similar to: re sults from "do.call" function

Hello, I'm trying to calculate an integration and x-axis is a time (format : %Y-%m-%d %H:%M:%S"). I use diff(date, units="mins") in a loop for but sometimes the results stay in seconds (95% is ok). Examples for 2 sets of data are given below (first result stays in seconds whereas the second in minutes as expected). Have you already seen this behaviour ? Any idea to solve this

Dear R users, A co-worker and I are writing a function to facilitate graph plotting in R. The function makes use of a lot of lists in its defaults. However, we discovered that R does not necessarily preserve the defaults if we were to input them in the form of list() when initializing the function. For example, if you feed the function codes below into R: myfunction=function( list1=list

Hi R users: I got this code to generate a graphic for each member of a lists. list1<-list(A=data.frame(x=c(1,2),y=c(5,6)),B=data.frame(x=c(8,9),y=c(12,6))) names1<-names(list1) sapply(1:length(list1),function(i) with(list1[[i]],plot(x,y,type="l",main=paste("Graphic of",names1[i])))) Is there a more elegant solution for not to use two separate lists? I would like to

Hi, I have 22 files (A1, A2, ..., A22) with different number of columns, totaling 10,000 columns: c1, c2, c3, ..., c10000 I have another file with a list of 100 columns that I need to extract. These 100 columns are distributed in 22 files. How to extract the 100 columns of the 22 files? I have done it "manually" with the following commands, for example: cromo1 = read.table ("~

Hi, I have 2 questions on list object:   1. Suppose I have a matrix like: dat <- matrix(1:9,3)   Now I want to replicate this entire matrix 3 times and put entire result in a list object. Means, if "res" is the resulting list then I should have:   res[[1]]=dat, res[[2]]=dat, res[[3]]=dat   How can I do that in the easilest manner?   2. Suppose I have 2 list objects: list1 <- list2

Hi, Algorithm question: I have two sets of "intervals", where an interval is an ordered pair [a,b] of two numbers. Is there an efficient way in R to generate the intersection of two lists of same? For concreteness: I'm representing a set of intervals with a data.frame: > list1 = as.data.frame(list(open=c(1,5), close=c(2,10))) > list1 open close 1 1 2 2 5

Hi, This has bugged me for a bit. First question is how to keep classes with rbind, and second question is how to properly return vecotrs instead of lists after turning an rbind of lists into a data.frame list1=list(a=2, b=as.Date("20090102", format="%Y%m%d")) list2=list(a=2, b=as.Date("20090102", format="%Y%m%d")) rbind(list1, list2) #this loses the

Hello R-Helpers, I have a slight problem with the expresion data[data==""] <- NA which works well for a data.frame. But now i must use the same for a list of data.frames. My idea is data[[]][data==""] but it don´t work. Thanks!! Dominic [[alternative HTML version deleted]]

HI Eliza, You could do this: set.seed(15) mat1<-matrix(sample(1:800,124*12,replace=TRUE),nrow=12) # smaller dataset #Your codes ?list1<-list() ?for(i in 1:ncol(mat1)){ ? list1[[i]]<-t(apply(mat1,1,function(x) x[i]-x)) ? list1} ?x<-list1?? x<-matrix(unlist(x),nrow=12) x<-abs(x) ?y<-colSums(x, na.rm=FALSE) z<-matrix(y,ncol=10) ?z<-as.dist(z) ?z ?# ?? 1?? 2?? 3?? 4?? 5??

Hi, I have two lists 1) List1- 30,000 rows and 104 columns 2) List2- a list of 14000 selected rownames  from List 1 Now, I want to extract all the 104 columns of List1  matching with the 14000 selected rownames from List2.  Psedocode will be something like this: match rownames(List2) with rownames(List1) extract selected matched 104 coloumns from (List1) strore in-> List3 So the

Hi, I am wondering whether we can apply 'cbind/rbind' on many **equivalent** list objects. For example please consider following: > list1 <- list2 <- vector("list", length=2); names(list1) <- names(list2) <- c("a", "b") > list1[[1]] <- matrix(1:25, 5) > list1[[2]] <- matrix(2:26, 5) > list2[[1]] <- 10:14 > list2[[2]] <-

I have the following code: list1 <- list() for (i in list.files(pattern="filename1")){ x <- read.table(i) list1[[i]] <- x } list2 <- list() for (i in list.files(pattern="filename2*")){ x <- read.table(i) list2[[i]] <- x } anslist <- vector('list', length(list1)) for(i in 1:length(list1)) if (list1[[i]] & list2[[i]] >1)

Hi. I read most of the postings here but unfortunately I didin''t found a complete example which could be used. Of cource the ones who are professionals in javascript could implement the missing peaces from the puzzle. What I''m required to do is a tree (sortable list) where items can also be deleted and at each modification a function (ajax) is called to save the changes. For

Dear R users, I have this program aa<-array(rep(0,27),dim=c(3,3,3)) a<-matrix(rep(1,9),ncol=3) n<-0 for (i in 1:3) {            a[i,]<-a[i,]*(-1)       n<-n+1       aa[,,n]<-a[i,] } but i real want to multiply each row  with -1 according to for loop and after that to put it in the array.  I will give an example for what excaclty want -1 -1 -1  1  1  1  1  1  1 -1 -1 -1 -1

I'm attempting to generalise a function that reads individual list components, in this case they are matrices, and converts them into 3 dimensional array. I can input each matrix individually, but want to do it for about 1,000 of them ... This works array2 <- abind(list1[[1]],list1[[2]],list1[[3]],along=3) This doesn't array2 <- abind(list1[[1:3]],along=3) This doesn't either

R-helpers: Say I have two lists of arbitrary elements, e.g.: list1=list(c(1:3),"R is fun!",c(3:6)) list2=list(c(10:5),c(5:3),c(13,5),"I am so confused") I would like to produce a single new list that is composed of all combinations of the "top level" of list1 and list2, e.g.: listcombo=list(list(list1[[1]],list2[[1]]),list(list1[[1]],list2[[2]]

I am experimenting with some of the common r functions. I had a question re:using "gsub" (or some similar functions) on the contents of a list. I want to design a function that looks at "everything" contained din a list, and anytime it finds the text string "pattern" replace it with "x". I also wish to preserve the "structure" of the original

For a list say; list1<-{1,2,3,4,5,2,1} How do I remove the duplicates please? My real list is 20,000 obs long of dates with many duplicates Regards Glenn [[alternative HTML version deleted]]

I am new to R, and I have been running into the following situation when I mistype a variable name in some code: > list1 <- list( a=1, b=2 ) > list2 <- list( a=1 ) > list2$b <- list1$c > list2 $a [1] 1 I would think at the point where I am trying to reference a field called "c" -- that does not exist -- in list1, there would be an error flagged. Instead, list1$c

I cannot understand why the following expression is accepted (and gives the expected result: to set column 3 and 4 of the first element of list1 -a data.frame list- as first element of list2): > list2[[1]]<-list1[[1]][3:4] ...while this one is not (to do the same iteratively from the first to the eleventh element of list1): > for (i in 1:11){list2[[i]]<-list1[[i]][3:4]} Error in