similar to: string to numeric question

R-help - I have this set of aggregated tables (sample data below via dput()). And I would like to have delayValue as the column variables with the "temp" (temp1, temp2, temp3) values as the row variables. However I would like to have the temp variables *aggregated into single rows* so that I have the frequency ("Freq" | counts) of each time each "delayValue" occurs

Hello,=0D =0D I just noticed that the "svd" function does not work properly for some=0D sparse matrices.=0D When I replace the 0 by very small noises (let's say 10^-16), it then=0D works.=0D The test I've performed is to compared the singular values to the eigen=0D values (as I work with squarred matrices).=0D =0D Here is the code (I may be wrong!):=0D =0D

Hello, No public anwer came to my previous post, and my problem is urgent, so I'm trying again. I'm using Ogg Vorbis since 2000 and some of my files appear to be damaged - at least some players reject some of them (WinAmp, Quintessential Media Player beta 116). Is there a repair tool for Windows which could rebuild vorbis files so that they all could be played in WinAmp, which is very

Uuugh..for the life of me, i cannot delete sound files using "EXEC System(rm /var/lib/asterisk/sounds/blah.gsm)" through AGI the AGI debug log indicates the command executes successful ( equals 0) but my files are clearly still there. If i try System(rm ...) in my extensions.conf diaplan it'll work there. Is there a bug in the AGI to use "System" ? because i tried to

hi, I considered multivariate multiple regression for respons, predictor, each 5 dimension. on going process, through initb <- eigen(temp)$vectors[,1:3] temp <- vhalf%*%Kproduct(Ir,initb) (herein 'vhalf' is root for inverse of covariance matrix and 'Kproduct' is Kronecker product) and then process regression. However, I have tried using the

Hello, I'd like to transpose data to create an analysis-friendly dataframe. See below for an example, I was unable to use t(x) and I couldn't find a function with options like PROC TRANSPOSE in SAS. The ideal solution handles variable quantities of SITE - but beggars can't be choosers. :-) Thank you in advance, Mike ## INPUT DATA USER_ID<-c(1,1,1,2,2,2,3,3,4) SITE

Hi all, Here I am trying to implement the switch() function to choose value of a variable depending on the value of an input variable :   temp1 <- "1"               temp1.name <- switch(temp1,                                   1 == "aa",                                   2 == "bb",                                   3 == "cc",

Hi I am trying to estimate bottom temperatures over a particular depth range, based on one dataset containing synthetic temperature profiles (for set depths) and another that contains information on bathymetry. I need to do this for multiple regions and thus would ideally like an automated solution that is quicker and more accurate than the manual option I currently have! I have not had much luck

this is a bad question but I can't figure it out and i've tried. if i sort the 2 column matrix , temp1, by the first column, then things work as expected. But, if I sort the 1 column matrix, temp2, then it gets turned coerced to a vector. I realize that I need to use drop=FALSE but i've put it in a few different places with no success. Thanks. temp1 <-

I realize this is a shot in the dark, but I'm trying to find a VoIP provider that offers 402 or 712 area code DID numbers. I'm almost completely convinced that no one offers these area codes (eastern Nebraska, western Iowa), however considering the wide audience of this mailing list I thought this would be a good place to ask. I would prefer a provider that allows for Asterisk use, but I

Hi, I have a data.frame that is date ordered by row number - earliest date first and most current last. I want to create a couple of new columns that show the max and min values from other columns *so far* - not for the whole data.frame. It seems this sort of question is really coming from my lack of understanding about how R intends me to limit myself to portions of a data.frame. I get the

i'm sorry. i had an error in my previous code because i left out a letter in the rownames. while fixing that, i also found a solution. so i'm sorry for the confusion. below is my fix. temp2 <- matrix(rnorm(10),nc=1,nrow=10) rownames(temp2) <-

I am using R 2.1.1 in an windows XP environment. I have 2 dataframes, temp1 and temp2. Each dataframe has 20 variables (“cocolumns") and 525 observations (“rows”). All variables are numeric. I want to create a new dataframe that also has 20 columns and 525 rows. The values in this dataframe should be the sum of the 2 other dataframe. (i.e. temp1$column

Dear all, I'm trying to gsub() "%" with "\%" with no obvious success. > temp1 <- c("mean", "sd", "0%", "25%", "50%", "75%", "100%") > temp1 [1] "mean" "sd" "0%" "25%" "50%" "75%" "100%" > gsub("%",

Hi all, hope you having a nice day, I ahve this weird results with identical (probably I am not understanding correctly what it does ...) I have these two data frames and I issue : > identical(temp, temp1) [1] FALSE However, these data frames are Nx2 and when I issue: > identical(temp[,2], temp1[,2]) [1] TRUE > identical(temp[,1], temp1[,1]) [1] TRUE and the results from str >

HI Irucka, Please check this: temp<- structure(list(`:Bostoncitydata` = structure(list(Month = c(1L, 2L, 3L, NA), Data1 = c(1.5, 12.3, 11.4, NA), Data2 = c(9.1342, 12.31, 3.5, NA)), .Names = c("Month", "Data1", "Data2"), class = "data.frame", row.names = c(NA, -4L)), `:Chicagocitydata` = structure(list(Month = c(1L, 2L, 3L, 4L, 5L, NA), Data1 = c(1.52,

Dear R-help, I have a character vector, some elements will be numeric, some not, and some even empty. E.g.: temp1 <- c("abcd"," 2 ","") I'm only interested in the numeric elements, the rest I can just throw away. It is easy enough to loop through the vector: temp <- try(eval(parse(text=temp1[1])), silent=TRUE); class(temp) # try-error temp <-

I stumbled onto this working on an update to coxph. The last 6 lines below are the question, the rest create a test data set. tmt585% R R version 2.12.2 (2011-02-25) Copyright (C) 2011 The R Foundation for Statistical Computing ISBN 3-900051-07-0 Platform: x86_64-unknown-linux-gnu (64-bit) # Lines of code from survival/tests/singtest.R > library(survival) Loading required package: splines

i have a time Series of IBM closing px from 1/1/2000 to today I want to graph the time serie by dividing the graph by year and month all the monthly graphs with the same year will go to one page. so from 1/1/2000 to 11/19/2010. i will have 11 pages, and each page will have 12 graphs (jan to dec) except for 2010. I am able to do it in R, but when i use sweave, I can only print the last page.

I have a question about the output given below after running few lines of code. Surely a 101 query! MF_Data <- read.csv("MF_Data_F.txt", header = F, sep="|") temp <- head(MF_Data) #Get the sample Data temp1 <- subset(temp, select= c(V1,V4,V6)) #where V1, V4, V6 are the col names .. to Get the relevant data names(temp1) <- c('Ticker',