similar to: From strings to numbers

Dear All, a short and maybe simple question: I have to rank all values in a matrix from 0 to X, [1] [2] [3] [4] [1] 0.1 2 0 3 [2] 50 3 3 1 [3] 100 1 1 0 [4] 100 2 2 0 0->0 0.1->1 2->2 3->3 50->4 100->5 (X=5) is there any function for this? i have looked in several packages (vegan, labdsv etc.) because I am working with species by site tables,

Dear all, I would like to know whether it is possible to unlist elements and keep the original format of the data. To make it more clear, let me give an exemple: I have a list l of dataframes that I created with apply but which looks like this: x1=data.frame(Name=LETTERS[1:2],Age=1:2) x2=data.frame(Name=LETTERS[3:4],Age=3:4) l=list(x1,x2) l [[1]] Name Age 1 A 1 2 B 2 [[2]] Name

Hello! I have a data frame with dates. I need to create a new "month" that starts on the 20th of each month - because I'll need to aggregate my data later by that "shifted" month. I wrote the code below and it works. However, I was wondering if there is some ready-made function in some package - that makes it easier/more elegant? Thanks a lot! # Example data:

Hi, I have loaded a dataset in R : data = label freq1 freq2 news 54 35 fun 37 21 milk 19 7 food 3 3 .... etc And I have a vector flist<-c("fun","food") Now I want to use the vector 'flist' for selecting these values from 'data' so that I get the following dataset : label freq1 freq2 fun 37 21 food

Hello, How ls() only functions or only data objects (basically anything other than functions) such as data.frame, numeric ...? John [[alternative HTML version deleted]]

Hi, I am trying to create a power curve to show how the power of a t-test varies depending on the mean. Any ideas how I should go about this? Louisa _________________________________________________________________ [[alternative HTML version deleted]]

Hi R Users, Simple question: How might I convert the text "a, b, c" (or for that matter "a b c" with any delimiter - space, comma, etc.) into a 3-element character vector? [1] a b c Thanks, Brad

i have a data set with repeated measures on same people, structure like below: id x1 x2 ... 001 10 20 ... 001 8 45 ... 001 4 2 ... 002 .... 002 ... 002 .... 002 .... 003 .... ....... what is the easist way to show how many observations for each subject id? [[alternative HTML version deleted]]

Hello I have a dataset in which I would like to replace 0s with NAs. There is a lot of information on how to replace NAs with 0, but I have struggled to find anything with regards to doing the reverse. Any recommendations would be great. Cheers Christine

Dear Listers, I am wondering how to convert multiple dummy variables to 1 factor variable. Thanks. wensui

Hi folk, I tried this and it works just perfectly tapply(iris[,1],iris[5],mean) but, how to obtain a single table from multiple variables? In tapply x is an atomic object so this code doesn't work tapply(iris[,1:4],iris[5],mean) Thanx and great summer holidays Gianandrea -- View this message in context: http://www.nabble.com/multiple-tapply-tp18868063p18868063.html Sent from the R help

Hello, I'm new to R, I've been working with it for the last 2 weeks. I am plotting some data and not getting the labels on the x axis I am expecting on my plot. my code reads #hours in the day h <- c(0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23) #hp is a data frame with a pivot table of 25 columns (label and data for 24 hours) plot(h, as.matrix(hp[1,2:25]),

Dear R users I have a very basic question. I tried but could not find the required result. using dat <- pima f <- table(dat[,9]) > f 0 1 500 268 i want to find that class say "0" having maximum frequency i.e 500. I used >which.max(f) which provide 0 1 How can i get only the "0". Thanks and best regards Muhammad Azam Ph.D. Student Department of

Good afternoon Running R2.10.0 on Windows I have a data frame that includes (among much else) a factor (In_2006) and a continuous variable (math_3_4). I would like to find the 2 cases for In_2006 = 0 that are closest to each case where In_2006 = 1. My data looks like In_2006 math_3_4 0 55.1 1 51.6 1 18.1 1 26.6 1 14.1

Dear R experts, Wish you all a HAPPY NEW YEAR! How do I go about plotting (using lattice) overlays of an ID (group=ID) observed, fitted data in each panel of a multiple panel plot (each panel identified by DS1 + DS2 + DS3)? "x" variable is X1 in the accompanying section of a dataset. each individual is identified by color and Y's are identified by "pch" or "lty".

Dear list, I have a vector (array, table row, whatever is best) of frequency values for categories (or bins), and I need to find the median category. Trivial to do by hand, but I was wondering if there is a means to do it in R in an elegant way. The obvious medioan(vector) returns the median frequency for the binns, and that is not what I want. i.e,: freq cat1 1 cat2 10

Hi All: I have a seemingly typical SPSS data file with 219 rows and 486 variables. When I attempt to read this file into R with read.spss() in the foreign package, I consistently get a "crash". This is the sequence of events: > library(foreign) > sessionInfo() R version 2.7.1 Patched (2008-07-24 r46120) i386-pc-mingw32 locale: LC_COLLATE=English_United

Hi Everyone, I am trying to use lmFit function; however, i cannot find it function anywhere. I have been trying to find the function in Bioconductor and elsewhere. I re-install bioconductor source, update package and update R as well. no luck Is there a command in R where i can just type, and it will download it for me? -- View this message in context:

I have a data set where I want the correlations between 2 variables conditional on a students grade level. This code works just fine. by(tmp[,c('mtsc07', 'DCBASmathscoreSPRING')], tmp$Grade, cor, use='complete', method='pearson') However, this generates an error by(tmp[,c('mtsc07', 'DCBASmathscoreSPRING')], tmp$Grade, cor, use='complete',

Hello! I have a data frame with a factor and a numeric variable: x<-data.frame(factor=c("b","b","d","d","e","e"),values=c(1,2,10,20,100,200)) For each level of "factor" - I would like to divide each value of "values" by the mean of "values" that corresponds to the level of "factor" In other