similar to: Replacing tabs with appropriate number of spaces

Hi all, I have problems in a dataframe variables types. Look: from a loop function: for(...){ ... dados.fin <- rbind(dados.fin, c(L=j, A=j^2, Nsp=nsps, N=length(amosfin$SP), AmT="am",NAm=nam, AMST=amst)) dados.fin <- rbind(dados.fin, c(L=j, A=j^2,

Hi, sorry by this off. I'm still try to understand nested design. I have the follow example (fiction): I have 12 plots in 4 sizes in 3 replicates (4*3 = 12) In each plot I put 2 species (A and B) to reproduce. After a period I make samples in each board and count the number of individuals total (tot) and individuals A and B (nsp). Others individuals excepts A and B are in total of

Hey List, I did a multiple regression and my final model looks as follows: model9<-lm(calP ~ nsP + I(st^2) + distPr + I(distPr^2)) Now I tried to predict the values for calP from this model using the following function: xv<-seq(0,89,by=1) yv<-predict(model9,list(distPr=xv,st=xv,nsP=xv)) The predicted values are however strange. Now I do not know weather just the model does not fit

R 4.0.2 OS X Colleagues I have the unfortunate need to create a large number of tables (destined for a Word document). I need to color cells depending on the contents, e.g., blue if the value is < 0.5, red if the value is > 1.5. If the output went initially to Excel, that would work; outputting directly to Word would be even better. I expect that several packages can accomplish this. I

Colleagues, I am using R (2.9.2, all platforms) to search for a complicated text string using regular expressions. I would appreciate any help you can provide. The string consists of the following elements: SOMEWORDWITHNOSPACES any number of spaces and/or tabs ( any number of spaces and/or tabs integer any number of spaces and/or tabs ) Examples include: WORD ( 123 ) WORD(1 )

Colleagues R 2.10.1 on a Mac I read in textfiles using readLines, then I process those files, then I use R to execute another program. Occasionally those files contain characters other than letter / numbers / routine punctuation marks. For example, a bullet (option-8 on a Mac) triggers the problem. Although R can read and process those characters, the other program cannot so I would like to

R 4.2.2 OS X Colleagues A file that I have read includes strings like this: "EVENT ? 30 sec" When I include the string in a graphic using: mtext(STRING, ?) it appears as: "EVENT ... 30 sec" Is there a simple work-around (short of reformatting all the strings, then using plotmath)? Dennis Dennis Fisher MD P < (The "P Less Than" Company) Phone / Fax:

OS X R 4.3.1 Colleagues I often create multipage PDFs [pdf()] in which the text "Page X" appears in the margin. These PDFs are created automatically using a massive R script. One of my clients requested that I change this to: Page X of XX where XX is the total number of pages. I don't know the number of expected pages so I can't think of any clever way to do this. I

Colleagues, I have created a list in the following manner: TEST <- list(c("A1", "A2"), c("B1", "B2"), c("C1", "C2")) I now want to delete one element from the list, e.g., the third. The command TEST[[3]] yields (as expected): [1] "C1" "C2" The command TEST[[-3]] yields: Error:

Colleagues, Hopefully a simple problem: I want to delete a column with a known name from a dataframe. I could write: FRAME <- FRAME[, names(FRAME) != NAMETODELETE] or FRAME <- FRAME[, !names(FRAME) %in% c(NAME1, NAME2, ETC)] Is there some simpler means to accomplish this? Dennis Dennis Fisher MD P < (The "P Less Than" Company) Phone: 1-866-PLessThan (1-866-753-7784)

Colleagues I am learning lattice graphics (R 2.12.2; OS X). Several days ago, I inquired about adding margin text to lattice graphics. Jim Price offered a useful reply, suggesting that I add: page = function(page) grid.text('words', x = 0.5, y = 0.01) to my call to the function. The entire function that he suggested was; xyplot(1 ~ 1, par.settings = list(layout.heights =

R 2.12.2 Windows 7 Colleagues, I just took advantage of the function: readWindowsShortcut in R.utils. It accomplished my goals and I was interested in learning its inner workings. So, I typed the function at the command line (without arguments or parentheses). R returned: function (...) UseMethod("readWindowsShortcut") <environment: namespace:R.utils> providing no

R 3.4.2 OS X Colleagues I would appreciate some help with regular expressions. I have string that looks like: " ITERATION ,THETA1 ,THETA2 ,THETA3 ,THETA4 ,THETA5 ,THETA6 ,THETA7 ,SIGMA(1,1) ,SIGMA(2,1) ,SIGMA(2,2)? In the entries that

Colleagues, I have some text: TEXT <- c("a", "bb;ccc", "dddd;eeeee;ffffff") I want to retrieve the portion of each element before the first semicolon. I can split each element using strsplit: SPLIT <- strsplit(TEXT, ";") This yields: > SPLIT [[1]] [1] "a" [[2]] [1] "bb" "ccc" [[3]] [1] "dddd"

Colleagues, I want to create the following array: "A1", "A2", "A3", "B1", "B2", "B3", "C1", "C2", "C3" I recall that there is a trick using "c" or "paste" permitting me to form all combinations of c("A", "B", "C") and 1:3. But, I can't recall the

R 4.2.3 OS X Colleagues, I am printing a large number of tables using the print command. A simple example is: print(data.frame(COL1=1:5, COL2=10:6)) The result in this case is: COL1 COL2 1 1 10 2 2 9 3 3 8 4 4 7 5 5 6 I would like to print the table WITHOUT the row numbers: COL1 COL2 1 10 2 9 3 8 4 7 5 6 Is there any simple

Colleagues Assume that I have a vector containing some text strings, some of which contain a particular character. I could like to apply "toupper" to the text before the character. For example (in this case, "|" is the particular character): ORIGINAL: TEXT <- c("aaaa", "bbb|cc", "|ddd") AFTER APPLICATION OF toupper: TEXT <-

Luke Thanks ? I revised the code to: ERRORMESSAGE <- try(source(USERSCRIPTFILE, local=T), silent=T) print(ERRORMESSAGE) now returns: $value [1] 0 $visible [1] FALSE Not clear what to make of that. Dennis Dennis Fisher MD P < (The "P Less Than" Company) Phone / Fax: 1-866-PLessThan (1-866-753-7784) www.PLessThan.com > On Feb 22, 2018, at 12:45 PM, luke-tierney at

Colleagues I just installed 3.4.2 on a Mac running High Sierra. I encountered the following: R version 3.4.2 (2017-09-28) -- "Short Summer" Copyright (C) 2017 The R Foundation for Statistical Computing Platform: x86_64-apple-darwin15.6.0 (64-bit) R is free software and comes with ABSOLUTELY NO WARRANTY. You are welcome to redistribute it under certain conditions. Type

Colleagues During the transition to R3.0.0 (OS X), one of the packages that I used -- SASxport -- did not work until I used the "type=source" option in install.packages. This led to an adventure: 1. I downloaded the package source: SASxport_1.2.4.tar.gz 2. in the SASxport/R folder, I found all the functions that are part of the package. I became interested in whether I could