Displaying 20 results from an estimated 300 matches similar to: "Help on Calculating day differences"
2007 Dec 03
1
help on qcc
Hello R Experts,
I started to work with the qcc package and it wprks quite nicely.
Heres My Code:
n <-
c(55,5,94,25,10,15,15,40,44,34,90,114,204,37,30,28,12,68,64,29,24,14,31,16,62,45,55,20,24,14,9,19,76,57,55,42,6,
54,32,117,19,32,9,11,13,31,27,33,44,28)
x <- c(6,0,30,5,2,1,4,5,2,9,12,24,64,3,9,21,9,48,15,4,3,0,1,0,6,
7,2,0,3,2,0,5,1,2,6,9,1,6,2,0,1,4,8,0,1,1,3,0,0,0)
2006 Sep 13
9
R-question
Hello Colleagues,
I programmed in SAS for 3 years and would like to switch to a not so costly
software product.
Hence I started to evaluate R, and my first test look promising.
However I have some question:
1. Is it possible to query R files by SQL internally on data frames (not on
a database) and how is the syntax (I have the RODBC package installed).
I would like to extract year, Quarter,
2011 May 24
1
Loading an S object into R
I hope you'll all forgive me for displaying my severe lack of knowledge on this topic, and I can't really provide much in the way of reproducible code.
A colleague of mine has asked if I know how to import an S object into R. The object is stored in a file named 'pre3.f' When I open the file as a text document I get what's printed below. Being one of those young bucks with
2012 May 15
1
vector w/o arithmetic addition for boxplot
Hello,
I am having trouble asking R to read individual numeric vectors for a box
plot of the residuals of a linear regression. It is performing arithmetic
addition on the 16 individual variables that I want individual box plots
for.
I have 16 race*treatment variables that were created from cleaned
data.frames for race and treatment independently: t1W, t1B.....t4W, t4B,
t4H, t4O.
class(t1W)
2009 Jan 22
2
How to Run R Programs in a Scheduled Way
Hello R Experts,
does anyone know how to run R programs automatically using the window
scheduler?
I want to run some R programs automatically and make the results available
via web.
Mit freundlichen Grüßen / Best Regards / С наилучшими пожеланиями /
üdvözlettel
Thorsten
[[alternative HTML version deleted]]
2013 Aug 08
13
[LLVMdev] Convert fdiv - X/Y -> X*1/Y
I would like to transform X/Y -> X*1/Y. Specifically, I would like to
convert:
define void @t1a(double %a, double %b, double %d) {
entry:
%div = fdiv fast double %a, %d
%div1 = fdiv fast double %b, %d
%call = tail call i32 @foo(double %div, double %div1)
ret void
}
to:
define void @t1b(double %a, double %b, double %d) {
entry:
%div = fdiv fast double 1.000000e+00, %d
%mul = fmul
2013 Aug 08
3
[LLVMdev] Convert fdiv - X/Y -> X*1/Y
I remember why I didn't implement this rule in Instcombine. It add one
instruction. So,
this xform should be driven by a redundancy eliminator if you care code
size.
On 8/8/13 10:13 AM, Shuxin Yang wrote:
> I did few transformation in Instruction *InstCombiner::visitFDiv() in
> an attempt to remove some divs.
> I may miss this case. If you need to implement this rule, it is
>
2013 Aug 08
0
[LLVMdev] Convert fdiv - X/Y -> X*1/Y
I did few transformation in Instruction *InstCombiner::visitFDiv() in an
attempt to remove some divs.
I may miss this case. If you need to implement this rule, it is better
done in Instcombine than in DAG combine.
Doing such xform early expose the redundancy of 1/y, which have positive
impact to neighboring code,
while DAG combine is bit blind.
You should be very careful, reciprocal is very
2013 Aug 08
0
[LLVMdev] Convert fdiv - X/Y -> X*1/Y
Hi Chad,
This is a great transform to do, but you’re right that it’s only safe under fast-math. This is particularly interesting when the original divisor is a constant so you can materialize the reciprocal at compile-time. You’re right that in either case, this optimization should only kick in when there is more than one divide instruction that will be changed to a mul.
I don’t have a strong
2013 Aug 08
0
[LLVMdev] Convert fdiv - X/Y -> X*1/Y
On 08.08.2013, at 18:25, Chad Rosier <chad.rosier at gmail.com> wrote:
> I would like to transform X/Y -> X*1/Y. Specifically, I would like to convert:
>
> define void @t1a(double %a, double %b, double %d) {
> entry:
> %div = fdiv fast double %a, %d
> %div1 = fdiv fast double %b, %d
> %call = tail call i32 @foo(double %div, double %div1)
> ret void
>
2009 Apr 16
2
there are fontencoding problem in Sweave
I want write article by russian language using Sweave. For cyrillic text
LaTeX use T2A encoding
\usepackage[T2A]{fontenc}
But in Sweave.sty we find:
\RequirePackage[T1]{fontenc}
It is source of critical problem.
For example Rnw file
$ cat estimation.Rnw
\documentclass[A4paper]{article}
\usepackage[T2A]{fontenc}
\usepackage[utf8]{inputenc}
\usepackage[russian,english]{babel}
2013 Aug 08
0
[LLVMdev] Convert fdiv - X/Y -> X*1/Y
I believe we were under the impression that InstCombine, as a canonicalized/optimizer, should not increase code size but only reduce it.
Minor aside, but you don't need all of fast-math for the IR, just the "arcp" flag, which allows for replacement of division with reciprocal-multiply.
On Aug 8, 2013, at 10:21 AM, Shuxin Yang <shuxin.llvm at gmail.com> wrote:
> I remember
2013 Aug 08
2
[LLVMdev] Convert fdiv - X/Y -> X*1/Y
On Aug 8, 2013, at 9:56 AM, Jim Grosbach <grosbach at apple.com> wrote:
> Hi Chad,
>
> This is a great transform to do, but you’re right that it’s only safe under fast-math. This is particularly interesting when the original divisor is a constant so you can materialize the reciprocal at compile-time. You’re right that in either case, this optimization should only kick in when
2012 Mar 19
2
'Unexpected numeric constant'
Dear R-help,
I am trying to rename the variables in a dataframe, called 'T1A' here.
Seems renaming was successful, but when I call one of the variable I got
error message and I wanted to know why.
The data frame contains 365 rows and 49 columns. I would like to name the
first column `DATE` and the others T0.5, T1, T1.5,...,T24 (as this is a set
of data collected every half hour for a
2006 Nov 07
3
Reformat a data frame
Hello Experts,
how do I reformat a data frame in the way described below:
df1:
ID desc resist thick temp
1 4711 100 5 20
2 4712 101 4 21
3 4711 99 3 19
4 4712 98 7 22
TO
df2:
id desc Param Value
1 4711 resist 100
1 4711 Thick 5
1 4711 temp 20
2 4712 resist 101
2 4712 Thick 4
2 4712 temp 21
3
2006 Oct 05
2
Variables in RODBC environment
Hello Experts,
how can I use variables in the RODBC environment.
Example which does not work:
Thanks for your help.
Thorsten
pn <- '39R5238';
library(RODBC);
odbcobj <- odbcConnect("SQUIT21C",uid="muehge",pwd="xxx");
sql <- "select
u.unitid,
from test
where part in ('pn')
";
parameter <- sqlQuery(odbcobj,sql);
2008 May 19
1
reshape a wide data frame from wide to a long format with metadata columns
Hello R users and developers,
I have a general question about reshaping a wide data frame using the
"reshape" command. I have a data frame consisting of 108 columns that
I would like to convert to a long table and remove the metadata
(embedded in the column names of the wide table) to new metadata
columns in the long format.
#example data frame. NOTE column names contain metadata::
2007 Sep 10
0
Loop and loop output [Cox model, for, function, loglik]
Dear R users,
Below I have written 4 functions CIT1, CIT2a and CIT2b and CIT3 which
recode a variable CLD_ISCH into 3 new variables(T1 T2 T3), I wish to use
T1, T2 and T3 based on the values of tf1 and tf2.
(NOTE:- T2a is used to create T2 in a long winded manner due to my lack
of programming experience)
I then attach T1 T2 and T3 to a dataset KidneyT that contains other
variables i wish to use
2009 Apr 16
0
there are fontencoding problem in Sweave
On 4/16/2009 10:29 AM, ?????? n/a wrote:
> I want write article by russian language using Sweave. For cyrillic text
> LaTeX use T2A encoding
>
> \usepackage[T2A]{fontenc}
>
> But in Sweave.sty we find:
>
> \RequirePackage[T1]{fontenc}
>
> It is source of critical problem.
>
> For example Rnw file
>
> $ cat estimation.Rnw
>
>
2012 May 02
3
strange differences in vector operation versus manual calculation
Hi, I'm running a calculation in two ways. The first way is to employ
vectors and evaluate a function in one go. The second way is to break
down the function into pieces and combine the pieces to the final
answer.
Algebraically, they should give me the same result. But the final
vector differs significantly. I must be missing something very
obvious, but I just cannot see it
xx <-