Displaying 20 results from an estimated 2000 matches similar to: "Why isn't R recognising integers as numbers?"
2008 Oct 16
1
Two last questions: about output
Here is my little scriptlet:
optdata =
read.csv("K:\\MerchantData\\RiskModel\\AutomatedRiskModel\\soptions.dat",
header = FALSE, na.strings="")
attach(optdata)
library(MASS)
setwd("K:\\MerchantData\\RiskModel\\AutomatedRiskModel")
for (i in 1:length(V4) ) {
x = read.csv(as.character(V4[[i]]), header = FALSE, na.strings="");
y = x[,1];
fp =
2008 Oct 15
1
Argh! Trouble using string data read from a file
Here is what I tried:
optdata =
read.csv("K:\\MerchantData\\RiskModel\\AutomatedRiskModel\\soptions.dat",
header = FALSE, na.strings="")
optdata
attach(optdata)
for (i in 1:length(V4) ) { x = read.csv(V4[[i]], header = FALSE,
na.strings="");x }
And here is the outcome (just a few of the 60 records successfully read):
> optdata =
>
2008 Sep 19
4
Novice question about getting data into R
I found it easy to use R when typing data manually into it. Now I need to
read data from a file, and I get the following errors:
> refdata =
> read.table("K:\\MerchantData\\RiskModel\\refund_distribution.csv", header
> = TRUE)
Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings,
:
line 1 did not have 42 elements
> refdata =
>
2008 Sep 22
1
R-help Digest, Vol 67, Issue 23
Warranty on Accuracy, Precision, Legality, ... of R in Research
(These questions may well have been raised.)
What is the implied warranty of using R for research & publications, consulting, etc.?
Alternately, how does one obtain such a warranty?
Your answers will be much appreciated.
Perhaps you can point me to some websites which discussed this subject in the past.
Thanks & regards
2008 Oct 08
0
Applying an R script to data within MySQL? How to?
I am trying something I haven't attempted before and the available
documentation doesn't quite answer my questions (at least in a way I can
understand). My usual course of action would be to extract my data from my
DB, do whatever manipulation is necessary, either manually or using a C++
program, and then import the data into R. Now I need to try to do it all
within R+RMySQL+MySQL.
I
2008 Sep 24
0
Trouble understanding the behaviour of stableFit(fBasics)
Can anyone explain such different output:
> stableFit(s,alpha = 1.75, beta = 0, gamma = 1, delta = 0,
+ type = c("q", "mle"), doplot = TRUE, trace = FALSE, title = NULL,
+ description = NULL)
Title:
Stable Parameter Estimation
Call:
.qStableFit(x = x, doplot = doplot, title = title, description =
description)
Model:
Student-t Distribution
Estimated
2010 Jul 08
1
Query about using timestamps returned by SQL as 'factor' for split
I have a simple query as follows:
"SELECT
m_id,sale_date,YEAR(sale_date),WEEK(sale_date),return_type,DATEDIFF(return_date,sale_date)
AS elapsed_time FROM risk_input"
I can get, and view, all the data that that query returns. The question is,
sale_date is a timestamp, and I need to call split to group this data by
m_id and the week in which the sale occurred. Obviously, I would
2008 Sep 05
1
library/function that estimates parameters of well known distributions from empirical data?
I found this a few months ago, but for the life of me I can't remember what
the function or package was, and I have had no luck finding it this week.
I have found, again, the functions for working with distributions like
Cauchy, F, normal, &c., and ks.test, but I have not found the functions for
estimating the distribution parameters given a vector of values.
What I need to do is
2009 Jan 27
1
Mystery Error in midnightStandard
I wasn't even aware I was using midnightStandard. You won't find it in my
script.
Here is the relevant loop:
date1 = timeDate(charvec = Sys.Date(), format = "%Y-%m-%d")
date1
dow = 3;
for (i in 1:length(V4) ) {
x = read.csv(as.character(V4[[i]]), header = FALSE, na.strings="");
y = x[,1];
year = V2[[i]];
week = V3[[i]];
dtstr =
2008 Oct 14
2
Getting frustrated with RMySQL
Getting the basic stuff to work is trivially simple. I can connect, and, for
example, get everything in any given table.
What I have yet to find is how to deal with parameterized queries or how to
do a simple insert (but not of a value known at the time the script is
written - I ultimately want to put my script into a scheduled task, so the
analysis can be repeated on updated data either daily
2008 Oct 20
1
How to get estimate of confidence interval?
I thought I was finished, having gotten everything to work as intended. This
is a model of risk, and the short term forecasts look very good, given the
data collected after the estimates are produced (this model is intended to
be executed daily, to give a continuing picture of our risk). But now there
is a new requirement.
I have weekly samples from a non-autonomous process (i.e. although well
2011 Mar 07
1
Risk differences with survey package
I'm trying to use the survey package to calculate a risk difference with
confidence interval for binge drinking between sexes. Variables are
X_RFBING2 (Yes, No) and SEX. Both are factors. I can get the group
prevalences easily enough with
result <- svyby(~X_RFBING2, ~SEX, la04.svy, svymean, na.rm = TRUE)
and then extract components from the svyby object with SE() and coef() to
do the
2007 Dec 21
1
using apply to loop
Hi,
I am running the following loop, but it takes hours to run as n is big. Is there any way "apply" can be used? Thanks.
### Start
nclass <- dim(data)[[2]] - 1
z <- matrix(0, ncol = nclass, nrow = nclass)
n <- dim(data)[[1]]
x <- c(1:nclass)
# loop starts
for(loop in 1:n) {
r <- data[loop, 1:nclass]
classified <- x[r == max(r)]
2007 Dec 21
1
using apply to loop [SEC=UNCLASSIFIED]
Hi Louis,
You could try this:
# find the index of the maximum value in each row of _data_, #
disregarding the last column classified <-
apply(data[,-(nclass+1)],1,which.max)
## or, if the maximum may be repeated:
classified <- apply(data[,-(nclass+1)], 1, FUN = function(x) which(x ==
max(x)))
# the variable _truth_ is just the last column of _data_ ?
truth <- data[,nclass + 1]
?table
2017 May 18
2
Bug: floating point bug in nclass.FD can cause hist() to crash
Hello everybody,
This is a bug involving functions in core R package:
graphics::hist.default, grDevices::nclass.FD, and
base::pretty.default. It is not yet on Bugzilla. I cannot submit it
myself, as I do not have an account. Could somebody else add it for
me, perhaps? That would be much appreciated.
Kind regards,
Sietse
Sietse Brouwer
Summary
-------
Floating point errors can cause a data
2012 Oct 07
2
[PATCH] drm/nouveau: fix error handling in core/core object creation functions
Signed-off-by: Marcin Slusarz <marcin.slusarz at gmail.com>
---
This patch relies on "drm/nouveau: remove >1 sclass support from nouveau_parent_create_".
There are *many* *more* code paths without proper error handling - I counted
at least 106 in 41 functions. If someone would like to do a bit of janitorial
work I marked those code paths and uploaded "patch" here:
2008 Oct 15
1
dbAppy questions/clarifications
In the example in the documentation, I see:
rs <- dbSendQuery(con,
"select Agent, ip_addr, DATA from pseudo_data order by Agent")
out <- dbApply(rs, INDEX = "Agent",
FUN = function(x, grp) quantile(x$DATA, names=FALSE))
Maybe I am a bit thick, but it took me a while, and a kind hint from Phil,
to figure much of this out.
It is clear that the SQL
2008 Jun 23
5
Need ideas on how to show spikes in my data and how to code it in R
Hi
I have recently been analyzing birthweight data from a clinic. The
data has obvious defects in that there is digit preference on certain
weights making them overrepresented. This shows as spikes in the
histogram on certain well rounded weights like 2, 2.5, 3, etc. I
would like to show this to government officials but can't figure out
how I should present the finding in an easy to
2012 Oct 07
1
[PATCH] drm/nouveau: remove >1 sclass support from nouveau_parent_create_
It's unused (only one codepath passes sclass at all and it's always one),
broken (overwrites the same field, leaking previous one) and confusing.
Signed-off-by: Marcin Slusarz <marcin.slusarz at gmail.com>
---
drivers/gpu/drm/nouveau/core/core/client.c | 2 +-
drivers/gpu/drm/nouveau/core/core/parent.c | 3 +--
1999 Nov 23
1
postscript colors
Is color specification like this available in R for setting
postscript colors?
> hue <- c(0, seq(from = 0, by = 1/(nclass), length = nclass))
> sat <- c(0, rep(1.0, nclass))
> bri <- c(0, rep(1.0, nclass))
> zcolors <- cbind(hue, sat, bri)
> ps.options (setcolor=ps.setcolor.hsb,colors=zcolors)