similar to: dataframes to a list

Hi R, A quick question: How do we find the number of words in a string? Example: C="Have a nice day" And the number of words should be 4. any built in function or?... Thanks, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com This e-mail may contain

Hi, Suppose a=matrix(1:9,3,3) > a [,1] [,2] [,3] [1,] 1 4 7 [2,] 2 5 8 [3,] 3 6 9 Now, > class(a[1:2,]) [1] "matrix" > class(a[1:3,]) [1] "matrix" > class(a[,1:2]) [1] "matrix" > class(a[,1:3]) [1] "matrix" But, > class(a[1,]) [1] "integer" > class(a[,1]) [1]

Hi R, A simple question, but don't know the answer... x="a" a=5 I need to remove the object "a" by using only x. something like rm(somefunction(x))...Is this possible? Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com This e-mail may contain

Hi R, This is a very trivial one.... C=0.1 I want to check whether my value of C is between 0 and 1 exclusively.... I don't want to use (C>0 & C<1). And I can't use a single statement like (0<C<1). Is there a between function? Or how do we specify from 0 to 1? Does %in% help me? Many Thanks, Shubha This e-mail may contain confidential and/or

Hi R, Can I get a comparison between R and MATLAB? How is R efficient than MATLAB? Or what are the weaknesses of R compared to MATLAB? Thank you very much for your help, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com This e-mail may contain confidential and/or

Hi R, Again struck with regular expressions... Suppose, S=c("World_is_beautiful", "one_two_three_four","My_book") I need to extract the last but one element of the strings. So, my output should look like: Ans=c("is","three","My") gsub() can do this...but wondering how do I give the regular expression....

Hi R, I have a 100th order equation for which I need to solve the value for x. Is there a package to do this? For example my equation is: (x^100 )- (2*x^99) +(10*x^50)+.............. +(6*x ) = 4000 I have only one unknown value and that is x. How do I solve for this? BR, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore *

Hi R, I have certain checkings, which gives FALSE, but actually it is true. Why does this happen? Note that the equations that I am checking below are not even the case of recurring decimals... > 1.4^2 == 1.96 [1] FALSE > 1.2^3==1.728 [1] FALSE Thanks in advance, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo *

Hi, Can somebody tell me the formula for "?wilderSum" in TTR package? I mean how are these calculated? BR, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com This e-mail may contain confidential and/or privileged i...{{dropped:13}}

Hi R, I have a list, l=list(list(c(1,2),c(4,5),c(6,7)),list(c(11,22,33),c(44,55,66))) > l [[1]] [[1]][[1]] [1] 1 2 [[1]][[2]] [1] 4 5 [[1]][[3]] [1] 6 7 [[2]] [[2]][[1]] [1] 11 22 33 [[2]][[2]] [1] 44 55 66 How do I know the dimensions of this list?... In other words, how many sub-lists, sub-sub-lists etc...are there in l? How do I know this?

Hi R, I am trying to download the data from R. I give the below command. > library(fImport) > yahooSeries("IBM") trying URL 'http://chart.yahoo.com/table.csv?s=IBM&a=7&b=08&c=2007&d=7&e=07&f=2008& g=d&x=.csv' Error in download.file(url = url, destfile = file, method = method) : cannot open URL

Hi R, I have the variance-covariance matrix, >V=matrix(c(0.011119238, 0.002407527, 0.002407527, 0.020739401),2,2) I need to find a vector X=c(x1,x2), such that 1) X'VX is equal to a constant 2 (say) and 2) sum(x) should be equal to a another constant 1.5 (say). How do we do this in R? BR, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94

Hi R, I was experimenting with the CA package for correspondence analysis. data(author) ca(author) plot(ca(author)) How can I get the values used by the plot for the two axis for biplot? In other words, how will I be able to obtain the scores in the dimensions (which are obtained by PCA) of the graphs? Thanks. Thanks and Regards, Shubha This e-mail may contain

Can I call R from SAS? I tried the below command in SAS, but not working... OPTIONS XWAIT XSYNC; X "C:\Program Files\R\R-2.7.1\bin\R.exe --no-save -quiet <""C:\TEMPO\program.r""> ""C:\TEMPO\program.log"""; Had done this before and it was working perfect... But now, not... Sorry if this query was supposed to be put in SAS mailing

Hi all, Just like Fortran creates EXE files for a code, can R also do the same? Thanks for the info. Thanks and Regards, Shubha Karanth | Amba Research Ph +91 80 3980 8283 | Mob +91 94 4886 4510 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com This e-mail may contain confidential and/or privileged i...{{dropped:13}}

Hello everybody, I would like to read a SAS Data data1.sas7bdat in R! Is this possible? Thank you a lot in advance ;), Stefo

Hi R, If x=c(1,3,5) y=c(2,4,6) I need a vector which is c(1,2,3,4,5,6) from x and y. How do I do it? I mean the best way.... Thanks, Shubha This e-mail may contain confidential and/or privileged i...{{dropped:13}}

Hi R, I need to generate 50 random numbers (preferably poisson), such that their sum is equal to 100. How do I do this? Thank you, Shubha This e-mail may contain confidential and/or privileged i...{{dropped:13}}

Hi R, I have a request... Can I call R functions/routines from C# or C++? If so, how do I do this? Do I need to have some knowledge on DLL to do this? Thanks a lot for your help, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com This e-mail may contain

Hi R, Let, x=1:80 I want to sum up first 8 elements of x, then again next 8 elements of x, then again another 8 elements..... So, my new vector should look like: c(36,100,164,228,292,356,420,484,548,612) I used: aggregate(x,list(rep(1:10,each=8)),sum)[-1] or rowsum(x,group=rep(1:10,each=8)) But without grouping, can I achieve the required? Any other ways of doing