similar to: read.table problem

Dear all, I have problem when reading a table into R. The total row of read in table has is much less than the original saved table. I built a 1,273,230 by 6 data set named "mydata2", it was saved in the following command, write.table(mydata2, "mydata2.txt", row.name=F,col.name=T,quote=F,sep="\t") The next day I read in above saved text file into R,

Hi all, I would like to check if a string contains "." in it. If yes, I would like to know the position of "." in the string. Eg: X<-"NM1236.3" In above example, "." is at position 7. I tried functions grep() and match(). It seems they couldn't detect ".". Thanks in advance for your help, Sityee [[alternative HTML version deleted]]

Hi All, I'm going to draw 8 plots in one page. I want the plots to be arranged in two rows, each row has 4 plots. So, I set the it par(mfrow=c(2,4)). However, there might be too many plots in a page, all the 8 plots were drawn in triangular shape, which makes the x-y coordinate scale not in same length, the x-axis length is much shorter than the y-axis length. Could anybody let me know how

Hi All, The for-loop below stopped when error("Cannot get confidence intervals on var-cov components: Non-positive definite approximate variance-covariance") occurred. I assigned a row of NA values to the data frame "m1" manually and reset "j" in the for-loop every time error returned. I’m wondering if there is a function that can detect error or failure, so the

you could try mapply mydata2<-mapply("[", mydata, lapply(mydata, function(x) !x %in% A)) mydata2[[1]]<-A #to replace the obviously deleted elements of "A" mydata2 mydata2[[1]] mydata2[[2]] mydata2[[3]] mydata2[[4]] Stefano -----Messaggio originale----- Da: r-help-bounces at stat.math.ethz.ch [mailto:r-help-bounces at stat.math.ethz.ch]Per conto di jastar

Hello, does anyone know of a quick way to create a data frame "like" another, but with more rows? What I'd like to do is this: if mydata is a data.frame like a b c 1 TRUE yes 2 FALSE no 3 TRUE yes I'd like to get mydata2 with the same column names and column types, but without the values and with more rows. All I could think of was to manually do

R helpers I am getting to grips with R but came across a small problem today that I could not fix by myself. I have 3 text files, each with a single column of data. I read them in using: myData1<-scan("C:/Program Files/R/myData1.txt") myData2<-scan("C:/Program Files/R/myData2.txt") myData3<-scan("C:/Program Files/R/myData3.txt") I wanted to produce a

Hi all, Could someone tell me how to split a word. c("AA") to c("A","A") Thanks! Phoebe [[alternative HTML version deleted]]

Hello I have dataframes. mydata1 <-data.frame(value=c(15,20,25,30,45,50),dates=c("2005-05-25 07:00:00 ","2005-05-25 19:00:00","2005-06-25 07:00:00","2005-06-25 19:00:00 ","2005-07-25 07:00:00","2005-8-25 19:00:00")) or mydata2 <-data.frame(value=c(15,20,25,30,45,50),dates=c("2005-05-25 00:00:00 ","2005-05-25

I'm trying to convert data from character to numeric. I've imported data as a csv file, I'm assuming that the import is a database - are all the columns in a database considered "vectors" and that they can be operated on individually Therefore I've tried the following mydata <- as.numeric(mydata$apples) when i then look at mydata again the named column is still

I can run one-sample t-test on an array, for example a matrix myData1, with the following apply(myData1, 2, t.test) Is there a similar fashion using apply() or something else to run 2-sample t-test with datasets from two groups, myData1 and myData2, without looping? TIA, Gang

Dear All, I have a dissimilarity matrix which I happily convert to a distance object by running: X <- as.dist(Y) and I can happily now run either hclust(X) or agnes(X). So that the various bits of output are labelled correctly I would dearly like to be able to give names to the columns and rows of X, as would happen if I ran: mydata<-read.table("clipboard",header=T)

Hi All, I have problem about the factor features. I read in a .cvs file, a column which is supposed to be numeric, but it becomes factor level data after reading in. mydata[,"newXaxis"] [1] 0 0.430010601 11.23198508 25.00940297 37.75338045 45.98289639 [7] 48.92328133 52.51142822 61.12359751 63.85832121 70.98927949 77.16550181 [13] 97.73545713 113.6588007 118.6588007

Dear users, I have a double for loop that does exactly what I want, but is quite slow. It is not so much with this simplified example, but IRL it is slow. Can anyone help me improve it? The data and code for foo_reg() are available at the end of the email; I preferred going directly into the problematic part. Here is the code (I tried to simplify it but I cannot do it too much or else it

Hi all, I'm hoping to add texts into a plot. I'm using text() to do it. I wonder if the text() allow me to make the text vertically printed? Thanks in advance for help, phoebe [[alternative HTML version deleted]]

Hi, It works for me to import spss datasets via library(foreign) with read.spss or via library Hmisc by (spss.get). But no matter which way I do import the data, user-defined missings from Spss are always lost. (it makes no difference if there are a single value, a range, or any combination of them. They are always ignored). Is there any way in R to find out if any value was user-defined missing

Hi all, Is there a function that allow me to concatenate each value in a vector to a string? x<-c("a","b","c","d") output string = a+b+c+d Thanks, phoebe [[alternative HTML version deleted]]

Hi All, I have a dataset with a column named "Condition", Sample Condition 1 c20 2 c20 3 c10 4 c10 5 c9 6 c9 7 c5 8 c5 9 c20 10 c10 Could you let me know the fastest way to change c20->"AA", c20->"BB", c9->"CC", c5->"DD"

Hello fellow R's, I?ve been learning to use the ggplot2 library, and after a full day of work I still have a couple of basic questions. Here is an example: mydata=data.frame(x=runif(20),y=runif(20),n=runif(20)) mydata2=data.frame(x=c(0.4,0.6,0.5),y=c(0.4,0.4,0.6)) ggplot(mydata, aes(x, y)) + geom_point(aes(size = n)) + geom_polygon(data=mydata2,aes(x,y,alpha=0.5)) In this plot, the

Hi there, I would like to draw a scatter plot and fit a smooth line by loess. Below is the data. However, the curve line started from 0, which my "resid" list doesn't consist of 0 value. It returned some warnings which I don't know if this is the reason affecting such problem. Here I also attached the warning messages. Please let me know if there is a solution to fix this. Thank