similar to: Lowest k values of list

I have a list of data frames like this: a<- data.frame(x=runif(10), y = runif(10), Acc = 1) b<- data.frame(x=runif(10), y = runif(10), Acc = 0) ls<- list(a,b) and I want to remove the data frames from ls that have Acc values other than 1. How do I do that? Thanks for any help! Matthew

Say I have: > set.seed( 1 ) > m <- matrix( runif(5^2), nrow=5, dimnames = list( c("A","B","C","D","E"), > c("O","P","Q","R","S") ) ) > m O P Q R S A 0.2655087 0.89838968 0.2059746 0.4976992 0.9347052 B 0.3721239 0.94467527 0.1765568

Dear R community! I am trying to create a heatmap based on the following data. As you can see the diagonal (0,0 to 10,10) is always 0). If I run the heatmap command like i posted it I get a graph with horizontal lines. What is my mistake? > heatmap(activity.matrix, Rowv = NA, Colv = NA, scale="column", xlab="x Compounds", ylab="y Compounds",

Hi all, I have two columns of data, the first consists of parameter estimates and the second probability estimates. I would like to extract the value from the first column based on the max value of column two, but not sure how to do this other than by extracting the value and then manually finding the value in the first column. Anyone know how to do this? Basically, I need to find the row

Hi, I want to generate a number of vectors and store them with different names, like this: x=1 while (x<100) { vector#x# = rnorm(100) x=x+1 } where each vector has, at its hand, instead of #x# a number which goes from 1 to 99. How can I do this? Thanks Gabriele Zoppoli, MD Ph.D. Fellow, Experimental and Clinical Oncology and Hematology, University of Genova, Genova, Italy Guest

Dear R Users, I have a data frame of 4 columns and ~58000 rows, the top of which looks like this: > head(max_out) Latitude Longitude Model Obs 1 -0.25 -49.25 4 4 2 -0.25 -50.25 4 5 3 -0.25 -50.75 4 4 4 -0.25 -51.25 3 11 5 -0.25 -51.75 6 4 6 -0.25 -52.25 12 5 The above shows, for each coordinate point, the

Hello, My question sounds simple, but as I am desperatly searchin for a solution I am asking you all. :) I try to filter out all non-numeric columns of a data frame using a for loop to go through all columns. My if clause looks like this:         for(j in 1:length(data)) {                 ...                 if(!is.numeric(data[j])) skip <- "not numeric")                 ...

Hi community, I want to count the occurrence of values within a dataframe. data$names is a list of many names. With namelist <- unique(data$names) I get all the existing names. But the result is a factor, not a list of strings. I would then like to go trough all the names in a for-loop and count their occurrence. How do I make this? Best regards, Markus

Hi everyone! I have an array containing the following fields for over hundred compounds: cpd, activity, fixterm, energy1, energy2, energy3, ... I want to run a multiple linear regression on all entries of an array. Therefore I tried to do this with a for loop. (Maybe there is a direct way of calculating it using apply, but I don't know that either.) Actually i tried the following code:

Hi Elaine I do not use it very often. I programmed it to mimic Minitab functions (partly) with some adons from czech statistics textbook written by M.Meloun (meloun militky statistics - first hit in google) Basically you can have your data in some data frame or they can be as separated vectors. The function itself expects input of 3 vectors, but you can easily to modify it for imput as

Dear list members. I have problems with the usage of cv.glm from the boot package. Here are some parts of the script I wanted to use: data <- read.table("selected_2D.csv", header=TRUE, sep=",") ? glm.fitted <- glm("ydata$ y ~ 1 + density + vsurf_ID6 + vsurf_S ", data=data) error <- cv.glm(data=data, glm.fitted, K=6) ydata$y is a separate data set, where

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When preparing a series of histograms I found that hist was combining the two lowest categories or bins, 1 and 2. Specifying breaks, as illustrated below, resulted in the correct histogram: values <- sample(10,500,replace=TRUE) hist(values) hist(values,breaks = 0:10) Apparently, the number of values strictly less than 1 is shown in the first bin (and since none is less than 1,

I am using a similar dataset to the following: a= c("Fruits", "Adam","errorA", "steve", "errorS", "apples", 17.1,2.22, 3.2,1.1, "oranges", 3.1,2.55, 18.1,3.2 ) a_table=data.matrix(t(matrix(a,nrow=5))) I would like to highlight the smallest value in the Adam and Steve columns and, also plus and minus the errors

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Just a quick question. What is the lowest possible bit rate for encoding in stereo in opus? Peter

http://bugzilla.mindrot.org/show_bug.cgi?id=255 Summary: You must "exec" login from the lowest login shell. Product: Portable OpenSSH Version: -current Platform: PPC OS/Version: AIX Status: NEW Severity: normal Priority: P2 Component: sshd AssignedTo: openssh-unix-dev at mindrot.org

http://bugzilla.mindrot.org/show_bug.cgi?id=255 ------- Additional Comments From dmanton at emea.att.com 2002-05-22 20:06 ------- Created an attachment (id=100) sshd -d -d -d ------- You are receiving this mail because: ------- You are the assignee for the bug, or are watching the assignee.

http://bugzilla.mindrot.org/show_bug.cgi?id=255 stevesk at pobox.com changed: What |Removed |Added ---------------------------------------------------------------------------- Status|NEW |RESOLVED Resolution| |FIXED ------- Additional Comments From stevesk at pobox.com 2002-06-23 04:51

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