similar to: Splitting Data Frame into Two Based on Source Array

Dear all, I found that printing with 'cat' is very slow. For example in my machine this snippet __BEGIN__ # I need to resolve to use this type of loop. # because using write(), I need to create a matrix which # consumes so much memory. Note that "foo, bar, qux" object # is already very large (>2Gb) for ( s in 1:length(x) ) {

I have the following list of strings: x <- c("foo, foo2, foo3", "bar", "qux, qux1") what I want to do is to obtain foo, bar qux Namely for each element in the vector obtain only string before the first comma. What's the way to do it? - G.V. [[alternative HTML version deleted]]

Hi R Developers, Greg is helping me with debugging R on Solaris 10 x64. Please let us know if you have any thoughts or tips that can help us debug this. Thanks, David ************ Using default transfer plist in vector_io: permuting About to write *** caught segfault *** address e8554000, cause 'memory not mapped' Traceback: 1: .External("do_hdf5save", call,

> Hi, Check if the shared directory has the write permission for all. i.e. chmod 777 for the particular directory > Date: Sun, 19 Sep 1999 21:06:36 -0700 > From: Kenny Cho <Kenny.Cho@Corp.Sun.COM> > To: samba@samba.org > Subject: Problem copying files to samba mount. > Message-ID: <37E5B2CC.9ADC9F8A@ha1pal.corp.sun.com> > MIME-Version: 1.0 >

Hi all, Suppose I have 2 matrices A and B. And I want to measure how good each of this matrix is. So I intend to compare A and B with another "gold standard" matrix X. Meaning the more similar a matrix to X the better it is. What is the common way in R to measure matrix similarity (ie. A vs X, and B vs X) ? - Gundala Viswanath Jakarta - Indonesia

Dear all, I tried to find index in repo given a query with this: > repo <- c("AAA", "AAT", "AAC", "AAG", "ATA", "ATT") > qr <- c("AAC", "ATT", "ATT") > which(repo%in%qr) [1] 3 6 Note that the query contain repeating elements, yet the output of which only returns unique. How can I make it

Hi, I have the following vector which is created from 3 distinct distribution (three components) of gamma: x=c(rgamma(30,shape=.2,scale=14),rgamma(30,shape=12,scale=10),rgamma(30,shape=5,scale=6)) I want to plot the density curve of X, in a way that it shows a distinct 3 curves that represent each component. How can I do that? I tried this but doesn't work: lines(density(x)) Please

Dear all, I have the following matrix. > dat A A A A A A A A A A [1,] 0 0 0 0 0 0 0 0 0 0 [2,] 0 0 0 0 0 0 0 0 0 1 [3,] 0 0 0 0 0 0 0 0 0 2 How can I change it into: [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [1,] 0 0 0 0 0 0 0 0 0 0 [2,] 0 0 0 0 0 0 0 0 0 1

Hello, This is a proposal for implementing "module flags". Please take a look at this and give any feedback you may have. Thanks! -bw Module Flags Metadata Information about the module as a whole is difficult to convey to LLVM's subsystems. The LLVM IR isn't sufficient to transmit this information. One should instead use the llvm.module.flags named

Dear list, I get the following message while computing truehist in R 1.4.1 on Redhat Linux 7.1: > truehist(lsk$Pox, nbins = "FD" , prob = TRUE, xlab = "Pox [mmol/kg]") Error in switch(casefold(nbins), scott = nclass.scott(data), "freedman-diaconis" = , : couldn't find function "nclass.fd" Maybe the "nclass.fd" should be

Hi, I have the following (M x N) matrix, where M = 10 and N =2 What I intend to do is to group index of (M) based on this condition of "x_mn" , namely For each M, If x_m1 > x_m2, assign index of M to Group1 otherwise assign index of M into Group 2 > x [,1] [,2] [1,] 4.482909e-01 0.55170907 [2,] 9.479594e-01 0.05204063 [3,] 8.923553e-01 0.10764474

Dear R community, I have a question concerning recoding of a variable. I have a data set in which there is a variable devoted to the ISCO code describing the occupation of this certain individual (http://www.ilo.org/public/english/bureau/stat/isco/isco88/major.htm). Every type of occupation begins with a number and every number added to this number describes th occupation more detailed. Now my

Hi, How can I extract the label only from a given data frame. Fore example from this data frame. > print(dataf) V1 V2 V3 V4 V5 V6 V7 V8 V9 11145 14.3 17.1 31.2 41.7 45.8 49.8 68.6 70.6 72.9 3545 10.2 15.6 20.9 23.2 31.4 31.7 36.2 48.4 51.9 8951 15.2 17.5 20.0 21.4 32.4

Hi all, The patch below is to fix a problem with unaligned memcpys. This program: void Bork() { int Qux[33] = {0}; } will currently produce this LLVM code on PPC64: @C.0.937 = internal constant [33 x i8] zeroinitializer define void @Bork() { entry: %Qux = alloca [33 x i8] %Qux1 = bitcast [33 x i8]* %Qux to i8* call void @llvm.memcpy.i64( i8* %Qux1, i8* getelementptr ([33 x i8]*

1. Same question as David, why &c - 8 is invalid? Is it related to below statements In C99 standard? 6.5.3.3: "Among the invalid values for dereferencing a pointer by the unary * operator are a null pointer, an address inappropriately aligned for the type of object pointed to, and the address of an object after the end of its lifetime." 2. We are trying to preserve 1st load and

Dear R users, I'm new of the R, I really don't know much. I want classification some data (two class, many features and huge size of data) by using R. At this case, I want using Support Vector Machine, Bayes theory based classifier, Discriminant Analysis, Regression based at least. Which package should I using, and can I compare each classifier result by predictions? Thank you.

On 05/12/2019 11:00 a.m., Johann R. Kleinbub wrote: > It's been three months without an answer, is it ok to thread bump? > Would someone provide a pointer? I agree it's a bug, and agree with your analysis. You should report it on bugs.r-project.org. (If you don't have an account there, let us know, and either someone will give you one, or someone will report it for you.)

https://bugzilla.netfilter.org/show_bug.cgi?id=1206 Bug ID: 1206 Summary: segfault when snat map rule has been added Product: nftables Version: unspecified Hardware: x86_64 OS: Ubuntu Status: NEW Severity: normal Priority: P5 Component: nft Assignee: pablo at netfilter.org

Hi, I have the following data that looks like this: > names(dat) [1] "(-2329,-2319]" "(-1399,-1389]" "(-669.4,-659.4]" How can I modify those names into just this? [1] -2329 -1399 -669.4 - Gundala Viswanath Jakarta - Indonesia

Hi all, This patch is to fix a problem on PPC64 where an unaligned memcpy is generated. The testcase is this: $ cat testcase.c void Qux() { char Bar[11] = {0}; } What happens is that we produce LLVM code like this: call void @llvm.memcpy.i64( i8* %event_list2, i8* getelementptr ([11 x i8]* @C.103.30698, i32 0, i32 0), i64 11, i32 8 ) Notice that it has an 8-byte alignment. However, the Bar