Displaying 20 results from an estimated 100 matches similar to: "variance components"
2009 Jan 15
3
How to create a chromosome location map by locus ID
Hi,
I'm trying to make a chromosomal map in R by using the locus. I have a list
of genes and their locus, and I want to visualise that so you can see if
there are multiple genes on a specific place on a chromosome. A example of
what I more or less want is below:
http://www.nabble.com/file/p21474206/untitled.JPG untitled.JPG
The genes and locus are here:
2008 Dec 29
3
Normal Curve
Dear ALL:
How I show the area under the normal curve for example for the following example:
Assume X has N(100,15). How to show the area corresponding to the probability:
P(90<X<110)
With many thanks
Abou
==========================
AbouEl-Makarim Aboueissa, Ph.D.
Assistant Professor of Statistics
Department of Mathematics & Statistics
University of Southern Maine
96
2013 Nov 21
3
uso detach
Un saludo:
Estoy intentando con el comando "detach()" eliminar todos los archivos que durante la analíticas voy utilizando y "attached" al programa.
El problema es que usando detach () no me borra todo lo adjuntado. No sé si estoy usando mal el comando o estoy usando un comando incorrecto que no es para esto.
Gracias.
Juan Bautista Relloso Barrio
Técnico del Dpto
2023 Nov 21
1
Cambiar el intervalo de confianza en un anova
Gracias Carlos.
Yo también he visto el ejemplo que te pone chatGPT, pero la salida que te da no soy capaz de interpretarla.
Os paso las ordenes y las respuestas de R de la propuesta de chatGPT
Ejemplo.aov<- aov(P~TRAT+CORTE+REP)
> summary (Ejemplo.aov)
Df Sum Sq Mean Sq F value Pr(>F)
TRAT 6 0.0028 0.00046 0.777 0.590
CORTE 2 0.5022 0.25110 424.542 <2e-16
2023 Nov 21
1
Cambiar el intervalo de confianza en un anova
Buenas,
En R, como en la mayoría del software estadístico, no se utiliza ningún nivel de confianza sino que lo que se calcula es el p-valor asociado
al contraste. De forma que cuanto más cerca de 0 esté el p-valor "menos credibilidad le damos a la hipótesis nula". Dicho mejor, debemos
rechazar la hipótesis nula si el p-valor está por debajo de nuestro nivel de confianza.
Por ejemplo,
2012 Sep 20
1
Conectar Tinn-R con R versión 2.15
Hola a todos:
Preguntar si alguien sabe si se puede conectar el Tinn-R con la versión 2.15 de "R"
Yo lo he intentado y no lo consigo. si abro un script con el tinn-R no se me activan los botones para poder correr las lineas y que el resultado aparezca en la ventana de abajo de "R".
Vamos como pasaba con la versión 2.14
Sin más un saludo a todos y gracias por
2023 Mar 02
2
Realizar anovas, por cada uno de los niveles de uno de los factores del ensayo
Buenas tardes.
Tengo un ensayo de dos factores (Variedad y dosis)
Quisiera hacer anovas para cada una de las dos variedades que estoy evaluando.
Lo puedo hacer cogiendo los datos primero de una variedad y luego de la otra.
Pero creo que hay un comando "by variedad" que lo hace si necesidad de andar modificando el archivo de datos. Pero no sé dónde hay que colocarlo.
Si alguno me puede
2009 Jan 16
0
R-help Digest, Vol 71, Issue 16
On Fri, 16 Jan 2009, r-help-request at r-project.org wrote:
> Date: Thu, 15 Jan 2009 13:29:03 +0100
> From: Pablo G Goicoechea <pgoikoetxea at neiker.net>
> Subject: Re: [R] How to create a chromosome location map by locus ID
> To: Sake <tlep.nav.ekas at hccnet.nl>
> Cc: r-help at r-project.org
> Message-ID: <496F2C0F.3040304 at neiker.net>
> Content-Type:
2018 Feb 17
3
RV: no puedo cargar el paquete "agricolae"
Cada vez que intento cargar el paquete "agricolae" me da el siguiente mensaje:
Error: package or namespace load failed for 'agricolae' in loadNamespace(i, c(lib.loc, .libPaths()), versionCheck = vI[[i]]):
there is no package called 'spData'
He intentado todo actualizar los paquetes, volverlos a instalar pero no hay forma.
Si sabeis la solución ??
Un saludo.
Juan
2008 Jul 27
0
competing risk model with time dependent covariates under R or Splus
This message was also sent to the MEDSTATS mailing list, so here is the reply I posted to that:
Philippe,
The machinery to use is to split follow-up time so finely that you can safely assume that rates are constant in each interval, and then just stuff it all into a Poisson model. This allows you to use any kind of time-dependent variables as well as accommodating competing risks.
In the Epi
2013 Nov 21
0
uso detach
Hola, ¿qué tal?
attach y detach son funciones cuyas páginas de ayuda están llenas de
avisos y caveats además de sugerencias acerca de alternativas a su
uso.
Yo siempre recomiendo no utilizarlas y yo en particular, las uso, si
acaso, de manera sumamente excepcional.
Un saludo,
Carlos J. Gil Bellosta
http://www.datanalytics.com
El día 21 de noviembre de 2013 13:18, Juan Bautista
<jbautista
2005 Aug 23
1
matrix conformity with matrix 1x1 and scalars
Hello,
I am calculating this thing with vectors (b) and matrices (G,P):
b'G/sqrt(b'Pb)
where the denominator is a quadratic form and therefore always a scalar.
In Scilab, it is quite simple:
b'*G/sqrt(b'*P*b)
However, in R, the denominator is an (1x1)matrix and R claims it is non
conformable and I have to use drop() or as.numeric(). Like this:
> b = 1:2
> G=diag(1,2)
>
2008 Nov 15
3
Statistics forums
Hi,
Given that the R forum is mostly a site to discuss issues related to the
language, are there any forums that discuss statistical issues? I am
specifically interested in the statistical issues in experimental design.
TIA,
Anjan
--
=============================
anjan purkayastha, phd
bioinformatics analyst
whitehead institute for biomedical research
nine cambridge center
cambridge, ma 02142
2011 Jun 04
1
nonparametric logistic regression based on locally weighted scatterplot smoothing (lowess)
Dear UseRs:
Recently, I have read an article regarding the association between age and
lymph node metastases.
http://jco.ascopubs.org/content/27/18/2931.long
In statistical analysis, the authors stated "Because a nonlinear
relationship between age and lymph node involvement was expected based on
existing literature, lymph node involvement was also regressed on age using
nonparametric
2012 May 01
1
testing parallel slopes assumption for Ordinal Logistic Regression
Hi everyone, I'm a bit new here (and new to R), and I was trying to do an
OLR, and testing the parallel slope assumption seems be very important. I
browsed through past postings, and didn't find much to help me in this area.
I was wondering if anyone knew how I could go about doing this. Thank you.
--
View this message in context:
2009 Aug 03
1
min frequencies of categorical predictor variables in GLM
Hi,
Suppose a binomial GLM with both continuous as well as categorical
predictors (sometimes referred to as GLM-ANCOVA, if I remember
correctly). For the categorical predictors = indicator variables, is
then there a suggested minimum frequency of each level ? Would such a
rule/ recommendation be dependent on the y-side too ?
Example: N is quite large, a bit > 100. Observed however are
2010 Dec 28
4
Reading sas7bdat files into R
Hi All,
I am trying to import a .sas7bdat file into R.
I tried using Hmisc package's sasxport.get() function.
temp <- sasxport.get("path\abcd.sas7bdat")
I get an error that says "Error in lookup.xport(file) : file not in SAS transfer format"
I am not familiar with SAS transfer format.
Could somebody please clarify what is it that I am missing,
Thanks for your
2023 Oct 31
0
Missing shapes in legend with scale_shape_manual
I believe the missing shapes are because you had set alpha=0 for the last geom point.
I expect there are better ways, but one way to handle it would be to avoid the filtering, adding columns with med and exercise status, like the following:
# setup with data provided
Date <- c('2023-10-17', '2023-10-16', '2023-10-15', '2023-10-14',
2023 Oct 31
0
Missing shapes in legend with scale_shape_manual
Tim, thanks, it helps very much. It works like a charm.
Wow, there's so much I don't understand about ggplot2 functions,
especially the aes() function. I just discovered the ggplot2-book.org
site, and I hope to read it slowly and carefully over the next couple
of weeks.
Thanks again, Tim, for all your help.
-Kevin
On Tue, 2023-10-31 at 12:35 +0000, Howard, Tim G (DEC) wrote:
> I
2010 Nov 29
1
weighted Spearman correlation coefficient
Hello,
I would be grateful if anybody can help me in finding an R function to
compute weighted Spearman correlation coefficient?
Kind regards,
Daniel