similar to: does there any function like sumif in excel?

R-help, I have two data frames df1 and df2: >head(df1) lgdcm 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 3 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 4 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 5 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ... ... > head(df2)

Can somebody tell me how to do the equivalent of a pivot table in R ? For example, if I have : var1 var2 var3 a x 10 b y 20 a z 10 b z 20 a z 10 b z 20 I could have : x y z a 1 0 2 b 0 1 2 where entries in the table are counts of var3.

I have an S3 class called "tis" (Time Indexed Series) which may or may not have multiple columns. I have a function "[<-.tis" that I've reproduced below. My question is this: inside of "[<-.tis", how can I distinguish between calls of the form x[i] <- someValue and x[i,] <- someValue ? In either case, nargs() is 3, and looking at the values

I have an S3 class called "tis" (Time Indexed Series) which may or may not have multiple columns. I have a function "[<-.tis" that I've reproduced below. My question is this: inside of "[<-.tis", how can I distinguish between calls of the form x[i] <- someValue and x[i,] <- someValue ? In either case, nargs() is 3, and looking at the values

Dear all, I coded a function called u.glm u.glm <- function (x,ahi,age,bmiz,gender) { library(nortest) lil.rslt <- lillie.test(x) if (lil.rslt$p.value >0.05) { cat("Logtrans=0, lillie=",lil.rslt$p.value,"\n") xmodel<-glm(x~ahi+age+bmiz+as.factor(gender)) summary(xmodel) confint(xmodel) } else { cat("Logtrans=1,

Dear list, I have a series of data points which I want to approximate with exactly two linear functions. I would like to choose the intervals so that the total deviation from my fitted lines is minimal. How do I best do this? Thanks! Kamila The information transmitted in this electronic communication...{{dropped}}

Rusers, I am trying to append multiple .csv files of different dimensions (but # of columns are the same for all .csv files). I do have .csv files whose names are CA1.csv ~ CA100.csv. CA means california and 1 means the first file. So what I have been doing (after googling how to append by row multiple files) was: cleanup_data<-function(state,count) { out<-matrix() for (i in 1:

Sorry guys, but I chose a really stupid name before (no "reference classes"). Hope it's okay to re-post. Cheers, Janko >>> ORIGINAL MESSAGE <<< Dear list, Is it possible to update or reassign '.self' with an image of '.self' (e.g. a locally stored .Rda file) from within a method? I know that this might sound akward, but here's the use

I'm trying to set a channel variable and make it available to another channel: I thought that if I SetVar(_SomeVariable=SomeValue) or SetVar(__SomeVariable=SomeValue) then SomeVariable would be available in the destination channel. However __SomeVariable, _SomeVariable and SomeVariable are all blank. The scenario: Agents logon to the queue using callbacklogin. From what I can gather

Hi everyone, I am quite new to R. my command is t.test(c(1:5,7:11), y=c(1:10),alternative = c("two.sided"), paired = TRUE) The output is Paired t-test data: c(1:5, 7:11) and c(1:10) t = 3, df = 9, p-value = 0.01496 alternative hypothesis: true difference in means is not equal to 0 95 percent confidence interval: 0.1229738 0.8770262 sample estimates: mean of the differences

Hi, I have a dataset with 6 categorical variables. I have used this following code to make the variables u1-u6 ordered factors and this works well. cat1cat2 cat3 cat4 cat5 cat6 ? 0 ? ?? 1 ? ? 1????? 0 ??? 0? ?? 1 ? 1 ? ?? 1 ? ? 0 ? ?? 0 ? ? 0 ? ? 0 ....... .... ############ data<-read,table("example.txt") data <- as.data.frame(lapply(data, ordered)) ############ Now,

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Hi I have the following columns with dates and results, sorted by subject and date. I'd like to compute the differences in dates and results for each patient, based on the previous row. Obviously the last entry for each subject should be a NA. Which would be the best way to accomplished that ? I guess questions like that have been already answered a thousand times, so I apologize for

On 08/06/18 19:38, Phil Perry wrote: > On 08/06/18 15:54, lejeczek wrote: >> hi >> >> how do you pass vars to rpmbuild for definition? eg >> >> rpmbuild --define \'"${_definition2}"\' >> >> I've been fiddling with ways to escape, but none is >> fricking working.. >> I mean, rpmbuild rushes to work(no errors nor

> What do you mean exactly by "behave differently on the other side of the cast”? Do you have a concrete example? I was hesitant to say only in that it is probably an "abuse of mechanics" and definitely playing with fire, _however_ the target I'm working on has extensive bit operations for a subset of memory, including atomic test-and-set, etc. It's convenient to be

hi guys I need to interpolate values for the zero coupon yield curve. Following data is given date days rate 1996 01

dear list, since matrix manipulations is often of interest in statistical computations, i'd like to get a working example of using Lapack for regression. However, i run into an error. My matrix-lapack-example.c file: #include <R_ext/Lapack.h> void reg(const char* trans, const int* m, const int* n, const int* nrhs, double* a, const int* lda, double* b, const int*

Hi, I am a new user of R using R 2.8.1 in windows 2003. I have a csv file with single column which contain the 30,000 students names. There were typo errors while entering this student names. The actual list of names is < 1000. However we dont have that list for keyword search. I am interested in grouping/cluster these names as those which are similar letter to letter. Are there any

Ok... I am reluctant to ask this question as I believe that it may be like asking what someones favorite linux distribution is... but I need to make an informed decision. We are getting ready to upgrade from a TE210P to a quad T1 card with echo cancellation. I am trying to decide between the Sangoma card and the Digium card. I need this to have great quality and I need it to work well. I would

I'm new with R. I want to plot 3 lines in one graph. This is my data: print(x) V1 V2 V3 V41 -4800 25195.73 7415.219 7264.282 -2800 15195.73 5415.219 7264.28 I tried using matplot, but I cannot get exactly what I want. This is what I get, and this is my code: matplot(x[,1],x[,-1],type='b', xlab = "epsilon_h", ylab = "Value2", xlim=