similar to: rolling regression between adjacent columns

Displaying 20 results from an estimated 2000 matches similar to: "rolling regression between adjacent columns"

2008 Jul 31
1
rollapply() to portions of a matrix
Hi everyone, I have a rollapply statement that applies a function, in steps, over a data matrix as follows: #Code start testm<-rollapply(mat, 100, by=100, min, na.rm=F) #Code end This moves down matrix 'mat' and calculates the minimum value over a 100 row range, every 100 rows (i.e. no overlaps). NAs are not removed. I want to modify this statement somehow so that the rollapply()
2008 Jul 27
4
product of successive rows
Hi everyone, I want to perform an operation on a matrx that outputs the product of successive pairs of rows. For example: calculating the product between rows 1 & 2; 3 & 4; 5 & 6...etc. Does anyone know of any readily available functions that can do this? Thanks, rcoder -- View this message in context: http://www.nabble.com/product-of-successive-rows-tp18681259p18681259.html
2008 Aug 12
7
ignoring zeros or converting to NA
Hi everyone, I have a matrix that has a combination of zeros and NAs. When I perform certain calculations on the matrix, the zeros generate "Inf" values. Is there a way to either convert the zeros in the matrix to NAs, or only perform the calculations if not zero (i.e. like using something similar to an !all(is.na() construct)? Thanks, rcoder -- View this message in context:
2008 Aug 13
3
conditional IF with AND
Hi everyone, I'm trying to create an "if" conditional statement with two conditions, whereby the statement is true when condition 1 AND condition 2 are met: code structure: if ?AND? (a[x,y] <condition1>, a[x,y] <condition2>) I've trawled through the help files, but I cannot find an example of the syntax for incorporating an AND in a conditional IF statement.
2008 Aug 02
1
problem with nested loop for regression
Hi everyone, I'm experiencing difficulty getting the results I want when I use a nested for loop. I have a data set to which I perform some calculations, and then try to apply a regression over a rolling window. The code runs, but the regression results I am getting (intercept and slope) are simply the same, repeated again and again in the results matrix. The regression does not seem to be
2008 Aug 13
2
missing TRUE/FALSE error in conditional construct
Hi everyone, I posted something similar to this in reply to another post, but there seems to be a problem getting it onto the board, so I'm starting a new post. I am trying to use conditional formatting to select non-zero and non-NaN values from a matrix and pass them into another matrix. The problem is that I keep encountering an error message indicating the ":missing value where
2008 Aug 13
2
merging data sets to match data to date
Hi everyone, I want to extract data from a data set according to dates specified in a vector. I have created a blank matrix with row names (dates) that I want to extract from the full data set. I have then performed a merge to try to o/p rows corresponding to common dates to a results matrix, but the operation did not fill the results matrix. Coulc anyone offer any advice to assist with this
2006 Mar 16
3
Did I use "step" function correctly? (Is R's step() function reliable?)
Hi all, I put up an exhaustive model to use R's "step" function: ------------------------ mygam=gam(col1 ~ 1 + col2 + col3 + col4 + col2 ^ 2 + col3 ^ 2 + col4 ^ 2 + col2 ^ 3 + col3 ^ 3 + col4 ^ 3 + s(col2, 1) + s(col3, 1) + s(col4, 1) + s(col2, 2) + s(col3, 2) + s(col4, 2) + s(col2, 3) + s(col3, 3) + s(col4, 3) + s(col2, 4) + s(col3, 4) + s(col4, 4) + s(col2, 5) + s(col3,
2017 Jun 21
4
selecting dataframe columns based on substring of col name(s)
Suppose I have the following sort of dataframe, where each column name has a common structure: prefix, followed by a number (for this example, col1, col2, col3 and col4): d = data.frame( col1=runif(10), col2=runif(10), col3=runif(10),col4=runif(10)) What I haven't been able to suss out is how to efficiently 'extract/manipulate/play with' columns from the data frame, making use
2017 Jun 21
0
selecting dataframe columns based on substring of col name(s)
> On Jun 21, 2017, at 9:11 AM, Evan Cooch <evan.cooch at gmail.com> wrote: > > Suppose I have the following sort of dataframe, where each column name has a common structure: prefix, followed by a number (for this example, col1, col2, col3 and col4): > > d = data.frame( col1=runif(10), col2=runif(10), col3=runif(10),col4=runif(10)) > > What I haven't been able to
2010 Mar 22
1
help needed with boxplot
I am new to R, can anyone help with boxplot for a dataset like: file1 col1 col2 col3 col4 col5 050350005 101 56.625 48.318 RED 051010002 106 50.625 46.990 GREEN 051190007 25 65.875 74.545 BLUE 051191002 246 52.875 57.070 RED 220050004 55 70 80.274 BLUE 220150008 75 67.750 62.749 RED 220170001 77 65.750 54.307 GREEN file2 col1 col2 col3 col4 col5 050350005 101 56.625 57 RED 051010002 106 50.625 77
2010 Jul 24
2
union data in column
Is there any function/way to merge/unite the following data GENEID col1 col2 col3 col4 G234064 1 0 0 0 G234064 1 0 0 0 G234064 1 0 0 0 G234064 0 1
2010 Oct 11
2
Split rows depending on time frame
Hi, I have the following data frame, where col2 is a startdate and col3 an enddate COL1 COL2 COL3 A 40462 40482 B 40462 40478 The above timeframe of 3 weeks I would like to splits it in weeks like this COL1 COL2 COL3 COL4 A 40462 40468 1 A 40469 40475 1 A 40476 40482 1 B
2008 Mar 16
2
How to loop through all the columns in dataframe
Hi: Can anyone advice me on how to loop and perform a calculation through all the columns. here's my data xd<- c(2.2024,2.4216,1.4672,1.4817,1.4957,1.4431,1.5676) pd<- c(0.017046,0.018504,0.012157,0.012253,0.012348,0.011997,0.012825) td<- c(160524,163565,143973,111956,89677,95269,81558) mydf<-data.frame(xd,pd,td) trans<-t(mydf) trans I have these values that I need to
2010 Apr 29
2
by funtion
Hello, I have a data.frame: name    col1    col2    col3    col4 AA    23    54    0.999    0.78 BB    123    5    1    0.99 AA    203    98    0.79    0.99 I want to get mean value data.frame in terms of name: name    col1    col2    col3    col4 AA    113.0000  76.0000   0.8945   0.8850 BB    123.00   5.00   1.00   0.99 I tried to use by function: >aa<-by(test[,2:5], feature, mean)
2010 Sep 27
1
compare two matrices
Hi everyone: I have a kinda easy question but i do not know how to solve that in a simple way. I want to compare the rows of two matrices. col1 <- c(1,2,3,4,5,6) col2 <- c(6,5,4,3,2,1) m <- cbind(col1, col2) col3 <- c(1,3,2,6) col4 <- c(6,3,5,1) n <- cbind(col3, col4) In matrix n, for example the first row is (1,6), it is also some row
2006 Dec 14
5
Better way to change the name of a column in a dataframe?
Hello R users -- If I have a dataframe such as the following, named "frame" with the columns intended to be named col1 through col6, > frame col1 col2 cmlo3 col4 col5 col6 [1,] 3 10 2 6 5 7 [2,] 6 8 4 10 7 1 [3,] 7 5 1 3 1 8 [4,] 10 6 5 4 9 2 and I want to correct or otherwise change the
2019 Feb 12
7
Leer un txt a trozos
Estimad en s eRRer en s, Tengo un txt que quiero importar a R. Pero no tiene un formato adecuado para usar cosas normales, como por ejemplo read.csv() El formato es algo así: time 1 col1 col2 col3 col4 dato dato dato dato dato dato dato dato dato dato dato dato dato dato dato dato dato dato dato dato end time 2 col1 col2 col3 col4 dato dato dato dato dato dato dato dato dato dato dato dato dato
2009 Dec 20
2
Remove rows in a matrix that match rows in another matrix
Dear R Community, The following seems like a simple problem, but I''ve been stuck on it for some time, with no luck using matching or subsetting functions. I''m trying to remove the rows from a large matrix that match rows in another large matrix. A (small scale) example: col1<-c("A", "B", "C", "D") col2<-c("A",
2009 Oct 02
3
help with regexp mass substitution
Hello * i have to rename a lot of variables, and, given that they have regular name constructs, I would like to use regexps. Here's a dump of my head(names(df)) varnames <- c("id.quest", "txt.1.3", "col1.1.3", "col2.1.3", "col3.1.3", "col4.1.3", "col5.1.3", "txt.2.3", "col1.2.3",