similar to: how to draw the legend about color from 3d picture

Hello all, I am trying to use computer modern fonts in my r grahics. I tried to do, as described here: http://www.stat.auckland.ac.nz/~paul/R/CM/CMR.html but unfortunately, it does not work. First of all I downloaded the cm-lgc package and the AFM and PFB-files from the page and put them in my R working directory, so far, so good. Then I tried to run the following code: > sn <-

Dear list, sorry to waste your time. I downloaded R and I like it very much. However, my main interest is in plotting 3D graphics form imported data (points and lines in a 3d space). I imported data in a very elegant way but I wasn't able to find in R something similar to the simple "splot" function of WGNUplot (I don't need persp, image, contour: my values are not

Hi, I want to format my axis in my persp3d plot. With my data, which I attached I created a persp3d plot with the following code, which I summarized from different code snippets I found: library(rugarch)library(rgl)library(fGarch)fd <-as.data.frame(modelfit,which ='density')color <-rgb(85,141,85,maxColorValue=255)x <-seq(-0.2,0.2,length=100)y <-c(1:2318)f

Hi All- I would like to create a 3d topographic map using lat/lon and z(height). I have been scouring the R help pages and have not located the package I am looking for. Does anyone have a suggestion of package that will work for this? thanks- sherri

Hi, I'm unable to find a way to smooth data for a persp() graph. Example, suppose that I have data x,y,z like this: x <- 1:10 y <- 1:10 k <- 20 z <- outer(x, y, "*") + matrix( k*runif(100, -1, 1), 10, 10) persp(x, y, z, theta = 35, phi = 25) The graph is not very nice. Is there a way to smooth the z data so that at the end the graph would look more like something

Hi everyone, I have a vector with atmospheric measurements (x-axis) that is obtained/calculated at different altitudes (y-axis). The altitude is uniformly distributed every 7 meters. For example my dataframe is: df <- dataframe( *altitude* = c(1005, 1012, 1019, 1026, 1033, 1040, 1047, 1054, 1061, 1068), *atm_values* = c(1.41, 1.40, 1.39, 1.38, 1.37, 1.37, 1.38, 1.36, 1.33, 1.31)

Try something like with(df, predict(smooth.spline(x = altitude, y = atm_values), deriv = 1)) Cheers, Andrew -- Andrew Robinson Chief Executive Officer, CEBRA and Professor of Biosecurity, School/s of BioSciences and Mathematics & Statistics University of Melbourne, VIC 3010 Australia Tel: (+61) 0403 138 955 Email: apro at unimelb.edu.au Website: https://researchers.ms.unimelb.edu.au/~apro

Hi Konstantinos Not exactly derivative but > diff(df[,2]) [1] -0.01 -0.01 -0.01 -0.01 0.00 0.01 -0.02 -0.03 -0.02 May be enaough for you. Cheers Petr > > -----Original Message----- > From: R-help <r-help-bounces at r-project.org> On Behalf Of konstantinos > christodoulou > Sent: Tuesday, January 31, 2023 10:16 AM > To: r-help mailing list <r-help at

Hi, When R generates density plots and these are exported to postscript( a=matrix(1:100,10,10);image(a,col=rainbow(100);dev.copy2eps(file="image.eps") ) The result often looks bad when rendered on screen. The help page states that this is because programs use anti-aliasing. That seems to be true - turning off anti-aliasing for gs (-dGraphicsAlphaBits=1) of in OSX's preview makes

I have multiple conditions that I would like to plot in a grid. To save space, I don't need the ticks, labels etc on the plots which are not on the outside. I tried split.screen, but if it is clearer to use, it seems pretty rigid since it decides of each screen size apriori while I need more space for the left column and top or bottom row screens than for the other plots. axis(1,tick=FALSE)

Dear R users, I face to a nested pattern and despite the numerous examples in the help I am still confused. I sampled bugs in different habitats within sites which were within rivers themselves within different regions. The habitat correspond to different substrata (not systematically present in all sites). For rivers and sites, I have environemental variables (e.g. altitude and slope of

Dear list, I want to make a plot based on the following information, using the command plot. variable A for x axis : temperature (range: -20 degrees to 40 degree) variable B for y axis : altitude (range: 50 m to 2500 m ) The data below 0 degree of X variable wants to be erased tentatively. Please kindly advise the command to extract the data ranging from 0 degree to 40 degrees. Thank

Hi there, I have two data sets, one of locations at different elevations (x,y,z) and the other of points that make up topographic contours (also x,y,z). I have used: result<-apply(distppll(data2,cbind(topocon[-nrow(topocon),],topocon[-1,])),1,min) where 'data2' are my measurement coordinates (x, y) and 'topocon' are my topographic contours (x,y). While this gives me an output

Hi all, Discussions about a need for an extension to Skeleton to cater for multi-track media files has been going on for a while. In a recent thread here, in discussions on IRC, and at FOMS between Jan, Ralph, Viktor and I, we discussed some fields. Viktor and I continued that discussion to make more specific recommendations on what fields to add. We now have a wiki page at

Hi everyone, Can anyone tell me if its possibility to extract the coefficients from the lm() command? For instance, imagine that we have the following data set (the number of observations for each company is actually larger than the one showed...): Company Y X1 X2 1 y_1 x1_1 x2_1 1 y_2 x1_2 x2_2 1 y_3 x1_3 x2_3 (...) 2 y_4 x1_4 x2_4 2 y_5 x1_5 x2_5 2 y_6 x1_6 x2_6 (...) n y_n x1_n x2_n n

Hello I am trying to draw a basic black and white map of two European countries. After searching some key words in google and reading many pages I arrived to the conclusion that persp() could be used to draw that map. I have prepared three small example files, which are supposed to be the files required for running that function. xvector is a vector with the longitudes yvector is a vector with

Tengo una consulta, alguien tiene algun script en R para hacer graficos de anomalias estandarizadas (precipitacion, temperatura, etc) y que me permita pintar de rojo anomalias positivas y azules las negativas, ​Muchas gracias de antemano​ -- Luis Alfonso LOPEZ ALVAREZ MSc- Meteorologia - Ing. Sistemas PROFESIONAL ESPECIALIZADO (E) METEOROLOGO - IDEAM e-mail: llopez@ideam.gov.co

Dear listers, I have written a function to facilitate the drawing of altitude profiles with x (distance), y (altitude) and a z parameter (altitude magnification). profplot<-function(x,y,z=10,...){ op <- par()$mai par(mai=c(0.95625,0.76875,0.76875,0.95625)) plot(x,y*z, type="l",asp=1,las=1,xlab="",ylab="",yaxt="n",...)

Hi, The script below is my current coding in order to produce a contour plot of temperature across altitude and time. In my case,?time,altitude and temperature?are represented by x, y and z variables. ############################################## Brazilan.Pallete <- colorRampPalette(c("blue","green","yellow","red")) image.plot(x, y, z, col =

I tried the following ordered logistic regression in R: mod1 <- polr(altitude~sp + wind_dir + wind_speed + hr, data=altioot) But when I asked The summary of my regression I got the folloing error message: > summary (mod1) Re-fitting to get Hessian Error in optim(start, fmin, gmin, method = "BFGS", hessian = Hess, ...) : the initial value of 'vmin' is not