similar to: loop with dates

Hello, I have been trying to download a pdf file but I only receive a blank sheets. I used the option internet2 in windows: Rgui.exe --internet2 but I recieved the same result. I use the next command: ulr2 <- "http://cran.r-project.org/doc/manuals/R-intro.pdf" download.file(url = ulr2, destfile = "D:\\users2\\r-intro.pdf",cacheOK = FALSE) Any ideas how I can resolve

I'm an R noob and have a (maybe) stupid question... I have a table where I have the weekdays and a number for each weekday of entries: Thats what the table looks like... Now I want to have an pie3D plot of this, but obviously the order of the weekdays are not as one would expect... Friday Monday Saturday Sunday Thursday Tuesday Wednesday 119 173 80

Dear R-users, How do I obtain a sequence of dates consisting of only weekdays without the weekends in R? In S, I can do the following: timeSeq(from="12/17/2007", to="8/25/2008", by="weekdays") I tried using looking at timeSequence (fSeries package) and seq.Date (base package) but I do not know if I can specify "weekdays" rather than "day".

I need to create a vector of dates, weekdays only for a function I am working on. Thanks to the chron library, I have managed to accomplish this, but is there is a better / easier way. This is what I have thus far. range.dates <- seq.dates('02/02/2009', '03/13/2009', by = 'days') range.days <- weekdays(range.dates) weekends <-

Hi, all Here I created a data frame like mydates<- seq(as.Date("2010-05-29"), length = 43, by = "day") myvalues<-runif(43,0,1) myframe<-data.frame(dates=mydates, day=weekdays(dates), value=myvalues) dates day value 1 2010-05-29 Saturday 0.14576143 2 2010-05-30 Sunday 0.37669604 3 2010-05-31 Monday 0.74813943 4 2010-06-01 Tuesday

Hello, I have some unbalanced panel data that is measured on weekdays only (i.e., excluding Saturday and Sunday). I would like to get the number of days between dates such that the number of days between a Friday and a Monday is 1 (and not 3). Here is some code to illustrate my problem: library('Hmisc'); DATE <-

Hello All: I am trying to generate a sequence of dates using library(chron). Using the following code, I got most of what I want, dts <- seq.dates("01/02/1998", "01/10/2001", by="day") dts <- dts[!is.weekend(dts)] a sequence of weekdays only (no weekend dates), with first observation appearing as 01/02/98 and the last 01/10/01. But I would

I just started playing with rails this week and am working on porting our existing website to rails in our navigation we have a list that has the days of the week that link to the articles for those days. this seems to be working when I had it in the template it would give me the array I was looking for so I decided to move it to the helper so that I could use it on all my templates.

Hi All, I am iterating through dated materials, with variable start and end dates, and would like to skip procedures everytime I encounter a weekend or holiday. To do this, I thought the easiest way would be to create a TRUE/FALSE vector corresponding to each day where it is TRUE if a workday, and FALSE if a weekend or holiday. So far I have been able to do this for weekdays: startDate <-

Hi, I'm trying to aggregate date values using the aggregate function. For example: aggregate(data,by=list(weekdays(LM),months(LM)),FUN=length) I would also like to aggregate by year but there seems to be no years() function. Should there be one? Is there any alternative choice? Also, a hours() function would be great. Any tip on this? Thanks in advance! S?rgio Nunes

Fellow R users, I am stumped on what would seem to be something fairly simple. I have a dataframe that has a variable named 'WEEK' that takes the numbers 1:26 (26 week time-period) with each number repeated five times consecutively (once for each weekday, Monday through Friday). Ex. 111112222233333.....2626262626. I would like to randomly extract two weekdays per five day week for

Dear all, can anyone please tell me how to generate a sequence of days continuously, however without considering weekends i.e. Saturday and Sunday? I am aware of following code: > seq(as.Date("2010-01-01"), as.Date("2010-02-01"), by="1 day")  [1] "2010-01-01" "2010-01-02" "2010-01-03" "2010-01-04" "2010-01-05"

Hi there, I am having problem of matching string. what i want is when i type a date such as 2010-11-30, the function will return the day (monday, tuesday, wednesday, thursday, friday or staturday). then i want another function will return true if the return of the day is monday, return false if the return of the day is not monday. I already find the weekdays(as.Date('2010-11-30')) function

Hi Folks! I'm struggling with dates - but enough about my personal life..... I have two daily time series files. In one (x) the date format is Y/m/d and the other (y) is d/m/y. I used read.zoo on both and they read into R with no problem. Then I use: weekdays(as.Date(x$DATE)) and get what I expect - all the days of the week in my data set. When I use:

Hello, I'm trying to write a function that returns the number of weekdays between a vector of start dates and a vector of end dates. Subtracting the 2 times the number of whole weeks is the easy part and works if the number of days is a multiple of 7. However, the number of weekend days in the tail is a little harder. It depends on both the start date of the tail and the number of days in

Hi All, I have a doubt regarding join tables I''m having 2 models 1)Fac 2)Cont and both models have " has and belong to many" relationships so there are 3 tables 1)facs 2)conts 3)conts_facs then i''m fetching the data in controller as @conts=Cont.find(:all]) @cfacs=Fac.all(:joins=>:conts, :select=>"facs.name") but i dont know how to get the

Hi, I am trying to plot an interaction.plot with different color for each level of a factor. It has an erratic behavior. For example, it works for the first interaction.plot below, with the example from the ALDA book, but not with the other plots, from the NPK dataset: # from http://www.ats.ucla.edu/stat/r/examples/alda/ch2.htm tolerance <-

Hi, I tried to read xlsx files by "XLConnect" packages, but the dates are one day earlier than it is supposed to be. I moved from California to Taiwan (Eastern Asia), and it worked well in California, but not in Taiwan. Even if I adjust my Mac time to California time zone, it gives the wrong dates. I don't know which part of the setting (in RStudio or in my Mac?) I should adjust.

I found myself wanting to average a vector [vec] within each level of a factor [Fac], returning a vector of the same length as vec. After a while I realised that lm1 <- lm(vec ~ Fac) fitted(lm1) did what I want. But there must be another way to do this, and it would be good to be able to apply other functions than mean() in this way. Cheers, Murray -- Dr Murray Jorgensen

Hi, I am analyzing a data set with greater than 1000 independent cases (collected in an unrestricted manner), where each case has 3 variables associated with it: one, a factor variable with 0/1 levels (called XX), another factor variable with 8 levels (X) and a third response variable with two levels (Y: 0/1). I am trying to see if X1 has an effect on the relationship between X2 and the