similar to: ggplot2 problem

You just have to change the levels of the factor ... library(ggplot2) Lab = c(letters[4:6], letters[1:3]) valuex = c(3.1,2.3,0.4,-0.4,-1.2,-4.4) df <- data.frame(Lab,valuex) # set the factor levels to the same order as observed in the data frame df$Lab <- factor(df$Lab, levels=unique(df$Lab)) px <- ggplot(df,aes(Lab,valuex,label=Lab)) + geom_text(aes(y=0)) + geom_bar(stat =

Hi, I have a question related to the newest version of ggplot2 (0.9.0). I just updated this morning and from CRAN it looks like the Mac version is the only one at 0.9.0 as of right now. http://cran.r-project.org/web/packages/ggplot2/index.html Anyway, I was in the midst of a project where I was trying to replicate "Back-to-back Bar Charts" in this blog post.

I was wondering if anyone could help me with this, simple problem. I am essentially following the example on Hadley's webpage (http://had.co.nz/ggplot2/geom_errorbar.html), but it still doesn't make any sense to me. df <- data.frame(trt = factor(c("intact", "intact", "removed", "removed")), coon = c(0.093, 0.06, 0.057, 0.09), group =

Hi all I have a large dataframe with (among others) a categorical variable of 52 levels and would like to create a barplot with the bars ordered in decreasing frequency of the levels. I belive it is referred to as a pareto plot. Consider a subset where I keep only the categorical variable in question. # Example: v1 = c("aa", "cc", "bb", "bb",

Hello! I am trying to understand how ggplot2's geom_bar treats NAs. The help file says: library(ggplot2) ?geom_bar na.rm: If FALSE, the default, missing values are removed with a warning. If TRUE, missing values are silently removed. I am trying it out: md <- data.frame(a = c(letters[1:5], letters[1:4], letters[1:3], rep(NA, 3))) str(md); levels(md$a) ggplot(data = md, mapping = aes(x =

Is it possible to set the margin in ggplot2 to a fixed size? I create many plots, and I want them to look the same. Especially I want them to have the same left margin. But P<-ggplot()+geom_bar(aes(c("short label1","short label2"),runif(2)))+coord_flip() P<-creates a plot with another margin as ggplot()+geom_bar(aes(c("very very very very long

Hi, I was trying to draw a geom_bar plot. However, by default, the bars are arranged according to the label, which I don't want. I want the bars to appear exactly as they appear in the data frame. For example in the code: Lab=c(letters[4:6],letters[1:3]) valuex = c(3.1,2.3,0.4,-0.4,-1.2,-4.4) df <- data.frame(Lab,valuex) px <- ggplot(df,aes(Lab,valuex,label=Lab)) +

To clarify: my question is not about "who could I exclude NAs from being counted" - I know how to do that. My question is: Why na.rm = T is not working for geom_bar in this case? On Thu, Jul 27, 2017 at 8:24 AM, Dimitri Liakhovitski < dimitri.liakhovitski at gmail.com> wrote: > Hello! > > I am trying to understand how ggplot2's geom_bar treats NAs. > The help file

Dear R-Help subsribers, upon running into a wonderful ggplot2 package by accident, I abruptly encountered another problem. Almost every command run with ggplot2 results in some sort of error. The one below is far the most common one. Kind people from ggplot2 mailing list couldn't manage to solve the problem, so I'm re-posting it here to try my luck. I will recommend myself for any tips

Hi James, If you want to specify the y-values, you need to use stat="identity" as below: ggplot(probability, aes(x=Fertilizer, y=prob)) + geom_bar(stat="identity", aes(fill=Treatment)) best, huzefa On Tue, Apr 12, 2016 at 1:02 PM, James Henson <jfhenson1 at gmail.com> wrote: > Dear R Community, > > Below is a problem with a simple ggplot2 graph. The code

Dear R gurus - consider this plot: library(ggplot2) dat <- sample(1:8,100,replace=TRUE) smp <- ggplot(data.frame(dat), aes(x=factor(dat),fill=factor(dat))) + geom_bar(width=1) smp + coord_polar() Q1. How do I change the font size and weight of bar labels (1,2,3...)? I've been wallowing in the 'Themes' structure and I just can't figure out the correct place to change

When I am using geom_bar I get these white slashes through the legend keys. I cannot figure out how to remove them. ggplot(diamonds, aes(clarity, fill=cut)) + geom_bar() I have tried using opts(legend.key = theme_blank()) but with no luck. Any suggestions would be much appreciated. I am using R vers. 2.15.0 and ggplot 0.9.1, win xp Best wishes Jonas Hal

I'm trying to reproduce the 3rd graph on the page of this site: http://learnr.wordpress.com/2009/03/17/ggplot2-barplots/ . However, the data below produces a ggplot with the stacks sorted in alphabetical order from the bottom up. I'd like the stacks to be in the order "Europe", "Asia", "Americas, "Africa", "Oceania". Is there an easy way to

Just a thought: Did you try na.rm = TRUE in case you have an object named "T" in scope? -- Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Thu, Jul 27, 2017 at 7:49 AM, Dimitri Liakhovitski <dimitri.liakhovitski at

Dear R Community, Below is a problem with a simple ggplot2 graph. The code returns the error message below. Error: stat_count() must not be used with a y aesthetic. My code is below and the data is attached as a ?text? file. # Graph of the probabilities library(digest) library(DT) datatable(probability) str(probability) probability$Fertilizer <- as.factor(probability$Fertilizer)

I'm trying to develop a stacked bar plot in R with ggplot2. My data: conv = c(10, 4.76, 17.14, 25, 26.47, 37.5, 20.83, 25.53, 32.5, 16.7, 27.33) click = c(20, 42, 35, 28, 34, 48, 48, 47, 40, 30, 30) date = c("July 7", "July 8", "July 9", "July 10", "July 11", "July 12", "July 13", "July 14", "July 15",

I think you should be more suspicious of yourself, Dimitri. A letter T variable can easily arise in the problem domain when you are not thinking of logical values at all, at which point your cavalier use of T as a synonym for TRUE can suddenly become a bug. -- Sent from my phone. Please excuse my brevity. On July 27, 2017 8:18:03 AM PDT, Dimitri Liakhovitski <dimitri.liakhovitski at

Thank you, Bert! I do NOT have an object named "T" in scope (I checked - and besides, it would never occur to me to use this name). TRUE or T results in the same unexpected behavior: ggplot(data = md, mapping = aes(x = a)) + geom_bar(na.rm = TRUE) On Thu, Jul 27, 2017 at 10:57 AM, Bert Gunter <bgunter.4567 at gmail.com> wrote: > Just a thought: > > Did you try

Hello, I think there is a bug in coord_equal when x s a factor : ggplot(diamonds, aes(clarity, fill=cut)) + geom_bar() ggplot(diamonds, aes(clarity, fill=cut)) + geom_bar() + coord_equal(1/2) David

Hi, i'm using this lines of code: dodge <-position_dodge(width=0.9) ggplot(dfm,aes(x = X,y = value)) + geom_bar(aes(fill = variable), position=dodge, stat="identity") + geom_errorbar(aes(ymin=value-er, ymax=value+er),width=0.25, position=dodge,stat="identity") to plot this data frame X variable value er 1 A X4 58.74 9.44 2 B X4