similar to: Table orderd by frequencies

Dear List, I ran into some problems with time-series-Data. Imagine a data-structure where observations (x) of test attendants (i) are made a four times (q) a year (y). The data is orderd the following way: I y q x 1 2006 1 1 1 2006 3 1 1 2006 4 1 1 2007 1 1 1 2007 2 1 1 2007 3 1 1 2007 4 1 2 2006 1 1 3 2007 1 1 3 2007 2 1 I am looking for a way to count the attendants that at least have

Dear List, I have Multi-level Data i= Indivitual Level g= Group Level var1= First Variable of interest var2= Second Variable of interest and I want to count the frequency of "var1" and "var2" on the group level. I found a way, but there must be a much simpler way. data.ml <- data.frame(i=c(1:8),g=as.factor(c(1,1,1,2,2,3,3,3)),var1=c(3,3,3,4,4,4,4 ,4),

Dear Everyone, I try to create a cvs-file with different results form the table function. Imagine a data-frame with two vectors a and b where b is of the class factor. I use the tapply function to count a for the different values of b. tapply(a,b,table) and I use the table function to have a look of the frequencies as a total table(a) I would like to put both results together in one txt or

Dear Everyone, I try to automatically manipulate the data of a variable (class = factor) like x 220 220a 221 221b B221 Into two variables (class = numeric) like x y 220 0 220 1 221 0 221 1 221 1 y has to carry the information about the class (number or string) of the former x-Variable. I could do it by hand like x[x == "220a"] <- 220

Dear list, I'm looking for a way to select rows of a data.frame with changing number of columns (constraint) involved. Assume a data (d) structure like Var.1 Var.2 Var.3 9 2 1 2 9 5 1 2 1 I know the number of involved columns. Is there a way to generate the following selection automatically (maybe for loop), so that it makes no difference if there are two or ten columns involved.

Dear list, I'm looking for a way to count the number of "|" within an object. The character "|" is used to separated ids. Assume a data (d) structure like Var NA NA NA NA NA 1 1|2 1|22|45 3 4b|24789 I need to know the maximum number of ids within one object. In this case 3 (1|22|45) Does anybody know a better way? Thanks Mit freundlichen Gr??en Andreas Kunzler

Dear List-serv members: How can I structure a for loop so that it will increment the counter by two using R? I am just looking for a simple example that shows where the incrementing part should go. Thanks! Jennifer -- Jennifer Hayes Clark Assistant Professor Department of Political Science University of Houston Houston, TX 77204-3011 [[alternative HTML version deleted]]

Dear all, I have got a question for generating repeats of a vector's elements. Please don't hesitate to email me back and say that it is very easy although I can't find a method to solve it. If I have a n-vector b, whose elements are b[1], b[2], ..., b[n], how can I generate such a vector b[1], b[1], b[2], b[1], b[2], b[3], b[1], b[2], b[3], b[4], ......, b[1], b[2], ...,

hi I have vector test. It has 3 elements. I want to join the three into one vector. "Geneset=HSA04910_INSULIN_SIGNALING_PATHWAY-157- 20". how can i do it. > class(test) [1] "character" > test [1] "Geneset=HSA04910_INSULIN_SIGNALING_PATHWAY" "157" [3] "20" Ramya --

Hi Is it possible to use the rep command (or maybe some other "shortcut") to create a vector with the following format: 4 3 4 2 3 4 1 2 3 4 Any help is much appreciated. Thanks Jacob Jacob L van Wyk Department of Statistics University of Johannesburg, APK Box 524 Auckland Park 2006 South Africa Office Tel: +27 11 559 3080 Fax: +27 11 559 2832 [[alternative HTML version

I would like to know how to convert a string with characters to all uppercase or all lowercase? If anyone could let me know if there exists a function in R for the conversion, that will be very helpful. Regards, Suman [[alternative HTML version deleted]]

I have a vector of data (species names) interspersed with NA values and I want a function to "fill in the blanks", replacing NA values with whatever the last species name was. For example the vector: "A","B",NA,NA,"C",NA,NA,NA,NA,"D",NA,NA. should evaluate to: "A" "B" "B" "B" "C"

Dear R experts,   I have a dataframe with 4 columns (variables). I want to redorder (or reposition) these columns on the basis of a value in its last row. e.g.   df1<-data.frame( v1= c(2,3,1,9,5), v2=c(8,5,12,4,11), v3=c(7,8,2,6,9), v4=c(1,4,6,3,6))    > df1    v1 v2 v3 v4 1  2  8  7  1 2  3  5  8  4 3  1 12  2  6 4  9  4  6  3 5  5 11  9  6 I wanto to get the order of df1 on the basis of

Hi - I'd like to have the area between 2 lines on a x-y plot be filled with grey, but I haven't had any luck using polygon or rect. (In reality, I'd like to do this for twice - once for a low group and once for a high group - and then I'd like to plot a set of data points for a 'normal' group together with these 2 grey areas.) Here's a simple example of the 2 lines:

Hi there! I can't find any information about creating combinations with repetitions in R. The function combn() does create combinations, but _without_ repetitions. Here is what I need to do: svIter <- 1000 xx <- matrix(rnorm(m*n), c(m, n)) sequence <- seq(range(xx)[1], range(xx)[2], length.out = svIter^(1/q)) expand.grid(secuence, secuence, .../q times/..., secuence) That is,

Hey list! I have a csv-file with two variables: (Date,CMI) Date,CMI Jan-93,3.24 Feb-93,-2.56 . . . Dec-06, 8.25 When I want to plot this dataset, R is sorting the date in alphabetical order. Is there any way to tell R not to do it? I know it is probably an easy issue but I couldn't find a solution so far. I have seen so many tips already but can't apply it on my own dataset. Thank

Dear R users, I have a newbie-question that I couldn't resolve after reading through several pieces of documentation and searching the archive. I have a data.frame containing experimental data from a group experiment in psychology. Each line represents a single participant, but participants were assigned to groups of three or four persons. One variable indicates each participants'

I am looking for the most efficient way to replace all occurrences of NaN in a data frame with NA. I can do this with a double loop, but it seems that there should be a higher level and more efficient way. With is.na, I could use ifelse, but if.nan seems not to have similar capabilities. TIA, Jon Peck Jon K. Peck jkpeck@aya.yale.edu [[alternative HTML version deleted]]

Dear List, I ran into some trouble by calculating differences. For me it is important that differences are either 0 or not. So I don't understand the outcome of this calculation 865.56-(782.86+0+63.85+18.85+0) [1] -1.136868e-13 I run R version 2.71 on WinXP I could solve my problem by using round() but I would like to know the reason. Maybe someone can help me? Thanx

Hi everybody! I'm sure that I overlook something and feel quite stupid to ask, but I have not found an easy solution to the following problem: Take e.g. the Orthodont data from the nlme package: > head(Orthodont) Grouped Data: distance ~ age | Subject distance age Subject Sex 1 26.0 8 M01 Male 2 25.0 10 M01 Male 3 29.0 12 M01 Male 4 31.0 14 M01 Male