sort could do it , but failed. e.g. x <- c(2, 9, 18, 3, 2) y<-c(2,5.6,5,9,8) z<-c(21,5,5,19,7) a<-cbind(x,y,z) a x y z [1,] 2 2.0 21 [2,] 9 5.6 5 [3,] 18 5.0 5 [4,] 3 9.0 19 [5,] 2 8.0 7 I want to sort dataset a according to ascending x and descending y, How to

(Forwarded off-list message) -------- Original Message -------- Subject: Re: [Xapian-discuss] what is the fastest way to fetch results which are sorted by timestamp ? Date: Thu, 11 Aug 2011 01:06:36 +0800 From: ??? <panjunyong at gmail.com> To: Tim Brody <tdb2 at ecs.soton.ac.uk> On Wed, Aug 10, 2011 at 6:39 PM, Tim Brody <tdb2 at ecs.soton.ac.uk> wrote: > Hi, > > In

when i tried to crate an upload file application in rails i am getting error like this Template is missing Missing template app\views\upload\uploadfile.html.erb in view path app/views this is ma model class DataFile < ActiveRecord::Base def self.save(upload) name = upload[''datafile''].original_filename directory = "public/data" # create the

Hi, 1) I ran a script say test.R. It ran and terminated with an error. However, I am not sure where the error occur. > source("test.R") Loading required package: tools Welcome to Bioconductor Vignettes contain introductory material. To view, type 'openVignette()'. To cite Bioconductor, see 'citation("Biobase")' and for packages