similar to: Sample on dataframe

Hello, I have the following data frame (DF): V5 V5.1 V5.2 V5.3 V5.4 V5.5 2 -5890.18905 -6019.84665 -6211.06545 -6198.9353 -6616.8677 -6498.7183 3 -5890.18905 -6019.84665 -6211.06545 -6198.9353 -6616.8677 -6498.7183 4 -5890.18905 -6019.84665 -6211.06545 -6198.9353 -6616.8677 -6498.7183 5 -5890.18905 -6019.84665 -6211.06545 -6198.9353 -6616.8677

Hi Sorry for banal question How to create empty data frame with for example 30 variables without typying: data.frame(x=1,y=1....) Jarek

Hi! How to write in model's formula of type: nls(y~k/(x^n), data=data, start=list(k=1,n=1)) i.e the problem is on x^n, I(x^n) generate error thanks Jarek

Dear All! I'm looking for equivalent of Matematica function "Which" which works as follows: z = Which[x<10,0.3, 10<=x<20,0.5, 20<=x<100,1] where x is a vector I can replace it with custom function with set of ifelse but I'm looking for simpler and faster (much faster) solution best wishes Jarek

I've been trough the R documentation for about half an hour and it's not clear to me how to do this: I need to format to character a series of integers from 1 to 1000, and I like them to look like "0001" "0002", "0059", "0123" and so on. Padded with zeroes to have four digits. Cheers! Mario. r-help-request at r-project.org wrote: > Send

I'm pretty new to the task of upgrading CentOS or RedHat o.s.'s. I'm more familiar with upgrading Debian based o.s.'s. Here are my questions: 1) will yum ever upgrade the major version? I understand that there is no upgrade path from v5.x to v6.x, but is that always the case? e.g. was there an upgrade path from v4.x -> v5.x? If yum is capable of doing so, what are the

On Thu, Dec 12, 2019 at 07:56:26AM -0500, Michael S. Tsirkin wrote: > On Thu, Dec 12, 2019 at 01:36:24PM +0100, Stefano Garzarella wrote: > > On Wed, Dec 11, 2019 at 11:03:07AM -0500, Michael S. Tsirkin wrote: > > > On Fri, Dec 06, 2019 at 03:39:12PM +0100, Stefano Garzarella wrote: > > > > When we receive a new packet from the guest, we check if the > > >

Hello, Is it possible to trigger an action in a controller when a table from database changes? I thought about using an utility like cron (railscron) to check every, e.g. 2 s, if the table changed, but I am wondering if there is a solution a bit more ''elegant'': to trigger an action exactly when the change is made. Best regards, -- Kuba Nowak

Hi all, I'm trying to use an iteration that appends something to vector 'peaklabels' like so: peaklabelNames <- append( peaklabelNames, substitute(i^{z+phantom()}*" ("*a*"AMU)",list(i="y2",z=2,a=0)) ) The vector is supposed to be used with 'text' to put labels on signals in an impulse plot. While not vectorized

Why is class(spectrum[["Ion"]]) after this "factor"? spectrum <- cbind(spectrum,Ion=rep("", nrow(spectrum)),Deviation.AMU=rep(0.0, nrow(spectrum))) slowly going crazy ... Joh

All, I'm pleased to announce that Xiph.org has been selected as a mentoring organization for the 2006 Google Summer of Code program. So if you need a summer job, and there's something about free multimedia that's been bugging you, here's your chance! We've put up some project ideas for things we'd like to see in the wiki http://wiki.xiph.org/index.php/Summer_of_Code

All, I'm pleased to announce that Xiph.org has been selected as a mentoring organization for the 2006 Google Summer of Code program. So if you need a summer job, and there's something about free multimedia that's been bugging you, here's your chance! We've put up some project ideas for things we'd like to see in the wiki http://wiki.xiph.org/index.php/Summer_of_Code

All, I'm pleased to announce that Xiph.org has been selected as a mentoring organization for the 2006 Google Summer of Code program. So if you need a summer job, and there's something about free multimedia that's been bugging you, here's your chance! We've put up some project ideas for things we'd like to see in the wiki http://wiki.xiph.org/index.php/Summer_of_Code

All, I'm pleased to announce that Xiph.org has been selected as a mentoring organization for the 2006 Google Summer of Code program. So if you need a summer job, and there's something about free multimedia that's been bugging you, here's your chance! We've put up some project ideas for things we'd like to see in the wiki http://wiki.xiph.org/index.php/Summer_of_Code

All, I'm pleased to announce that Xiph.org has been selected as a mentoring organization for the 2006 Google Summer of Code program. So if you need a summer job, and there's something about free multimedia that's been bugging you, here's your chance! We've put up some project ideas for things we'd like to see in the wiki http://wiki.xiph.org/index.php/Summer_of_Code

Hi all, I asked something like this earlier but decided that a proper minimal example might be helpfull ;0) Why does this work with regards to the expression (substitution): require(stats) plot(cars) text(5,120,labels=substitute(i^{z+phantom()}*"("*a*" AMU)",list(i="yx",z=2,a=0))) text(c(5,5),c(115,110),labels=c("One","Two")) But adding this

Hi all, I'm getting a segmentation fault with yum when I try to update a CentOS v5.4 install to v5.5. What I've done: * Ran yum clean all. * Ran yum update yum* * Ran yum update, and got the segmentation fault. * Yum suggested running with option --skip-broken, which I did. Still got the segmentation fault. * Rebooted machine and ran yum update again. Segmentation fault... * Googled

I currently have about eight servers running a mixture of CentOS x86_64 v5.2 and v5.3 but none with the very latest updates. They all obtain their authentication information over LDAP and to avoid the starting message bus hang problem[1], nscd is set to soft failure. However, yesterday I set up a new CentOS v5.3 server with the latest updates, but it refuses to get beyond "Starting message

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Hi I have the problem with fitting curve to data with lm and glm. When I use polynominal dependiency, fitted values from model are OK, but I cannot recive proper values when I use coefficents to caltulate this. Let me present simple example: I have simple data.frame: (dd) a: 1 2 3 4 5 6 b: 3 5 6 7 9 10 I try to fit it to model: model=glm(b~poly(a,3),data=dd) I have following data