similar to: creating axis of the plot before data are plotted -- solved

Dear R-users, I'm tackling with a problem which causing me a head-ache for a long time. I would like to create a nice x-axis to my plots, but I do not know how to implement the method. Imagine a matrix where you have rownames real numbers -- these rownames should be written in the x-axis nicely. I could not find any way how. I'll describe what I'm doing now: I have a matrix where

Dear R-users, I'd like to turn a vector so it starts with it's end. For better understanding, this set of commands will do what I need: i <- seq(1:10) i_turned <- i for (j in 1:length(i)) i_turned[j] <- i[length(i)-j+1] now, i_turned is what I call turned. Is there a function which would make a script lighter? Thank you upfront for any hint. Best regards, Zroutik

Dear R users, I plot data with points(my_data[x]~x, col = x, type = "o", lwd="4") where x is an integer running from 1 to 10, I get points drawn at the plot. When want to do a legend to this I try legend(leg.txt[x], col = x, text.col = 1, pch = 1, bty = "n") where leg.txt contains the names of the variable and x behaves the same. The difference between the

Hi, I'm looking for a manual (we based or pdf) which would explain in detail with graphical examples what all the option can do in plot and par. Does anybody now anything like this? A couple of manuals to R I went through do have plot parameters mentioned, but sometimes it is hard to understand or imagine what the parameter can do (the same with the related help page) e.g. I met "From

Dear R-users, in a minimal example exists() gives FALSE on an object which obviously does exist. How can I check on that list object anyway else, please? > SmoothData <- list(exists=TRUE, span=0.001) > SmoothData $exists [1] TRUE $span [1] 0.001 > exists("SmoothData") TRUE > exists("SmoothData$span") FALSE > exists("SmoothData[[2]]") FALSE

Dear R-users! Is there a way to obtain the name of the executed myscript.r, i.e. when cmd> rscript myscript.r is executed? (The name of the script in this case is "myscript.r") Here is the explanation of why I would like to get that: Why: I have prepared a set of scripts (decompose_data.r, plot_with_higher_resolution.r, plot_3D.r, etc.) placed in a root directory at one place. I

Dear R-users, I need to load outputs from multiple previous calculations into one R session for comparison and (cross-)analysis. The previous calculations are stored in different directories in .Rdata files (I don't know if this is the best storage for later usage, but the previous project could be recalculated and saved into different format, if needed, potentially.) I can load consequently

#This is probably due to my incomplete understanding of grep, but the below code has been working for some time to #search for .R with anything in front of it and return a list of scripts to source. Likely, the syntax for the #grep statement has been wrong all along. scripts2source <- (c("/home/ssefick/R_scripts/Convert_package.R",

Dear R-users, I'd like to fit a sine function to my data. The result should have a format (and thus the formula, too) y ~ a + sin(x+b) where y and x are vectors, and a and b are (yet) unknown values. The data sets (vectors x and y) are OK, and I can do a simple lm fitting lm(y~x), or lm(y~I(sin(2*pi*x/360))), succesfully My issue is that I'm not able to do the optional linear shift in

I am not entirely sure what is going on. I am sure that I am missing something. maptools won't detach... Thanks for all of your help. R 2.11.1 OS Ubuntu 10.04 R --vanilla install.packages("sp", dep=TRUE) Loading required package: reshape Loading required package: plyr Loading required package: grid Loading required package: proto This is vegan 1.17-3 Loading required package:

Apparently there is one or more concepts that I do not fully understand from the descriptions of a function and the apply material. I have been reading the mail from this forum and have learned much but, in this case, what I have been reading here and from the manual isn't enough. The following code produces what I want with the for loop. From what I have read from this forum, a for

Hi Stephen, Thanks again for getting back to me, Ivan Krylov responded also and suggested windows binaries and I must confess I was only familiar with installing from files via the package sources (apart from the conventional install.packages method), so the solution was as simple as installing via the binaries. Thanks again, best wishes, James From: stephen sefick <ssefick at gmail.com>

Dear R users, is there a hack how to get the filename of the current script.r sourced/ran? My issue: I have a couple of scripts which were optimised and are placed in tens of directories. (I have a height.r script in 30 directories, a lines.r script in 25 directories and another flow.r script in 54 directories, growing). The script runs in the directory and does its job: sources data and creates

Is there a way to use the cycle variable for rowname? v=1:6 for (a in 1:3){ for (b in 4:5) { v=rbind(v,a.b=1) } } v This above obviously does not work, but I couldn't find out how to use a and b to construct a rowname like 14, 15, 24, 25. Thanks for the help. Balazs -- View this message in context: http://www.nabble.com/using-for-variable-as-rowname-tp19533203p19533203.html Sent from

Hi! All, I have 2 correlation matrices of 4000x4000 both with same row names and column names say cor1 and cor2. I have extracted some information from 1st matrix cor1 which is something like this: rowname colname cor1_value a b 0.8 b a 0.8 c f 0.62 d k 0.59 - - -- -

Hello, I am trying to do arithmetic on numbers extracted from a PostgreSQL database, wherein the numbers are stored as type "money". The transcript below illustrates the problem. > Membersind06 <- sqlQuery(channel,"select * from income where rowname like '%Membersind%'") > names(Membersind06) [1] "rowname" "item"

Hi, My first post here and new to R so please bear with me (long time programmer though, helping a friend with some scripts). I've noticed a behaviour when using rownames() that I think is odd, wondering if I'm doing something wrong. To illustrate, say I create a very simple matrix (called fred): fred<-matrix(,4,2) It looks like this: [,1] [,2] [1,] NA NA [2,] NA NA

Dear r-helpers, I would very much appreciate help with the following problem: The following command (in a .Rnw file) latex(anova(e7.lmer3, e7.lmer4), file = 'e7lmer34.tex', rowname = c ('nonlinear', 'linear'), longtable = FALSE, dcolumn = T, booktabs = T, table.env = F) produces the following output after running Sweave: % latex.default(anova(e7.lmer1, e7.lmer2),

Hi I want to extract rows of a matrix, and preserve rownames even if only one row is selected. Toy example: R> a <- matrix(1:9,3,3) R> rownames(a) <- letters[1:3] R> colnames(a) <- LETTERS[1:3] R> a A B C a 1 4 7 b 2 5 8 c 3 6 9 Extract the first two rows: R> wanted <- 1:2 R> a[wanted,] A B C a 1 4 7 b 2 5 8 rownames come through fine. Now extract just

Dear Gavin, This is really great, thank you! I created some long loops to get rid of extra months at the beginning and the end of my data but your code is great for putting it then together quarterly. thanks again, Denise On Mon, 2008-08-18 at 14:31 +0100, Denise Xifara wrote: > Thank you very much Stephen, but how will aggregate deal with months that > fall outside annual quarters? eg,