similar to: printing name of object inside lapply

Dear list, I have a data file which includes, alongside various variables representing questionnaire scores, a variable for survey weights computed as the number of observations in the sample drawn from that group divided by the number of observations in the population in the group. I need to calculate a covariance matrix of the questionnaire scores for use in sem. How do I apply the weights?

Hi list members Any easy way to get standardized cronbach's alpha for a scale, as in SPSS? Thanks Steve Powell proMENTE social research research | evaluation | training & consulting Kranj?evi?eva 35, 71000 Sarajevo mobile: +387 61 215 997 | office: +387 33 556 865 | fax: +387 33 556 866 Checked by AVG Free Edition. 17:44

Dear list members, In sem, std.coef() will give me standardized coefficients from a sem model. But is there a trick so that path.diagram can use these coefficients rather than unstandardized ones? Thanks Steve Powell From: John Fox <jfox_at_mcmaster.ca> Date: Wed 28 Feb 2007 - 14:37:22 GMT Dear Tim, See ?standardized.coefficients (after loading the sem package). Regards, John John

Hi, Is it possible to assign a separate colour for comments written with #, eg:- #this is a comment . I am looking to colour them differently from the program text in R-Editor (not console). Is it possible to do so? Eg. In Visual basic, the colour for remarks gets green automatically Regards Sumit [[alternative HTML version deleted]]

hi list members I am trying to use odfWeave with R 2.5.1 on Windows XP. however when running e.g. odfWeave(demoFile, outputFile) I get: Error in odfWeave(demoFile, outputFile) : Error unzipping file In addition: Warning message: unzip not found in: system(zipCmd[2], invisible = TRUE) presumably my zip and unzip are not set up correctly but I dont know how to do that. I installed zip and

Dear list members I would like to apply a vector of labels v=c("lab1","lab2","lab3") to a dataframe df=data.frame(1:3,1:3,1:3) using some kind of loop or apply function. Any ideas? Thanks Steve Powell Checked by AVG Free Edition. 17:03 [[alternative HTML version deleted]]

Dear list members I am still a newbie so might be asking a stupid question, but I can't get ggplot to work in a loop (or a "while" statement for that matter). # to take a minimal example - mydata$varc = c(1,2,3) for (i in 1:1){ jpeg("test3.jpg") plot(mydata$varc) #ggplot(mydata, aes(x=mydata$varc)) + geom_bar() dev.off() } this produces

Dear expeRts, sorry for such a newbie question - in PCA/factor analysis e.g. in SPSS it is possible to save scores from the factors. Is it analogously possible to "save" the implied scores from the latent variables in a measurement model or structural model e.g. using the sem or lavaan packages, to use in further analyses? Best wishes Steve Powell www.promente.org | skype

Hi I have a list that has attributes: attributes(lis[2]) $names [1] "150096_at" I want to use those attributes in a function and then use lapply to apply that function to every element of the list, eg for simplicity's sake: my.fun <- function(x) { attributes(x) } Then l2 <- lapply(lis, my.fun) It seems that "attributes(x)" within the function is not the

I set up a local repo for testing packages. My packages are not showing up from the repository when viewed by Linux clients. I suspect this is a web administrator/firewall issue, but it could be I created the repo wrongly. I am supposed to run write_PACKAGES separately in each R-version folder. Right? Maybe other novices can use these scripts, if they are not wrong :) Here's the file

I have a list of data.frames, and i want to iterate over this list and generate graphs with the same title of the data.frame. I did the graphs with: lapply(anual, function(x) plot(x[,'chuva'], type='l', xlab= 'anos', ylab = 'Precicipatação(mm)', col='red')) where anual is list of data.frames. I am plotting just the column "chuva" at each

Hello, I'm having difficulty passing an object name to a lapply function. Can somebody tell me the trick to make this work? #Works T13702 <- TRACKDATA[["13702.xls"]][["data"]] min(unlist(lapply(list(T13702), function(x) mdy.date(x[1, 2], x[1, 1], x[1, 3])))) 16553 #Works d<-2 assign(paste("T",substr(names(TRACKDATA)[d],1,(nchar(names(TRACKDATA)[d]

I am tying myself in knots over subscripts when applied to lists I have a list along the lines of: lis<-list(c("a","b","next","want1","c"),c("d", "next", "want2", "a")) >From which I want to extract the values following "next" in each member of the list, i.e. something along the lines of

I'm writing to ask for a policy exception, or advice on how to make this package CRAN allowable. http://rweb.quant.ku.edu/kran/src/contrib/portableParallelSeeds_0.9.tar.gz Yesterday I tried to submit a package on CRAN and Dr Ripley pointed out that I had not understood the instructions about packages. Here's the part where the R check gives a Note * checking R code for possible

I have a vaiable named NAM having value : 1,2,3,4,5,6,7,8,9. I want to make an indicator variable that will take value 1 if NAM=7 or NAM=8 or NAM=9. How can I do that? I usually do: Var001<- ifelse(NAM==7,1,0) for the simplest case. [[alternative HTML version deleted]]

My understanding is that R will not make copies of lists if there is only one reference to the object. However, I've encountered a case where R does make copies, even though (I think) there should be only one reference to the object. I hope that someone could shed some light on why this is happening. I'll start with a simple example. Below, x is a list with one element, and changing that

Is there a simple way to calculate summary statistics for all the matrices or dataframes in a list? For example: > z <- list(matrix(c(2,2,2,2), ncol = 2), matrix(c(4,4,4,4), ncol = 2)) > z [[1]] [,1] [,2] [1,] 2 2 [2,] 2 2 [[2]] [,1] [,2] [1,] 4 4 [2,] 4 4 > I would like to calculate, for example, the mean value for each cell. I can do that the hard

Hi All? I was looking at a posting from June-17. I managed to solve it. However, when I changed the example in the posting, my solution will work only once at a time which was mentioned by Jim Lemon on his response to the original posting. This means that my solution will have to be repeated as many times as the maximum number of spaces on each gap; something that may not work well for large

Dear all,   i would like to count the number of times where I have combined occurrences of the categories of 2 variables.   For instance, in the dataframe below, i would like to know how many times each author (au1, au2, au3 represent the first, second, third author) is associated with each of the category of the variable 'nam'. The position of the author does not matter.   nam <-

Hello, I have a maybe trivial question, but I simply don't understand well enought how to work with text/strings: I have a rather compelx data structure, a big list with several sub-lists/dataframes and for certain calculations (which I do in loops), I only need a certain group of sub-lists/dataframes, which I want to specify with a name vector and paste together the object name and pass it