similar to: plot(linear model) without lines

Based on the feedback received, I did the following: a) moved my lib sub-directory from the existing installed R version to c:\myRLib b) installed the updated R version c) created .Renviron file in the home directory (C:\R-2.5.1) with the line R_LIBS=c:/myRLib d) used .libPaths() command to confirm that the new R installation was recognizing the myRLib sub-directory e) deleted my old R

I can't seem to find just what I'm looking for in R help, Everitt and Hothorn HSAUR, Murrell's book, or the R graphics gallery at http://addictedtor.free.fr/graphiques/. Probably not looking efficiently, but anyway, If my data look like this: > head(data) cat startyear studentid 1 other 2001 12 2 UHS 2001 17 3 Lourdes 2001 10 4

Is there a way to automate fitting and assessing loglinear models for several nominal variables . . . something akin to step or drop1 or add1 for linear or logistic regression? Thanks. --Chris -- Christopher W. Ryan, MD SUNY Upstate Medical University Clinical Campus at Binghamton 40 Arch Street, Johnson City, NY 13790 cryanatbinghamtondotedu "If you want to build a ship, don't drum

I can't seem to use the point-and-click identify() function properly. I'm running R 2.5.1 (I know, I need to get around to upgrading) under Win XP. The problem is, when I click on a point on the graph, I get an error, "no point within 0.25 inches." But in some areas, I can click where there is no visible point anywhere close, and an identify() label will pop up. The troublesome

How would I color points conditional on their value in a plot of a time series. Something like this: ## demonstration data ttt <- ts(rpois(12, lambda = 8), start = c(2000, 1), freq = 4) ttt plot(ttt, type = "p") ## doesn't work--all points the same color plot(ttt, type = "p", col = ifelse(ttt < 8, "black", "red")) ## also doesn't work--all

Running R 2.13.1 on Windows XP. I would like to get week of the year (1-52) for each date. library(chron) dts <- dates(c("02/27/92", "02/27/92", "01/14/92","02/28/92", "02/01/92")) dts dts.chron <- as.chron(dts) dts.chron class(dts.chron) # all of these component extractions work: months(dts.chron) weekdays(dts.chron) years(dts.chron)

R 2.5.1 on WinXP I'm trying to create new variables in a dataframe called jaw, as powers of jaw$age up to the sixth power, and name them jaw$age.(--the digit corresponding to the power--) Obviously none of these work (silly for me to try, I suppose): for (i in 2:6) { jaw$age.'i' <- jaw$age^i } for (i in 2:6) { jaw$age.i <- jaw$age^i } for (i in 2:6) {

Excellent! Worked like a charm. Thanks. --Chris Ryan On Tue, May 1, 2018 at 4:33 PM, William Dunlap <wdunlap at tibco.com> wrote: > The ts method for plot() is quirky. You can use the default method: > > plot(as.vector(time(ttt)), as.vector(ttt), type = "p", col=ifelse(ttt<8, > "black", "red")) > > > Bill Dunlap > TIBCO Software

I'm trying to learn Sweave. So far things are going well with the chunks of code identified by << >>= But I'm having trouble with the in-line text use of \Sexpr. Here is a short example .Rnw file: \documentclass[12pt]{article} \usepackage[margin=1.25in]{geometry} \usepackage{graphicx} \usepackage{Sweave} \begin{document} <<test>>= pnorm(1) @ \Sexpr{2+6}

The ts method for plot() is quirky. You can use the default method: plot(as.vector(time(ttt)), as.vector(ttt), type = "p", col=ifelse(ttt<8, "black", "red")) Bill Dunlap TIBCO Software wdunlap tibco.com On Tue, May 1, 2018 at 1:17 PM, Christopher W Ryan <cryan at binghamton.edu> wrote: > How would I color points conditional on their value in a plot

suppose I have some logical vector x <- as.logical(c(0,0,0,1,0,0,1,1,0)) x How would I make the words TRUE appear on the screen in a different color from the words FALSE? Thanks. --Chris -- Christopher W. Ryan, MD SUNY Upstate Medical University Clinical Campus at Binghamton 40 Arch Street, Johnson City, NY 13790 cryanatbinghamtondotedu "If you want to build a ship, don't drum

You may also want to check this out: plot(ttt, type = "p") points(ttt, col = ifelse(ttt < 8, "black", "red")) Eivind K. Dovik Bergen, NO On Tue, 1 May 2018, Christopher W Ryan wrote: > Excellent! Worked like a charm. Thanks. > > --Chris Ryan > > On Tue, May 1, 2018 at 4:33 PM, William Dunlap <wdunlap at tibco.com> wrote: > >> The

hi: apologies for taking up everyone's time. my problem is probably documented somewhere, but I again cannot find it. (which reminds me: I cannot find a search engine that allows me to search the archives of this very useful mailing list.) * it seems that lines(lowess()) fails to plot certain line segments. (and, what does it do at the x-min and x-max of a data set?) Rather than

I participate peripherally on a listserve for middle- and high-school science teachers. Sometimes questions about graphing or data analysis come up. I never miss an opportunity to advocate for R. However, the teachers are often skeptical that their students would be able to issue commands or write a little code; they think it would be too difficult. Perhaps this stems from the Microsoft- and

Hi, I have a scatter plot of the variables GNI and Lifeexp (Gross National Income and Life Expectancy, both metric). So I plotted them and I want to add a regression line and a lowess line. I use lowess and not loess because I have missing values. My code: plot(GNI,Lifeexp) abline(lm(Lifeexp~GNI), col="red") y.loess<-loess(Lifeexp~GNI,na. action = na.exclude)

Full_Name: Adrian Custer Version: 0.90.0 OS: Linux on Thinkpad (pentium) and desktop (K6) Submission from: (NULL) (128.32.251.234) When I create a boxplot, and then try to overlay a lowess fit or just the points, the points do not appear in the highest level and the lowess curve does not reach the highest level. However, if I add one to each of the models, the problem is solved. I tried this

I'm using this code to plot a smoothed line. These two columns of data really represent 4 groups and I'd like to plot a separate line for each group but have them all in the same plot. The R-Docs for lowess do not seem to indicate some type of "GROUPS=var_name" option. What would be the syntax for this? plot(AWGT ~ lipid ) lines(lowess(lipid , AWGT, f=.8)) -- Dean

I have a dataframe that looks like this: > str(chr) 'data.frame': 84 obs. of 7 variables: $ county: Factor w/ 3 levels "Broome","Nassau",..: 3 3 3 3 3 3 3 3 3 3 ... $ item : Factor w/ 28 levels "Access to healthy foods",..: 21 19 20 18 16 3 2 6 17 8 ... $ value : num 8644 15 3.5 3.9 7.7 ... $ low : num 7897 9 2.5 2.6 7 ... $ high : num 9390

beginner's mistake on my part. the fitted turned out to have negative values in it, so the logplot failed. apologies. it still would be nice to have more docs on lowess, but this has nothing to do with my question. regards, /iaw

The lowess() help page refers to documentation in "src/appl/lowess.doc". This was moved to "src/library/stats/src/lowess.doc" in 2007. This patch fixes it: Index: src/library/stats/man/lowess.Rd =================================================================== --- src/library/stats/man/lowess.Rd (revision 79137) +++ src/library/stats/man/lowess.Rd (working copy) @@