Displaying 20 results from an estimated 100 matches similar to: "nomogram function (design library)"
2006 Mar 02
0
glmpath (new version 0.91)
We have uploaded to CRAN a new version of glmpath, a package
which fits the L1 regularization path for generalized linear models.
The revision includes:
- coxpath, a function for fitting the L1-regularization path for the Cox
ph model;
- bootstrap functions for analyzing sparse solutions;
- the ability to mix in L2 regularization along with L1 (elasticnet).
We have also completed a report that
2006 Mar 02
0
glmpath (new version 0.91)
We have uploaded to CRAN a new version of glmpath, a package
which fits the L1 regularization path for generalized linear models.
The revision includes:
- coxpath, a function for fitting the L1-regularization path for the Cox
ph model;
- bootstrap functions for analyzing sparse solutions;
- the ability to mix in L2 regularization along with L1 (elasticnet).
We have also completed a report that
2008 Mar 02
0
coxpath() in package glmpath
Hi,
I am new to model selection by coefficient shrinkage
method such as lasso. And I became particularly
interested in variable selection in Cox regression by
lasso. I became aware of the coxpath() in R package
glmpath does lasso on Cox model. I have tried the
sample script on the help page of coxpath(), but I
have difficult time understanding the output.
Therefore, I would greatly appreciate if
2010 Jun 04
0
glmpath crossvalidation
Hi all,
I'm relatively new to using R, and have been trying to fit an L1
regularization path using coxpath from the glmpath library.
I'm interested in using a cross validation framework, where I crossvalidate
on a training set to select the lambda that achieves the lowest error, then
use that value of lambda on the entire training set, before applying to a
test set. This seems to entail
2008 Feb 22
0
R CMD check for glmpath on Windows (PR#10823)
The problem first appeared in R 2.6.1 and is still there in R 2.6.2
On Windows running R CMD check command for glmpath package fails. The reason
seems to be that when R is running the examples file (glmpath-Ex.R), it skips
about 50 lines and as a result gives a syntax error.
I'm working with a modified version of the CRAN glmpath 0.94. My version
happens to give a more clear example of a
2009 Mar 31
3
R Language Bloggers and Web Sites Owners
Dear List,
Apologies in advance for non bloggers for the spam on the slightly off topic.
This is an invitation to all R language bloggers to help spread the
world at a forum where leading authors come?together.
Current only 1 R blogger is there- David Smith, from Revolution Computing.
There are many from SAS (Jason Burke,Gary Conkins) ,one from SPSS (Jon
Peck) and others from SAP,Aster Data
2010 Mar 23
0
glmpath and coxpath variables
Hi,
I am analyzing a set of variables in order to create a survival model for a
set of patients. I have checked the reference manual for glm path and
coxpath in order to achieve it. However I have a doubt about the class of
the covariates I can use with the last mentioned package.
In the example, the package loads a list called "lung.data". This object has
a matrix with the covariate
2008 Oct 15
0
R-help Digest, Vol 67, Issue 31
V;
Sent via BlackBerry from T-Mobile
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Subject: R-help Digest, Vol 67, Issue 31
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2010 Dec 14
0
Urgent help requested using survfit(individual=T):
Hello:
I would like to obtain probability of an event for one single patient as a
function of time (from survfit.coxph) object, as I want to find what is the
probability of an event say at 1 month and what is the probability of an
event at 80 months and compare. So I tried the following but it fails
miserably. I looked at some old posts but could not figure out the solution.
Here's what I did
2010 Dec 14
1
survfit
Hello R helpers:
*My first message didn't pass trough filter so here it's again*
I would like to obtain probability of an event for one single patient as a
function of time (from survfit.coxph) object, as I want to find what is the
probability of an event say at 1 month and what is the probability of an
event at 80 months and compare. So I tried the following but it fails
miserably. I
2007 Oct 03
1
Nomogram
Hi R users.
I have a model of cox that already it is estimated (I have only the
model estimated, I haven't data), how can I determine a nomogram with
R? Is it posible to do nomograms in Design package? I think that's
only when the model (Cox Regression in this case) is before estimated
in R.
Thanks
2010 Aug 25
1
modify a nomogram
Hi,
I would like to emphasize ("zoom") the zone of a nomogram where the
probability are > 0.01
(nomogram built with nomogram, Design).
As a consequence, I don't need to draw the part of the "Total points"
axis with score < 60 equivalent in my case to a linear predictor < 4.5
- As far as I know, this is not possible with the arguments of the function.
- Changing
2013 Nov 12
0
A problem about nomogram
You did not follow the posting guide, did you use pure ascii email, and
used illegal characters in your source code. This caused extra work.
Once I cleaned up your characters and made the example self-contained,
the labels worked fine for me. Here's the cleaned-up code:
library(rms)
x1 <- runif(20)
x2 <- runif(20)
y <- sample(0:1, 20, TRUE)
label(x1) <- 'A'
label(x2)
2006 Nov 06
1
Competing risk nomogram
Dear R Users,
Do you have a sample code for developing a nomogram with competing-risks?
Any help is appreciated.
Kind regards,
ND Nguyen
2013 Mar 21
1
Re-order variables listed in nomogram?
Hi,
I am using the function "nomogram" in the rms package for survival analysis.
How is the order in which variables determined and how can I change it? I use it with a cph() model.
Many Thanks
Eleni Rapsomaniki
Clinical Epidemiology Group
Department of Epidemiology and Public Health
University College London
2017 Oct 26
1
nomogram function error
Hi R-help,
?
I have fit a cox ph model to my data, but have beenreceiving an error when trying to fit a model to the nomogram. Here is the codeand corresponding error:
?
?
>nomogramCF = nomogram(cph_age6_40avp4,
+????????????????????lp.at= seq(-10,10,by =0.5),lp = TRUE,
+??????????????????????
+??????????????????????funlabel="5year survival",
2005 May 30
0
Nomogram
I don't think Spencer replied to your message. It wasn't addressed to you. He was replying to a specific post on nomograms. However you might try being less specific as a search on "spatial cluster" gave back
[R] mclust - clustering by spatial patterns http://finzi.psych.upenn.edu/R/Rhelp02a/archive/13474.html
[R] Spatial Clustering
2011 Jun 24
1
Competing-risks nomogram
Hi R users,
I'd like to draw a nomogram using a competing-risks regression (crr function
in R), rather than a cox regression. However, the nomogram function provided
in the Design package is not good for this purpose.
Do you have any suggestion.
I really appreciate your help
Many thanks
F.Abdollah, MD
San-Raffele hospital
Milan, Italy
--
View this message in context:
2011 Nov 30
0
formula for calculating the survival probability for nomogram
Hi, I used Dr. Harrell's rms package to make a nomogram.
Below is my code for nomogram and calculate total points and probability *in
original data set* used for building the nomogram. *My question is how I get
the formula for calculating the survival probability for this nomogram. Then
I can use this formula to do validation by using other data set. *
f1 <- cph(Surv(retime,dfs) ~
2013 Feb 14
1
Nomogram after Cox Random Effect (frailty) model
Dear R-users,
I am a novice R-user with some experience in using the RMS package for taking nomograms after various survival models.
This time, I am trying to plot a nomogram after a Random Effects Cox, implemented by the "coxme" package. My questions are:
1. Is it possible to take a nomogram directly after the coxme survival function?
2. If not is there a way to take the linear