Displaying 20 results from an estimated 1000 matches similar to: "Plotting 3 way Anova"
2007 Apr 09
1
How to solve differential and integral equation using R?
Hello,
I want to know if there are some functions or packages to solve differential
and integral equation using R.
Thanks.
Shao chunxuan.
[[alternative HTML version deleted]]
2009 Mar 20
1
Is this sample size big enough to test for statistical significance?
Dear R community,
Is this sample size large enough to study differences between two groups of the populations?
Q1: do the body temperatures differ between the two groups of the overwintering turtles juveniles and adults?
One group (adults) has 6 turtles
Second group (juveniles) has 1 turtle.
There are 3 replications, i.e. the experiment was repeated over the three years, but using
2008 Sep 06
2
Hopefully an easy error bar question
Hi im trying to add error bars to my barplots, there very basic, i have a few grapghs where the y variable is different but on all the X variable is Age (Adult and Juvenile) however this is split into two levels so i have males and females, so my graph basically has four bars on it.
I know how to add eror bars for instance when there is only one level eg lookng at the diffrence between male and
2006 Dec 28
1
split-plot multiple comparisons
Dear R user,
I am new with split-plot designs and I have problems with multiple comparisons.
This data correspond to an split-plot experiment with two replications
(bloque).(Hoshmand, 2006 pp 138). Briefly, the whole-plot factor is
Nitrogen concentration ("nitrogeno") and the subplot factor is the variety
of corn ("hibrido"). The aim is to determine if major differences
2011 Mar 30
0
offset in gam
Hi, we are modelling dusky grouper distribution using underwater visual
census. Our response variable is the abundance of groupers but we want to
see differences in habitat related to maturity because dusky groupers use
different habitats when they're juveniles versus adults. So we're using the
% of maturity.
ie 1 individual that is 50cm TL gets aprox 0.5 (50% chances to be mature and
50%
2013 Jan 15
0
temporal and spatial correlation structures in GAMM
Dear R_help
list members!
I’m
studding forest carnivores and I have data on resting site selection and use!
I’m trying
to model the probability that a forest carnivore might have in be located in a
tree hollow (1) (the main resting site selected) rather than elsewhere (0)
(other resting site types, dens, nests, etc.).
The model
should be related with several variables such as for instance:
2016 Apr 26
5
Linear Regressions with constraint coefficients
Hi all,
I hope you are doing well?
I?m currently using the lm() function from the package stats to fit linear multifactor regressions.
Unfortunately, I didn?t yet find a way to fit linear multifactor regressions with constraint coefficients? I would like the slope coefficients to be all inside an interval, let?s say, between 0 and 1. Further, if possible, the slope coefficients should add up to
2009 Nov 16
5
Writing a data frame in an excel file
Hello, I am having trouble by using the write.table function to write a data
frame of 4 columns and 7530 rows. I don?t know if I should just use a
sep="\n" and change the .xls file into a .csv file. Thanks in advance
-----
Anna Lippel
new in R so be careful I should be asking a loooooooot of questions!:teeth:
--
View this message in context:
2016 Apr 26
1
Linear Regressions with constraint coefficients
If the slope coefficients sum to a constant, the regressors are
dependent and so a unique solution is impossible (an infinity of
solutions would result). So I think you have something going on that
you don't understand and should consult a local statistician to help
you formulate your problem appropriately.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people
2010 Feb 09
1
Interpretation of high order interaction terms.
I have difficulties in interpreting high order interaction terms in
high-way ANOVA.
According to Introductory Statistics with R by Peter Dalgaard (Section 12.5),
"The exact definition of the interaction terms and the interpretation of their
associated regression coefficients can be elusive. Some peculiar things
happen if an interaction term is present but one or more of the main
effects are
2004 Sep 02
3
Sample Rates
Hi there -
I am currently in the middle of a project where I need to configure an
Icecast Server and I am using Ices as the encoder. I want to configure Ices
to take in a stream with a sample rate of 128 kHz and output it to the
Icecast server. My question is, what are the minimum and maximum sample
rates that Ices will continue to work with?
Thank you,
Heidi Young
Software
2016 Apr 26
2
Linear Regressions with constraint coefficients
Ok, and if I would just like to force my slope coefficients to be inside an interval, let's say, between 0 and 1? Is there a way in R to formulate such a constraint regression?
Thanks in advance and kind regards,
Aljosa
Aljosa Aleksandrovic, FRM, CAIA
Quantitative Analyst - Convertibles
aljosa.aleksandrovic at man.com
Tel +41 55 417 7603
Man Investments (CH) AG
Huobstrasse 3 | 8808
2016 Apr 28
2
Linear Regressions with constraint coefficients
Hi Gabor,
Thanks a lot for your help!
I tried to implement your nonlinear least squares solver on my data set. I was just wondering about the argument start. If I would like to force all my coefficients to be inside an interval, let?s say, between 0 and 1, what kind of starting values are normally recommended for the start argument (e.g. Using a 4 factor model with b1, b2, b3 and b4, I tried
2009 Oct 07
2
Plotting 1 covariate, 3 factors
I'm interested in plotting a y with an x factor as the combination of 2
factors and colour with respect to a third, which the code below does with
interaction.plot(). However, this is because I redefine the x to be 1
factor. Is there a way of getting it to plot without redefining it, and
ideally to not join up the lines BETWEEN levels a and b, but just join those
between after and before for
2010 Mar 06
2
Plot interaction in multilevel model
I am trying to plot an interaction in a multilevel model. Here is some
sample data. In the following example, it is longitudinal (i.e., repeated
measures), so the outcome, score (at each of the three time points), is
nested within the individual. I am interested in the interaction between
gender and happiness predicting score.
id <- c(1,1,1,2,2,2,3,3,3)
age <-
2016 Apr 26
0
Linear Regressions with constraint coefficients
This is a quadratic programming problem that you can solve using
either a quadratic programming solver with constraints or a general
nonlinear solver with constraints. See
https://cran.r-project.org/web/views/Optimization.html
for more info on what is available.
Here is an example using a nonlinear least squares solver and
non-negative bound constraints. The constraint that the coefficients
sum
2008 Sep 02
2
Google Chrome - any luck, anyone?
This is the sum total of my results so far:
fun at heidi:~/download$ wine ChromeSetup.exe
fixme:ntoskrnl:KeInitializeSpinLock 0x457a04
fun at heidi:~/download$
No window opening or anything. This is on Kubuntu 8.04 with KDE 4.1.
- d.
2016 Apr 26
0
Linear Regressions with constraint coefficients
Have you tried web searching on " R constrained linear regression" or
similar. There seemed to be resources related to your issues when I
looked. You might also search on rseek.org . There are apparently
several packages that do regression with constraints, but I don't know
if they fit your situation.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that
2006 Jun 15
1
more function in R?
I'm an R newbie and I just have a simple question.
I'm using interactive R on a linux box and I'm trying to find out if there's
a more or a less function. The data I want to look at is larger then my
screen size and all I end up seeing is the last fews line of data. Is there
a way that I can paginate through the data and the results of my summary
functions?
thanks,
Heidi
2007 Mar 25
1
anova-interaction
HI,
I am trying to perform ANOVA with 2 factors:
material (3), temperature(3). The interaction is significant. I tried
something like, ( summary(avt, split=list("temp:mat"=list("15"=1,
"70"=2, "125"=3))) is not correct).
Thanks,
av <- aov(time ~ mat*temp, data=dados)
avt <- aov(time ~ temp/mat)
summary(avt,