similar to: accessing list elements

Hi, I have a list of mutations, called "mutList", of the form: > head(mutList) Alu 1 AluJ 2 AluJ/F(R)AM 3 AluJ/FLAM 4 AluJ/FRAM 5 AluJ/monomer 6 AluJb It contains about 500 elements and not all of them contain the sequence "Alu". I tried using this code: Alu<-mutList[which(grep("Alu",mutList)==1)] But that simply returned

Hi R, Please solve my problem........... I am extracting Bloomberg data from R, in a loop. R is getting fatigued by doing this process and gives some errors. I introduced sleep function. Doing this sometimes I get the results and sometimes not. I even noticed that if I give complete rest for R (don't open R window) for 1 day and then run my code with the sleep function, then the

I am trying to replicate the SAS proc univariate in R. I got most of the stats I needed for a by grouping in a data frame using: all1 <- ddply(all,"ACT_NAME", summarise, mean=mean(COUNTS), sd=sd(COUNTS), q25=quantile(COUNTS,.25),median=quantile(COUNTS,.50), q75=quantile(COUNTS,.75), q90=quantile(COUNTS,.90), q95=quantile(COUNTS,.95), q99=quantile(COUNTS,.99) )

? data=read.table("http://statcourse.com/research/boston.csv", , sep=",", header = TRUE) ? library(rpart) ? fit=rpart (MV~ CRIM+ZN+INDUS+CHAS+NOX+RM+AGE+DIS+RAD+TAX+ PT+B+LSTAT) Please: Show me the tree. Mark -------- Original Message -------- Subject: Re: [R] help with rpart From: "Stephen Milborrow" <[1]milbo at sonic.net>

Quoting from today's PhD Comics, available at: http://www.phdcomics.com/comics.php?f=1476 What the methodology section says: "Analysis was performed using a commercially available software package." What it really means: "I put the numbers into this magic box and out came my thesis!" -- Sarah Goslee http://www.functionaldiversity.org

I thought some of you might be amused by this. In my non-work time, I'm an avid weaver and teacher of weaving. I'm working on a project involving creating many detailed weaving patterns, so I wrote R code to automate it. Details here: http://stringpage.com/blog/?p=822 If the overlap between R users and avid tablet weavers turns out to be >> 1, I'll polish it up and turn it

Hi Sarah, Thank you for your help. I tried using CR1<-as.matrix(CR1) but gives error Error in corrplot(CR1, method = "circle") : The matrix is not in [-1, 1]!. I am using a corrplot library. Please find the reproducible example: dput(head(CR1,10)) structure(c(26L, 46L, 39L, 38L, 47L, 59L, 56L, 61L, 43L, 60L, 78L, 63L, 2L, 58L, 8L, 1L, 1L, 9L, 11L, 2L, 1037500L, 46747L, 346300L,

Hi everyone, I looked around the list for a while but couldn't find a solution to my problem. I am storing some results to a simulation in a list and for each element i have two separate vectors(is that what they are called, correct my vocab if necessary). See below Version1_<-list() for(i in 1:5){ Version1_[[i]]<-list(First=rnorm(1),Second=rnorm(1)) } What I want is to put all

Hi All, I generated 5000 samples using the following script test<- rnorm(5000,1000,100) test1 <- subset(test, subset=(test > 1100)) d <- density(test) plot(d, main="Density of production") abline(v=mean(test1) I wanted to do the following but faced difficulties 1. to shade or color (blue) the curve using the criterion that any

Dear list, just to put it in a simple way: i read.csv from csv file to create a gdata then, create array gdata34 however, when making a loop for assigning gdata34[1,m]<-gdata[m,4], this is what happen gdata[1,4] 's real value is 10354, however, the gdata34[1,4] turns to be 883 then i checked the type: gdata[1,4] is integer, while gdata34[1,4] is double. Can any one give me some help

Hi, I have a set of x, y points where x represents dates and y actual values. I am trying to plot a line graph of the data with points on top, but R is connecting the wrong points with lines. Does anyone know how I can rectify this. Please see sample below: x= 24/09/2009 09:13 16/10/2009 11:17 24/10/2009 21:43 11/09/2009 18:34 22/08/2009 15:45 10/08/2009 00:30 14/08/2009 14:52 24/09/2009

Hi just a quick question in which I must use the "function and return" part of R. If I was asked to define a function called "median" where the function has a single argument x and returns the median value of a vector. How would I go about saying the median = element x in terms of n (say (n + 1)/2 or whatever it would be) if there is an even amount of elements, or x in terms

R-helpers: It looks like http://finzi.psych.upenn.edu/search.html has stopped spidering the mailing lists -- this used to be my go-to site for searching for R solutions. Are there any good replacements for this? I want to be able to search both functions and mailing lists at the same time. Cheers! --j -- Jonathan A. Greenberg, PhD Assistant Professor Department of Geography University of

Hello, I need some results from the survival analysis of my data that I do not know whether exist in Survival Package or how to obtain if they do: 1. The Mean survival time 2. The standard error of the mean 3. Point and 95% Lower & Upper Confidence Intervals estimates Any help will be greatly appreciated. Cem [[alternative HTML version

Hi folks, I am starter for R. While I tried list as following: > l <- list() > l$foo NULL > l$foobar <- 1 > l$foo [1] 1 Apparently, foo and foobar are different name for elements in list (actually foo does not exist). But why they are sharing same value? Thanks a lot! Max [[alternative HTML version deleted]]

That does clarify for me that you're missing a step: I didn't clearly follow your description at first. corrplot expects a correlation matrix, not your original data. You need to use cor() first. That's pretty clear in the documentation. See for instance the examples: data(mtcars) M <- cor(mtcars) corrplot(M) Sarah On Sat, Mar 17, 2018 at 12:00 PM Shivi Bhatia <shivipmp82 at

Hi, Can R read in .xyz files? If so, what is the package, thanks -- Shane [[alternative HTML version deleted]]

I need the output to have groups and the probability any given record in that group then has of being in the response class. Just like my email in the beginning i need the output that looks like if A and if B and if C then %77 it will be D. The examples you provided are just simply not similar. They are different and would take interpretation to get what i need. On Apr 14, 2016 1:26 AM,

A simple question, but I can't find something to do what I want: Given: a vector of numbers, like lambda <- c(0, 0.005, 0.01, 0.02, 0.04, 0.08) Desired: format them in minimal space for use as plot labels, ie, without leading or tailing 0s. For this example: lambdaf <- c("0", .005", ".01", ".02", ".04", ".08") -- Michael

Hi. Can you please answer to my questions about R ? 1.how can I write command for vector ? for exaple in this sample : I have this : a1 <- c (1:10) now how can I put in the vector ? bye for now, Thanks a lot. Majid. [[alternative HTML version deleted]]