Displaying 20 results from an estimated 1000 matches similar to: "gam and ordination (vegan and labdsv surf and ordisurf)"
2010 Apr 13
1
vegan (ordisurf): R² for smoothed surfaces
Dear r-helpers,
I just read in an article by Virtanen et al. (2006) where vegetation-environment relationships are studied by fitting smoothed surfaces on an NMDS ordination using GAMs (Wood 2000). The authors describe, that they used R? as goodness-of-fit statistic, which they compare to the R? of fitted vectors. Calculations were carried out using the package vegan (Oksanen).
I know that I can
2010 Jun 09
1
ordisurf (pkg vegan) gives implausible result
I'm having trouble with the ordisurf function in the vegan package.
I have created an ordination plot (cmdscale) of 60 samples based on
Bray-Curtis dissimilarities, and would like to overlay various soil edaphic
characteristics as possible clues to the clustering I observe in my plot.
However, I find that ordisurf creates a surface on the plot that is a
perfect, even gradient - and
2011 Sep 28
1
generic argument passing to plot function
Hello I am trying to write a function that would plot timeseries easily...
I aim at plotting two time-series on 2 different y axis sharing the same
x-axis
I succeded in doing so:
plotTimeSerie(x,y,y2,[a lot of other args]){
...
plot()
axis.POSIXct(side=1) #here I build the x-axis
points() #here I plot the first time serie related to y-axis
...
axis(side=2,[some args])
2004 Aug 15
3
Stacking Vectors/Dataframes
Hello,
Is there a simple way of stacking/merging two dataframes in R? I want to
stack them piece-wise, not simply add one whole dataframe to the bottom of
the other. I want to create as follows:
x.frame:
aX1 bX1 cX1 ... zX1
aX2 bX2 cX2 ... zX2
... ... ... ... ...
aX99 bX99 cX99 ... zX99
y.frame:
aY1 bY1 cY1 ... zY1
aY2 bY2 cY2 ... zY2
... ... ... ... ...
aY99 bY99 cY99 ...
2010 Jan 28
2
Data.frame manipulation
Hi All,
I'm conducting a meta-analysis and have taken a data.frame with multiple
rows per
study (for each effect size) and performed a weighted average of effect size
for
each study. This results in a reduced # of rows. I am particularly
interested in
simply reducing the additional variables in the data.frame to the first row
of the
corresponding id variable. For example:
2010 Feb 15
2
creating functions question
Hi All,
I am interested in creating a function that will take x number of lm
objects and automate the comparison of each model (using anova). Here
is a simple example (the actual function will involve more than what
Im presenting but is irrelevant for the example):
# sample data:
id<-rep(1:20)
n<-c(10,20,13,22,28,12,12,36,19,12,36,75,33,121,37,14,40,16,14,20)
2013 Nov 25
4
lmer specification for random effects: contradictory reults
Hi All,
I was wondering if someone could help me to solve this issue with lmer.
In order to understand the best mixed effects model to fit my data, I
compared the following options according to the procedures specified in many
papers (i.e. Baayen
<http://www.google.it/url?sa=t&rct=j&q=&esrc=s&source=web&cd=1&ved=0CDsQFjAA
2011 Oct 26
2
Error in summary.mlm: formula not subsettable
When I fit a multivariate linear model, and the formula is defined
outside the call to lm(), the method summary.mlm() fails.
This works well:
> y <- matrix(rnorm(20),nrow=10)
> x <- matrix(rnorm(10))
> mod1 <- lm(y~x)
> summary(mod1)
...
But this does not:
> f <- y~x
> mod2 <- lm(f)
> summary(mod2)
Error en object$call$formula[[2L]] <- object$terms[[2L]]
2010 Feb 20
3
aggregating using 'with' function
Hi All,
I am interested in aggregating a data frame based on 2
categories--mean effect size (r) for each 'id's' 'mod1'. The
'with' function works well when aggregating on one category (e.g.,
based on 'id' below) but doesnt work if I try 2 categories. How can
this be accomplished?
# sample data
id<-c(1,1,1,rep(4:12))
n<-c(10,20,13,22,28,12,12,36,19,12,
2010 Jul 09
1
output without quotes
Hi All,
I am interested in printing column names without quotes and am struggling to
do it properly. The tough part is that I am interested in using these column
names for a function within a function (e.g., lm() within a wrapper
function). Therefore, cat() doesnt seem appropriate and print() is not what
I need. Ideas?
# sample data
mod1 <- rnorm(20, 10, 2)
mod2 <- rnorm(20, 5, 1)
dat
2003 Feb 10
2
problems using lqs()
Dear List-members,
I found a strange behaviour in the lqs function.
Suppose I have the following data:
y <- c(7.6, 7.7, 4.3, 5.9, 5.0, 6.5, 8.3, 8.2, 13.2, 12.6, 10.4, 10.8,
13.1, 12.3, 10.4, 10.5, 7.7, 9.5, 12.0, 12.6, 13.6, 14.1, 13.5, 11.5,
12.0, 13.0, 14.1, 15.1)
x1 <- c(8.2, 7.6,, 4.6, 4.3, 5.9, 5.0, 6.5, 8.3, 10.1, 13.2, 12.6, 10.4,
10.8, 13.1, 13.3, 10.4, 10.5, 7.7, 10.0, 12.0,
2012 Jun 06
3
Sobel's test for mediation and lme4/nlme
Hello,
Any advice or pointers for implementing Sobel's test for mediation in
2-level model setting? For fitting the hierarchical models, I am using
"lme4" but could also revert to "nlme" since it is a relatively simple
varying intercept model and they yield identical estimates. I apologize for
this is an R question with an embedded statistical question.
I noticed that a
2009 Oct 21
1
How to find the interception point of two linear fitted model in R?
Dear All,
Let have 10 pair of observations, as shown below.
######################
x <- 1:10
y <- c(1,3,2,4,5,10,13,15,19,22)
plot(x,y)
######################
Two fitted? models, with ranges of [1,5] and [5,10],?can be easily fitted separately by lm function as shown below:
#######################
mod1 <- lm(y[1:5] ~ x[1:5])
mod2 <- lm(y[5:10] ~ x[5:10])
#######################
2008 Oct 16
1
lmer for two models followed by anova to compare the two models
Dear Colleagues,
I run this model:
mod1 <- lmer(x~category+subcomp+category*subcomp+(1|id),data=impchiefsrm)
obtain this summary result:
Linear mixed-effects model fit by REML
Formula: x ~ category + subcomp + category * subcomp + (1 | id)
Data: impchiefsrm
AIC BIC logLik MLdeviance REMLdeviance
4102 4670 -1954 3665 3908
Random effects:
Groups Name Variance
2006 Aug 29
2
lattice and several groups
Dear R-list,
I would like to use the lattice library to show several groups on
the same graph. Here's my example :
## the data
f1 <- factor(c("mod1","mod2","mod3"),levels=c("mod1","mod2","mod3"))
f1 <- rep(f1,3)
f2 <-
2012 May 09
1
reception of (Vegan) envfit analysis by manuscript reviewers
I'm getting lots of grief from reviewers about figures generated with
the envfit function in the Vegan package. Has anyone else struggled to
effectively explain this analysis? If so, can you share any helpful
tips?
The most recent comment I've gotten back: "What this shows is which
NMDS axis separates the communities, not the relationship between the
edaphic factor and the
2008 Sep 08
1
correct lme syntax for this problem?
Hello all,
I am about to send off a manuscript and, although I am fairly
confident I have used the lme function correctly, I want to be 100%
sure. Could some kind soul out there put my mind at ease?
I am simply interested in whether a predictor (SPI) is related to
height. However, there are five different populations, and each may
differ in mean level of height as well as the relationship
2008 Jan 18
2
plotting other axes for PCA
Hi R-community,
I am doing a PCA and I need plots for different combinations of axes (e.g.,
PC1 vs PC3, and PC2 vs PC3) with the arrows indicating the loadings of each
variables. What I need is exactly what I get using biplot (pca.object) but
for other axes.
I have plotted PC2 and 3 using the scores of the cases, but I don't get the
arrows proportional to the loadings of each variables on
2011 Nov 17
1
Log-transform and specifying Gamma
Dear R help,
I am trying to work out if I am justified in log-transforming data and specifying Gamma in the same glm.
Does it have to be one or the other?
I have attached an R script and the datafile to show what I mean.
Also, I cannot find a mixed-model that allows Gamma errors (so I cannot find a way of including random effects).
What should I do?
Many thanks,
Pete
--------------
2010 Sep 08
4
coxph and ordinal variables?
Dear R-help members,
Apologies - I am posting on behalf of a colleague, who is a little puzzled
as STATA and R seem to be yielding different survival estimates for the same
dataset when treating a variable as ordinal. Ordered() is used to represent
an ordinal variable) I understand that R's coxph (by default) uses the Efron
approximation, whereas STATA uses (by default) the Breslow. but we