similar to: converting a data-frame by a defined rule

I'm running into a problem I can't seem to find a solution for. I'm attempting to add sequences into an existing data set based on subsets of the data. I've done this using a for loop with a small subset of data, but attempting the same process using real data (200k rows) is taking way too long. Here is some sample data and my ultimate goal >

Hi, I have a problem sorting and selecting entries within a data-frame and I don't know if it is possible to solve it with R ... (probably yes, but I have no idea how). Following Data; row1 row2 a 12 pos NA a 3 neg NA a 5 neg NA a 11 pos NA I want to extract the values in row 2 in the lines with an "a" in row1. But I want to have two vectors: vector x with all

Hello List, I am not sure that I have the correct terminology here (restricted bootstrap) which may be hampering my archive searches. I have quite a large spatially autocorrelated data set. I have xy coordinates and the corresponding pairwise distance matrix (metres) for each row. I would like to randomly sample some number of rows but restricting samples such that the distance between them is

Hi, May be this helps: dat1<- as.data.frame(table1) ?dat2<- as.data.frame(table2) names(dat2)<-c("V3","V4") library(plyr) res<-join(dat1,dat2,type="full") ?res[is.na(res)]<- 0 ?res #? V1 V2 V3 V4 #1? 1? 1? 0? 0 #2? 1? 2? 0? 0 #3? 0? 0? 0? 1 #4? 0? 0? 0? 4 ?combinedtable<-as.matrix(res) ?colnames(combinedtable)<- NULL ?combinedtable #???? [,1] [,2]

I guess this has a simple solution: I have matrix 'mat1' which has row and column names, e.g.: A B C row1 0 0 0 row2 0 0 0 .... rown 0 0 0 I have a another matrix 'mat2', essentially a subset of 'mat1' where the rownames are all in 'mat1' e.g.: B row3 5 row8 6 row54 7 I want to insert the values of matrix mat2 for column B (in reality it could be some or

Hi Friends, I am new to R. On R utility class pages, creating "named.list" is described with this command : new("named.list",a=1,b=2) For large matrix having two columns, such as : "row1" 2334 "row2" 347 "row3" 379 ... I want to create a named.list like : $row1 [1] 2334 $row2 [1] 347 ... Can anyone explain how "named.list"

Dear R-help team, I am getting addicted to using R but keep on getting many challenges on the way especially on data management (data cleaning). I have been wanting to drop all the rows if there values are `NA' or have specific values like 1 or 2 or 3. mdat <- matrix(1:21, nrow = 7, ncol=3, byrow=TRUE, dimnames = list(c("row1",

Hi, I received an internal test case from a game team (it wasn't about this in particular), and I was wondering if there was maybe an opportunity to canonicalize a particular code pattern: %inputi = bitcast <4 x float> %input to <4 x i32> %row0i = and <4 x i32> %inputi, <i32 -1, i32 0, i32 0, i32 0> %row0 = bitcast <4 x i32> %row0i to <4 x float>

Hi R Users, I'm using following data/code (data is attached also) to produce a stacked barplot. # Sample Data: Names Col1 Col2 Col3 Row1 -20 40 -10 Row2 30 -20 40 Row3 30 10 -20 Row4 20 20 -10 # R Code: dta<-read.table("data.txt", header=TRUE, row.names="Names") barchart(data.matrix(dta), horizontal=FALSE, stack=TRUE, par.settings = simpleTheme(col =

Hi R Users, I'm trying to plot a stacked barplot. Here is data: Sample Col1 Col2 Col3 Row1 -2 4 -1 Row2 3 -2 4 Row3 3 5 -2 Row4 4 1 -1 I'm using following R code: library(lattice) dta<-read.table("data.txt", header=TRUE, row.names="Sample") barchart(data.matrix(dta), horizontal=FALSE, stack=TRUE, col=2:4,

Hi R Users, I'm using following data/code (data is also attached) to produce a stacked barplot. *I need help with changing legend boxes, currently I'm using "rectangles=TRUE". Is it possible to get small squares instead -- may be with a small gap between colored squares.* Currently there is no gap between the colored rectangles. # Sample Data: Names Col1 Col2 Col3 Row1 -20 40

Hi, i have that table Thesis Day A B C 1 0 83.43 90.15 22.97 1 0 85.50 94.97 16.62 1 0 83.36 95.38 20.70 1 0 84.47 92.16 23.58 1 0 83.98 95.33 19.39 1 0 82.86 93.78 24.55 1 0 83.39 92.67 19.56 1 0 85.17 95.24 17.95 1 0 81.62 93.32 28.49 1 0 82.99 92.85 19.73 1 0 81.11 95.67 27.20 1 0 83.39 94.69 16.51 1 0 79.56 89.87 30.39 1 0 80.54 93.32 21.76 1 0 82.11 92.58 22.17 1 14 85.65 94.00 19.19 1 14

Liu Xin <navy.xliu at gmail.com> writes: > I think we are solving a same problem. I am working on shader language > too. I am not satisfied with current binaries because vector operations > are kept in llvm opt. > > glsl shader language has an operation called "swizzle". It can select > sub-components of a vector. If a shader only takes components "xy"

Hi guys, I have a matrix with values varying from approximately -0.7 to 0.33 that I want to create a heatmap/levelplot with. When I execute the levelplot function for my matrix, I end up getting colors that are adjusted to the max and min rather than around 0. In other words, ideally I would like to have a color ramp that goes from red (negative number), to white (0), to blue (positive);

All, I frequently make spreadsheets in Excel in which I rank values in columns by stop-light colors (red is bad, yellow is OK, green is good). Image and heatmap expect a matrix in which all the data are in the same scale, but I frequently have different scales in different columns. ie. Column one runs from 1-10 while column 2 runs from 1-100. I thus need to define a separate color ramp for each

I HAVE BEEN ASKED TO BE REMOVED FROM THIS LIST OVER 20 TIMES, PLEASE CAN I BE REMOVED!!!!!!!!!!!!! --- On Thu, 3/12/09, Peng Cai <pengcaimaillist@gmail.com> wrote: From: Peng Cai <pengcaimaillist@gmail.com> Subject: Re: [R] Help: barchart() {Lattice} To: "Felix Andrews" <felix@nfrac.org> Cc: r-help@r-project.org Received: Thursday, 3 December, 2009, 10:17 AM Got it

thanks for the great help! But I have one additional question (hope I can work alone then); I want to replace the values of a vector, like this: x <- c(1,2,2,3,3,4,4,4,5,1) x[x==1] <- c(12) x[x==2] <- c(13) x[x==3] <- c(17) x[x==4] <- c(20) x[x==5] <- c(22) is there a way to do that just in one or two code lines? I tried x[x == c(1:5)] <- c(12,13,17,20,22) but that

Hi to all is there any construct to sum data=data.frame(row1=c(1,1,3,1,2,3,2,2,1,3,4,5,2,3,2,1) , row2=c(2,2,1,1,1,2,1,2,1,1,1,1,2,2,2,1) ) Means I would like to get all y of row1 if in row2 of the data.frame is an x f.e row1=3 and row2=2 so I would like to get 6 And is there another construct to get the count of pairs where row1=3 and row2=2 means the result should be

Hi R-experts, I try to find a way to transfer a matrix to a data.frame that is used as input of aov. can you give me advice for that? >mdat <- matrix(c(1,2,3, 11,12,13), nrow = 2, ncol=3, byrow=TRUE, dimnames = list(c("row1", "row2"), c("Col1", "Col2", "Col3"))) >mdat      Col1 Col2 Col3 row1    1    2    3 row2   11   12   13 ===>

Hi, I have this variable; x <- c("test_01.log") and I want to extract the number (01) out of the variable. So that I get; > x [1] 1 I tried strsplit, but I don't know how to refer to the result. Can someone help me with that? [[alternative HTML version deleted]]