similar to: data frame column name as a function argument

Hi, I'm trying the brlr function in a penalized logistic regression function. However, I am not sure why I am encountering errors. I hope to seek your advice here. (output below) Thank you! Your help is truly appreciated. Min-Han #No error here, the glm seems to work fine >

Hi, I'm a new user or R and I try to concatenate a several rows according with the value in a column. this is my data.frame and I want to concatenate my data.frame according with the column "b" and make a new data.frame with the information in the others columns. >table1 a b c d 1 E001234 TSA IP234 like_domain 2

I have a data frame of around 4500 rows which contain file name prefixes and other interesting variables. each prefix corresponds to multiple files and a I only have 4300 complete sets of files. If any one of the files is missing for a given prefix, then the function I use fails. The effect is emulated by the function "f" and data "dummy.data": f <- function(x) if(runif(1)

I have a question, which very easy to solve, but I can't find a solution. I want to convert a data frame to matrix. Here my toy example: > L3 <- c(1:3) > L10 <- c(1:6) > d <- data.frame(cbind(x=c(10,20), y=L10), fac=sample(L3, + 6, repl=TRUE)) > d x y fac 1 10 1 1 2 20 2 1 3 10 3 1 4 20 4 3 5 10 5 2 6 20 6 2 > is.data.frame(d) [1] TRUE > sapply(d,

I want to transform the data by "tapply" to one dataframe. But I can not get it. For example: > tst=tapply(point,pp,length) > tst[1:10] p1 p10 p100 p1000 p1001 p1002 p1003 p1004 p1005 p1006 1 5 1 8 6 5 8 7 4 4 > res=as.data.frame(tst) # I try to transform it > res[1:10,] p1 p10 p100 p1000 p1001 p1002 p1003 p1004 p1005 p1006 1 5 1 8 6 5

Hi, I'm a R newbie and want to accelerate the following pre-filtering step of a data set with more than 115,000 rows : #----------------- # Function to filter out constant data columns filter.const<-function(X, vectors=c('column', 'row'), tol=0){ realdata=c() filteredX<-matrix() if( vectors[1] == 'row' ){ for( row in (1:nrow(X)) ){ if(

Hi, I often run into this problem: I have a data.frame with one column containing entries that are not unique. What I then want is a subset of the data.frame in which the entries in that column have become the 'unique' of the original column. Normally I program around it by taking the unique of the column and making a new data.frame with it and filling the rest of the data. (By the way,

A copy of this question can be found on Cross Validated: https://stats.stackexchange.com/questions/645362 I am estimating a system of seemingly unrelated regressions (SUR) in R. Each of the equations has one unique regressor and one common regressor. I am using `gmm::sysGmm` and am experimenting with different weighting matrices. I get the same results (point estimates, standard errors and

Does anyone know if there is an R function that will take a matrix like this jim 1 0 0 0 0 0 jim 0 1 0 0 0 0 jim 0 0 1 0 0 0 bob 1 0 0 0 0 0 bob 0 0 1 0 0 0 harry 0 0 1 0 0 0 harry 0 0 0 1 0 0 harry 0 0 0 0 1 0 harry 0 0 0 0 0 1 and make it like this? (that is, add together rows that have the same name?) jim 1 1 1 0 0 0 bob

Hi all, I have this (non-working) script: dataTest <- data.frame(col1=c(1,2,3)) new.data <- c(1,2) name <- "test" n.row <- dim(dataTest)[1] length(new.data) <- n.row names(new.data) <- name cbind(dataTest, name=new.data) print(dataTest) and would like to bind the new column 'new.data' to 'dataTest' by using the value of the variable 'name' as

Generally speaking, this sort of detailed statistical question about a speccial package in R does not get a reply on this general R programming help list. Instead, I suggest you either email the maintainer (found by ?maintainer) or ask a question on a relevant R task view, such as https://cran.r-project.org/web/views/Econometrics.html . (or any other that you judge to be more appropriate).

I am trying to write a function to change the case of all of the text in a data frame to lower case. I do not have foreknowledge of the data frame names or the data types of each column. It seems that if one references the data frame by index, then it returns class "data.frame" but if it is referenced by name, it returns class "factor" or whatever the column actually is:

Hi All, I have attempted to extract only the factor columns from an existing data set inside a loop without success . I tried the transform function which worked, but not inside the loop (attempts with cbind did not work either - inside a loop). Here is my function: getcatcolumns<-function(x) { # ignore type checking for data frames etc res <- data.frame() for(i in

I wish to set up a simple function using boxplot so that it will be available to someone using R for Windows. (I myself use Linux.) The way the data is organised makes it convenient to use the boxplot function in a manner similar to this example given in the help. > mat <- cbind(Uni05 = (1:100)/21, Norm = rnorm(100), + T5 = rt(100, df = 5), Gam2 = rgamma(100, shape

I'm having trouble reshaping a data.frame from long to wide. (I think that's the right terminology; feel free to educate me.) I've looked at the reshape function and package and plyr package, but I can't quite figure out how to do this after a dozen variations. I have a data.frame with more levels than this, but similar to: > tst K1 K2 K3 V1 V2 V3 1 10 D a 0.08 99

Hello, I'm trying to use tapply to find group means in a function. It works outside of a function, but I get the error message from the following code: "Error in tapply(index, cluster, mean) : arguments must have same length." Any suggestions? Thanks. eric d <- data.frame(cbind(cluster=1:2, value1=1:10, value2=11:20)) d FindClusterTraits <- function(framename, index){

Dear R helpers, I have one trivial problem while writing an output file in csv format. I have two dataframes say df1 and df2 which I am reading from two different csv files. df1 has column names as date, r1, r2, r3 while the dataframe df2 has column names as date, 1w, 2w. (the dates in both the date frames are identical also no of elements in each column are equal say = 10). I merge these

A user sent me an example where coxph fails, and the root of the failure is a case where names(mf) is not equal to the term.labels attribute of the formula -- the latter has an extraneous newline. Here is an example that does not use the survival library. # first create a data set with many long names n <- 30? # number of rows for the dummy data set vname <- vector("character",

Dear R contributors, I have a problem in selecting in an efficient way, rows of a data frame according to a condition, which is a part of a row name of the table. The data frame is made of 64 rows and 2 columns, but the row names are very long but I need to select them according to a small part of it and perform calculations on the subsets. This is the example: X Y "Unique to

For some time I have been using rsync to backup data between different machines and my NAS drive. But within the last 2 days I have found out that rsync is not removing old files from destination - directories renamed or removed from source. In this example I want to sync files on my Debian Linux server to a NAS drive. NAS drive is mounted using smbmount. Using "-avhzn" dry-run it