similar to: spreading the risk

Hello all. I am trying to do the equivalent of: @componentlogs = Componentlog.find(:all, :conditions => [ "cl_compname like ?", @criteria ], :offset => offset, :limit => items_per_page, :order => "cl_spr DESC" ) in a find_by_sql statement. I cannot use the build in because the adaptor isn''t quite right (OCI8) When I use it I get the following error

>I have a series of write statements because >i am writing to a file >where the characters strings are the column names of a dataframe >and the numbers are the elements in a particular row. >So, a file might look like > >AAA 2.1 >BB 3.1 >AHLZ 0.2 > >and it would be named "rowname".mls. > >so, each time i get to a new row, i create a new file and

rm(list=ls()) yx.df<-read.csv("c:/MK-2-72.csv",sep=',',header=T,dec='.') dim(yx.df) #get X matrix y<-yx.df[,1] x<-yx.df[,2:643] #conver to matrix mat<-as.matrix(x) #get row number rownum<-nrow(mat) #remove the constant parameters mat1<-mat[,apply(mat,2,function(.col)!(all(.col[1]==.col[2:rownum])))] dim(yx.df) dim(mat1) #remove columns with numbers of

Hi all, This is a very basic question, but I just can't figure out why R is handling a loop I'm writing the way it is. Here is the script I have written: grid_2_series<-function(gage_handle,data_type,filename) series_name<-paste(gage_handle,data_type,sep="_") data_grid<-read.table(file=paste(filename,".txt",sep=""))

Hello Lets say as an example I have a dataframe with the following attributes: rownum(1:405), colnum(1:287), year(2000:2009), daily(rownum x colnum x year) and foragePotential (0:1, by 0.01). The data is actually stored in a netcdf file and I'm trying to provide a conceptual version of the data. Ok. I need to calculate a moving mean and a moving variance for each cell on the following

Hi All, We have a raw dataset that, on the sampling time column, for example: t <- c(0,1,2,5,0,5,0,2,5) And we need to create a second column that indicates the day of the sampling, so the end result of what we want is a vector: 1,1,1,1,2,2,3,3,3 Additional information that might simplify the matter is that, for each day, the time starts with zero and ends with 5. I am a beginner with R.? So

Hello all. I am using the Paginate_with_ajax code as described on the wiki but I am running into the following problem. The following code will work fine and retrieved unsorted records in a hunky dory fashion: @componentlogs = Componentlog.find(:all, :conditions => [ "cl_compname like ?", @criteria ], :offset => offset, :limit => items_per_page ) However if I try and add an

"bitsweat" has kicked AR/Oracle while it was down... http://dev.rubyonrails.org/changeset/7769 ------------------------------------------------------------------------ r7769 | bitsweat | 2007-10-06 22:29:37 -0700 (Sat, 06 Oct 2007) | 1 line MySQL: speedup date/time parsing. ------------------------------------------------------------------------ U

Dear R gurus, I have the following code, but I still not know how to estimate and extract confidence intervals (95%CI) from resampling. Thanks! ~Adriana #data penta<-c(770,729,640,486,450,410,400,340,306,283,278,260,253,242,240,229,201,198,190,186,180,170,168,151,150,148,147,125,117,110,107,104,85,83,80,74,70,66,54,46,45,43,40,38,10) x<-log(penta+1) plot(ecdf(x),

This is another edition of Rails Core Weekly, affectionately known as RCW. A much nicer pre-web 3.0 version is available from the following url : http://www.pinupgeek.com/articles/category/rails-core-weekly-news We have an Atom/RSS feed available there as well. Rails Core Weekly summarizes the rails-core mailing list, a list dedicated to Ruby on Rails internals and its development. RCW is

Hi, I have the following: for(j in (y.raw+1):(rownum-1)){ valsum<-tstfframed[min.x,j]+tstfframed[min.x,j+1] if(valsum == 1){ cat("valsum loop") int.num<-int.num+1 } } but I get the error message: "Error in if (valsum == 1) { : argument is of length zero". I checked whether to see if all the stated variables have associated values (and are not NAs) and

Hello, I have a data frame that looks like this (containing interarrival times): > str(df) 'data.frame': 18233 obs. of 1 variable: $ Interarrival: int 135 806 117 4 14 1 9 104 169 0 ... > head(df) Interarrival 1 135 2 806 3 117 4 4 5 14 6 1 > This corresponds to the time differences (in ms) of a poisson arrival

Hi to all!! I am new to ruby. I am trying to write a program to fetch the data from Database and written the data using pagination. I could get the data from DB. but pagination is not working. When i see the log file it is showing the following error. NoMethodError: undefined method ''paginatior'' #<Hash...> my pginate.rb and pagination.rb files are not in the same folder

Hi I run Ruby on Rails on Oracle XE. I have a simple table: create table customer(id number primary key, name varchar2(100)); And ruby script\generate model Customer ruby script\generate controller Customer http://localhost:3000/customer/ - show a fine list, but when I click show/edit/destroy, I get an ORA-01722: OCIError: ORA-01722: invalid number: select * from (select raw_sql_.*,

Hello: I am new R user stumped why the R code after this paragraph generates "Error: syntax error" messages after each of the last 2 lines. I have tried searching the manuals, Hmisc documentation, contributed manuals, help archives, and Internet. I am running R 1.7.1 under Windows 2000 (I will upgrade when my imminent OS upgrade happens). My data was successfully entered and

I was looking for an R-package that would reduce matrices to row-echelon form, but Google was not my friend; any leads? If not, I wonder if the problem could be expressed in terms of constraint satisfaction...

I have 2 dataframes. "mydata" contains numerical data. "mybys" contains information on the "group" each row of the data is in. I wish to aggregate each column in mydata using the corresponding column in mybys. Please see the example below. What is a more elegant or "better" way to accomplish this task? Thanks! mydata =