similar to: Suppressing internal grid in filled.contour

I've got the graphic with this: a=c(120,40,75,85,55,75,55,90,90,55,155) plot(ecdf(a)) How can I draw lines to show the lower quatile and upper quartil? I only know there is the argument lines(), but I don't know how to use it -- View this message in context: http://r.789695.n4.nabble.com/How-can-I-draw-a-line-in-empirical-distribution-function-tp3090675p3090675.html Sent from the R

I apologize for what may be a newbie question: I have two sets of data, one is X,Y,Z data that I'd like to make a contour plot of (Z defining the contours), and a second set of X,Y data (Y as a function of X) which I would like made into a line plot OVERLAYED on the contour plot (X and Y from both plots are in the same units and will have overlapping values). Any suggestions on how to do this

I'm working on an update for my CRAN package "spatial.tools" and I noticed a new warning when running R CMD CHECK --as-cran: * checking CRAN incoming feasibility ... NOTE Maintainer: 'Jonathan Asher Greenberg <spatial-tools@estarcion.net>' Depends: includes the non-default packages: 'sp' 'raster' 'rgdal' 'mmap' 'abind'

I'm trying to hunt down an appropriate kriging package for my specific application, and I was hoping someone on the R list might have some pointers -- I'm interested in performing kriging and related spatial interpolations with one of the R packages, but I need to be able to provide my own point-to-point distances (e.g. I do not want to use standard between point distances, as calculated

R-developers: I'm working on updating my R package "spatial.tools", and one thing I was wondering was the proper way to have hidden functions -- should I simply not export them to the namespace and use the ::: operator to call them (which is what I currently do)? --j -- Jonathan A. Greenberg, PhD Assistant Professor Global Environmental Analysis and Remote Sensing (GEARS)

I'm trying to redirect where temporary files go under R to D:\temp\somerandomname from its default (C:\Documents and Settings\username\Temp\somerandomname) -- how do I go about doing this? --j -- Jonathan A. Greenberg, PhD Postdoctoral Scholar Center for Spatial Technologies and Remote Sensing (CSTARS) University of California, Davis One Shields Avenue The Barn, Room 250N Davis, CA 95616

Hopefully this is a pretty easy fix -- I need to have R query the path separator for some code I'm trying to write (it involves using a system() call) -- the call requires a path and a wildcard, e.g.: command="mycommand /path/to/*.files" in the case of unix or, command="mycommand.exe C:\\path\\to\\*.files" on a windows box System.which is working correctly, so the

R-helpers: I'm working on an r-package that I want to make as easy-to-use as possible for a novice R-user, which includes automatically installing required packages. I, myself, am a novice R-packager, so the solution I came up with was to embed: print("Loading required packages...") if (!require("reshape")) { install.packages("reshape") } if

R'ers: I was hoping I could get some direction on this. I have a dataset of the form: Y1,Y2,...,YM = f(X1,X2,...,XN), where N is >>> M The response data (Y1,Y2,...,YM) is frequency data, such that the sum of all Yi = 1.0. Both Xj and Yi are continuous variables. I'm trying to figure out the best approach(es) to solving for the model f() -- any ideas? I could solve

R-helpers: I'd like to be able to store all the file information from an ftp site (e.g. file and foldernames) through an R command. Any ideas how to do this? Here's an example site to use: ftp://e4ftl01.cr.usgs.gov/MOTA/MCD15A3.005 --j -- Jonathan A. Greenberg, PhD Assistant Professor Department of Geography and Geographic Information Science University of Illinois at

R-helpers: I need a quick help with the following graph (I'm a lattice newbie): require("lattice") npp=1:5 names(npp)=c("A","B","C","D","E") barchart(npp,origin=0,box.width=1) # What I want to do, is add a single vertical line positioned at x = 2 that lays over the bars (say, using a dotted line). How do I go about doing this?

Quick question -- if I have a vector of strings that I'd like to split into two new vectors based on a substring that is inside of each string, what is the most efficient way to do this? The substring that I want to split on is multiple characters, if that matters, and it is contained in every element of the character vector. --j -- Jonathan A. Greenberg, PhD Postdoctoral Scholar

R-developers: I'm beginning to work on a manuscript for a set of functions I developed for a package I have on CRAN (spatial.tools), and I'd like to rename a function in my package to give a better idea of what it does prior to manuscript submission -- is there a "safe" way to do a backwards-compatible rename of a function within a CRAN package (so functions that rely on the

This is probably a very noobish question, but if I want to create a function that allows an undetermined number of, say, numeric vectors to be fed to it, I would use: myfunction = function(...) { # Do something } Right? If so, how do I a) count the number of vectors "fed" to the function, and b) how do I treat those vectors as variables, e.g. for the call:

I have a numerical vector which contains a (poorly) formatted time column, which, in theory, should be HHMM, but was distributed as an integer, so, for 12:15 am, it is saved as "15" (e.g. HHMM = 0015 with the zeroes stripped). I'm trying to use this in conjunction with strptime, but I'm thinking because each time is an integer ranging from 1 to 4 digits, I probably need to

I'm hoping to get some "best practice" feedback for constructing a function call which takes an undefined set of DIFFERENT length vectors -- e.g. say we have two lists: list1=c(1:10) list2=c(2:4) lists = data.frame(list1,list2) coerces those two to be the same length (recycling list2 to fill in the missing rows) -- what is a quick way of having each of those lists retain their

R-helpers: It looks like http://finzi.psych.upenn.edu/search.html has stopped spidering the mailing lists -- this used to be my go-to site for searching for R solutions. Are there any good replacements for this? I want to be able to search both functions and mailing lists at the same time. Cheers! --j -- Jonathan A. Greenberg, PhD Assistant Professor Department of Geography University of

R-helpers: Say I have a list: myvariables <- list(a=1:10,b=20) Is there a way to load the list components into the environment as variables based on the component names? i.e. by applying this theoretical function to myvariables I would have the variables a and b loaded into the environment without having to explicitly define them. --j -- Jonathan A. Greenberg, PhD Assistant Professor

Rhelpers: I'm trying to make a barchart of a 2-group dataset (barchart(x~y,data=data,groups=z,horizontal=FALSE)). My problem is that I can't, for the life of me, seem to get rid of the inter-bar space -- box.ratio set to 10000 doesn't do much. Any ideas? I'd ideally want zero space between the bars. Thanks! --j -- Jonathan A. Greenberg, PhD Assistant Project Scientist

Our lab has a lot of different unix boxes, with different hardware, and I'm assuming (perhaps wrongly) that by setting a per-user package installation directory, the packages will only work on one type of hardware. Our systems are all set up to share the same home directory (and, thus, the same .Renviron file) -- so, is there a way to set, in the .Renviron file, per-computer or