Displaying 20 results from an estimated 2000 matches similar to: "using complete.cases() with nested factors"
2010 May 18
2
Function that is giving me a headache- any help appreciated (automatic read )
note: whole function is below- I am sure I am doing something silly.
when I use it like USGS(input="precipitation") it is choking on the
precip.1 <- subset(DF, precipitation!="NA")
b <- ddply(precip.1$precipitation, .(precip.1$gauge_name), cumsum)
DF.precip <- precip.1
DF.precip$precipitation <- b$.data
part, but runs fine outside of the function:
days=7
2010 Oct 19
1
Problems with a specific calculate.
Hello friends of R,
My name is Toni, i'm 25 and I'm working on the Meteorological Investigation team from Balearic Islands.
I had contact to you because I have a problem:
I done a file for every day since 1912 about precipitation. That file has the following structure:
> str(Ast)
Loading required package: sp
Formal class 'SpatialPixelsDataFrame' [package "sp"]
2012 Oct 04
3
R combining vectors into a data frame but without a continuous common variable
Hello,
I have two different files which I'd like to combine to make one data frame
but I've no idea how to do it! The first file has two columns; one is the
date, the following is a binary code for debris flow events. Then my other
file has also two columns; the date and then precipitation data.
The thing is, is that the two date columns don't all contain the same dates.
The binary
2011 Feb 17
3
summing 15 minute precip data to daily
Hi all,
i'm sure there is an easy way to do this, but i'm stumped, so any help would
be appreciated.
i have a single column of data for precipitation every 15 minutes over a
year. i want to sum the precip to daily data.
so the first 96 records = the first day, the second 96 records = the second
day, and so on....
is there a way to write a for loop that would sum the data to daily, and
2013 Apr 18
1
Arranging two different types of ggplot2 plots with axes lined up
Hi all,
I want to arrange two ggplot2 plots on the same page with their x-axes
lined up - even though one is a boxplot and the other is a line plot. Is
there a simple way to do this? I know I could do this using facetting if
they were both the same type of plot (for example, if they were both
boxplots), but I haven't been able to figure it out for two different types
of plots.
Below is my
2007 Sep 10
1
overlay lattice histograms with goodness-of-fit pdfs
Hello,
I am new to R exploratory data analysis and plotting. Is anyone aware of a way
to overlay a set of conditional histograms with conditional PDFs? Below, I
generate a lattice plot of precipitation histograms based on different months
and stations, given a subset of the dataset:
histogram(~ data | month * station,
data = sta.stack[sta.stack[,"type"]=="precip" &
2011 Mar 13
4
readMat - how to retrieve the variables
Hello
I have a matlab MAT file that contains one single variable: a. The
structure of a is as follows:
a.river1.flow (flow values)
a.river1.date_flow (date)
a.river1.precip (precipitation values)
a.river1.date_precip
a.river2.flow
a.river2.date_flow
a.river2.precip
a.river2.date_precip
I have used readMat to load the variable a in R, however I have no idea how
readMat translates a. I managed
2009 Oct 06
1
ggplot2 applying a function based on facet
Look at the bottom of the message for my question
#here is a little function that I wrote
USGS <- function(input="discharge", days=7){
library(chron)
library(gsubfn)
#021973269 is the Waynesboro Gauge on the Savannah River Proper (SRS)
#02102908 is the Flat Creek Gauge (ftbrfcms)
#02133500 is the Drowning Creek (ftbrbmcm)
#02341800 is the Upatoi Creek Near Columbus (ftbn)
#02342500 is
2010 Nov 17
3
stacking consecutive columns
I have a file, each column of which is a separate year, and each row of each column is mean precipitation for that month. Looks like this (except it goes back to 1964).
month X2000 X2001 X2002 X2003 X2004 X2005 X2006 X2007 X2008 X2009
1 1.600 1.010 4.320 2.110 0.925 3.275 3.460 0.675 1.315 2.920
2 2.960 3.905 3.230 2.380 2.720 1.880 2.430 1.380
2006 Nov 20
2
problem with loop to put data into array with missing data for some files
Dear R-help community,
My main goal of this message is to find a way of skipping a file of a month/year
in a loop that does not exist (and making it's output into an data.out array
would be NA) and moving onto the next year/month in the loop to carry on filling
data.out with real precipitation data.
The situation so far:
I downloaded 50 years worth of GRIB data files from the NCEP data
2006 Nov 20
3
problem with loop to put data into array with missing data forsome files
Hi Jenny
If you want a general solution I understand.
However I just downloaded the file fine (as far as I can tell) so you
are welcome to have a copy. I can email it to you if you want.
I do not think your test for NA is valid. i.e
if(test != "NA"){
}
I think you should use
if(is.na(test)){
}
Or something similar.
J
---
John Seers
Institute of Food Research
Norwich
2012 Jul 14
2
Loading in Large Dataset + variables via loop
Hello, I'm new to R with a (probably elementary) question.
Suppose I have a dataset called /A/ with /n/ locations, and each location
contains within it 3 time series of different variables (all of 100 years
length); each time series is of a weather variable (for each location there
is a temperature, precipitation, and pressure). For instance, location 1
has a temperature1 time series, a
2009 Jan 22
1
reshape() problems
Hi
I have a data frame with timeseries information like this:
year cell Q1 Q2 Q3 Q4
1940 1 1.2 1.4 1.4 1.9
1941 1 2.9 2.1 3.4 2.4
1942 1 2.7 3.2 1.5 2.6
1940 2 1.4 2.1 2.6 2.4
1941 2 2.4 1.4 1.4 3.4
1942 2 1.4 2.4 2.5 4.4
where the Qs mean 'quarter'. I want to extract from
2010 Oct 06
3
Assigning value to a vector from within a function
Hi all,
I am having trouble assigning a value within a vector using a variable
defined within a function. I suspect this has something to do with
namespaces but I cannot figure it out. Please reply directly to me if you
can help.
###begin code
#simple vector
test<-c(4,5,6)
#simple function to get a value from a vector
#works just like I would expect, has no problem indexing using the local
2008 Nov 04
1
perform Kruskal-Wallis test without using the built-in command in R
Hi,
again i am stuck in my presentation, and i have never learn R before in my
life but need this to be done, so please help me out for a favour:
http://www.nabble.com/file/p20333155/kew.dat kew.dat
run this in R and these comes up:
Month Year Rain
1 Jan 1900 74.400000
2 Feb 1900 80.500000
3 Mar 1900 23.600000
4 Apr 1900 23.600000
5 May 1900 25.100000
6
2005 Feb 02
4
(no subject)
can you recommend a good manual for R that starts with a data set and gives
demonstrations on what can be done using R? I downloadedR Langauage
definition and An introduction to R but haven't found them overly useful.
I'd really like to be able to follow some tutorials using a dataset or many
datasets. The datasets I have available on R are
Data sets in package 'datasets':
2010 Jun 06
2
Color scale graphic
Hello
Recently, I've been dealing with a seemingly simple problem. I have a table
with two columns filled with values from a test I made (say, amount of
precipitation and Months measured). Now, instead of plotting a typical
linear graphic with precipitation on the y-axis and the months in the
x-axys, I would like to "convert" the values of precipitation in a color
gradient,
2003 Sep 29
4
Data frame transpose
Hi All,
I want to ask if there is a transpose function for data frame like the
procedure of transpose in SAS? Because I want to partially transpose a
data frame which contains 5 columns (siteid, date, time, obs, mod), what
I want to do is to put time as the column variables along with siteid,
and date, and put obs and mod in the row names. specifically to
transpose a data frame:
siteid date
2007 May 24
6
Sum per hour
Dear all,
I have a list of precipitation record and a list of time
I would like to sum them up per hour, or per day.
Does such a function exist ?
example:
time<-c("2000-10-03 14:00:00","2000-10-03 14:10:00","2000-10-03
14:20:00","2000-10-03 15:30:00","2000-10-03 16:40:00","2000-10-03
16:50:00","2000-10-03
2013 Feb 23
1
Extract, sum and Loop in R
Hi all,
I have gone through some basics of R in eclipse environment. What I need to
work is more than basic level so I could not find out the solution by
myself. could anyone help me ?
My case,
I have climate data (precipitation) in nc format with single layer for each
time interval in a day. That means for January 1, 2013, I have 8 separate
files each containing 3 hrs cumulative precipitation