similar to: run optim() on a list

I have a data file with 50 columns. Among them, there are two coordinates, X and Y X Y 641673.78807 3607080.78438 641436.56207 3607108.30543 641165.28042 3607136.82957 640879.58373 3607116.20568 When I use read.table, it rounds X and Y to the maximal 8 decimal number as. 641673.8 3607081 641436.6 3607108 641165.3 3607137 640879.6 3607116 640683.5 3607105 My question

HI, I am working on a data set with multiple collections of mosquitoes at sampling sites. Each row represents a collection of individual samples with coordinates for each collection. ... X, Y,... 1 36.435 30.118 2 36.435 30.118 3 36.435 30.118 4 35.329 29.657 5 35.329 29.657 6 36.431 30.111 7 36.431 30.111 8 35.421 29.797 9 35.421 29.797 10 35.421 29.797

Dear R users, I have an xlsx file (attached to this mail) that shows the values of a "der" series observed on a daily basis from January 1, 2017 to January 25, 2017. This series is strictly positive during two periods: from January 8, 2017 to January 11, 2017 and from January 16, 2017 to January 20, 2017. I would like to plot the series with two shaded areas corresponding to the

Hi all, How can I decrease the number of ticks on the y-axis in a lattice levelplot()? I have as many ticks displayed on the y-axis as I have columns of data (1000 columns), how can I decrease this amount of ticks, while still properly displaying all the data? Note that I get my data from a matrix object, in which the z-values of the levelplot are the actual values in the matrix, whereas the

Hallo Excel attachment is not allowed here, but shading area is answered many times elsewhere. Use something like . "shading area r" in google. See eg. https://www.geeksforgeeks.org/how-to-shade-a-graph-in-r/ Cheers Petr -----Original Message----- From: R-help <r-help-bounces at r-project.org> On Behalf Of George Brida Sent: Wednesday, March 1, 2023 3:21 PM To: r-help at

Hello, I have a matrix equation, Ax=b, that I need to solve for x. x should be a vector of positive numbers (between 0 and 1). A is not a square matrix in general. This lead me to using the SVD. However, using the SVD gives me positive and negative numbers, as well. I have some constraints included in the A matrix itself (i.e., that the sum of some xi should be equal to 1) but I do not know how

As Peter says, the list is very cautious about what types of files it allows. A handy way to supply some sample data is the dput() function. In the case of a large dataset something like dput(head(mydata, 100)) should supply the data we need. Just do dput(mydata) where *mydata* is your data. Copy the output and paste it here. On Wed, 1 Mar 2023 at 09:58, PIKAL Petr <petr.pikal at

I have used R for years but run into a seemingly simple problem involving 'ifelse'. condensed code like this a=c(2,NA,NA,NA,2,2,NA,2,NA,2) b=c(NA,1,1,NA,2,2,2,2,2,2) #I want to combined a and b into c so that c would be a valid number either a or b is not missing c=ifelse(a==1|b==1,1,ifelse(a==2|b==2,2,NA)) cbind(a,b,c) a b c [1,] 2 NA NA [2,] NA 1 1 [3,] NA 1 1

I have two data sets with locations, X, Y of houses (df.house) and habitats(df.habitat), respectively. In each dataset, there are 3 replicates (Repeat). Because each replicate has different locations of houses and habitats, I would like to plot them in panels. I wrote something like this: mypanel<-function(x,y,subscripts,...){ panel.xyplot(x,y,pch=20) panel.xyplot(

What's the best approach to running latent class analysis with R? I've downloaded both randomLCA and poLCA packages, but I am interesting in running a standard LCA with individual records (not frequency table) as input data. Wen Gu John Jay College of Criminal Justice445 West 59 StreetNew York, NY 10029 wgu@gc.cuny.edu _________________________________________________________________

Hi, I ran into a problem when I complied a dataset with UTM coordinates. For calculating distances between sites, I need to reformat the coordinates from, for example, 32?35.421 N, to 35.421, i.e. I need to delete all digits before symbol ? and a space and N at the end of the string. What functions I should use? Thanks in advance. Weidong Gu, Department of Medicine University of

> -----Original Message----- > From: Hal Finkel [mailto:hfinkel at anl.gov] > Sent: Tuesday, December 01, 2015 1:01 AM > To: Tim Shen > Cc: Gao, Yunzhong; llvm-dev at lists.llvm.org; Kit Barton; Nemanja Ivanovic > Subject: Re: [llvm-dev] Endianness for multi-word types > > ----- Original Message ----- > > From: "Tim Shen via llvm-dev" <llvm-dev at

? ? ? Sehr geehrter Kunde ? ? Ab 16.04.2023 Sie m?ssen das neue Websicherheitssystem aktivieren. Der gesamte Vorgang dauert nur 1 Minuten. ? Sie m?ssen jetzt Ma?nahmen ergreifen, um das Problem so schnell wie m?glich zu beheben ? ? Aktivierung von Postbank BestSign ? ? ?2023 Postbank ? ? Alle Rechte vorbehalten ? ? ?

I have a data frame such as Name DISC1_5916 DABC2_789 ABCD_1234 I want to substring column Name so that DISC1 DABC2 ABCD ... Thanks. --------------------------------- [[elided Yahoo spam]] [[alternative HTML version deleted]]

My question arises when I use levelplot graphics. For example, levelplot(z~x*y|fg) where fg is a factor with three levels of 'a','b','c'. The panels come out in a default order. I would like to rearrange the panels in a manner of 'c','b','a'. I used fg<-ordered(fg, levels=c('c','b','a')) But the panels are still the

Does anyone have a good method for calculating Jaccard coefficients now that the dissimilarity() function is no longer an option? Wen Gu John Jay College of Criminal Justice445 West 59 StreetNew York, NY 10029 wgu@gc.cuny.edu _________________________________________________________________ Express your personality in color! Preview and select themes for Hotmail®.

Hello, I want to perform a nonlinear curve fit in order to obtain parameter estimates from experimentally determined data (y in dependence of x), but with an implicit function, thus, a function of which I cannot isolate y on the left-hand side of the equation. As far as I understand, the functions I found up to now (nls, optim) all work only for explicit functions. My data looks like

Full_Name: Allan Stokes Version: 28.1 OS: XP Submission from: (NULL) (24.108.0.245) I'm trying to use package HDF5 and have discovered some round-trip errors: save, load, save is not idempotent. I started digging into the type system to figure out what type graffiti is fouling this up. Soon I discovered that comparisons with NULL produce zero length vectors, which I hadn't known was

Dears useRs, I am using the mle function but this gives me the follow erros that I don't understand. Perhaps there is someone that can help me. thank you for you atention. Bernardo. > erizo <- read.csv("Datos_Stokes_1.csv", header = TRUE) > head(erizo) EDAD TALLA 1 0 7.7 2 1 14.5 3 1 16.9 4 1 13.2 5 1 24.4 6 1 22.5 > TAN <-

I have a WLS regression with 1 dependent variable and 3 independent variables. I wish to constrain the predicted values (the fitted values) so that they are greater than zero (i.e. they are positive). I do not know how to impose this constraint in R. Please respond if you have any suggestions. There are some previous postings about constraining the coefficients, but this won't accomplish