similar to: positioning of color key in levelplot

Displaying 20 results from an estimated 3000 matches similar to: "positioning of color key in levelplot"

2009 Sep 20
2
missing level of a nested factor results in an NA in lm output
Hello All, I have posted to this list before regarding the same issue so I apologize for the multiple e-mails. I am still struggling with this issue so I thought I'd give it another try. This time I have included reproducible code and a subset of the data I am analyzing. I am running an ANOVA with three factors: GROUP (5 levels), FEATURE (2 levels), and PATIENT (2 levels), where
2008 Jul 07
1
GLM, LMER, GEE interpretation
Hi, my dependent variable is a proportion ("prob.bind"), and the independent variables are factors for group membership ("group") and a covariate ("capacity"). I am interested in the effects of group, capacity, and their interaction. Each subject is observed on all (4) levels of capacity (I use capacity as a covariate because the effect of this variable is normatively
2011 Apr 30
1
More flexible aggregate / eval
Dear list, I would like to do some calculation using different grouping variables. My 'df' looks like this: # Some data set.seed(345) id <- seq(200,400, by=10) ids <- sample(substr(id,1,1)) group1 <- rep(1:3, each=7) group2 <- rep(1:2, c(10,11)) group3 <- rep(1:4, c(5,5,5,6)) df <- data.frame(id, ids, group1, group2, group3) df <- rbind(df, df, df) df$time <-
2005 Jun 24
1
lme4 extracting individual variance components
Hi, For further calculations I need to extract indivdual Variances of different random effects from a fitted model. I found out how to extract the correlations (VarCorr(m1)@reSumry$group1) but I was not able to find a way to extract the other components individually. To extract the Residuals I tried: (ranef(m1)@ stdErr) which unfortunately did not work. Thank you very much for your help!
2012 Jun 16
2
aligning axis labels in a colorkey from levelplot
R does a great job with the fine details regarding plots. e.g in the following: library(lattice) y <- -4:4/10 xyplot(y~1, las=1) the y axis is labelled with numbers -0.4, -0.2, 0.0, 0.2, 0.4 with the numbers aligned on the decimal point. How do I get the same behaviour in the colorkey of a levelplot? e.g. levelplot(matrix(y,3,3)) the numbers in the colorkey seem left-aligned, and
2005 Jan 27
3
clustering
Hi, I just get a question (sorry if it is a dumb one) and I "phase" my question in the following R codes: group1<-rnorm(n=50, mean=0, sd=1) group2<-rnorm(n=20, mean=1, sd=1.5) group3<-c(group1,group2) Now, if I am given a dataset from group3, what method (discriminant analysis, clustering, maybe) is the best to cluster them by using R. The known info includes: 2 clusters,
2004 Apr 27
1
helps on levelplot
I'm a new user of levelplot, and are not familiar with the terminology very well. Is the bar alongside the levelplot indicating color or shade call "colorkey"? I have to adjust the size of its label, but couldn't make it so far. This is how I did: levelplot(z~x*y, grid, at=seq(0,1,by=0.1), colorkey=list(labels=list(cex=2))) But I got error message "Error in
2020 Jun 16
2
Samba as a domain member:
Yes: # getent group GROUP group:x:17573: # getent group group2 group2:x:11010: # getent group GROUP3 group3:x:21178: # wbinfo --group-info GROUP group:x:17573: # wbinfo -n GROUP S-1-5-21-948789634-15155995-928725530-7573 SID_DOM_GROUP (2)
2011 Aug 17
3
How to apply a function to subsets of a data frame *and* obtain a data frame again?
Dear all, First, let's create some data to play around: set.seed(1) (df <- data.frame(Group=rep(c("Group1","Group2","Group3"), each=10), Value=c(rexp(10, 1), rexp(10, 4), rexp(10, 10)))[sample(1:30,30),]) ## Now we need the empirical distribution function: edf <- function(x) ecdf(x)(x) # empirical distribution function evaluated at x ##
2004 Feb 11
1
levelplot colorkey
Dear R'ers, I've scanned available documentation and the web, but I can't seem to figure out where I've gone wrong in adding numbers to scale the colorkey in levelplot (Lattice package). For example, levelplot(z, contour=T, labels=T, cuts=10, region=T,... colorkey=list(T, space="bottom", at=seq(0,2000,length=20),
2008 Nov 24
1
No write permission if POSIX bits 0 on ZFS written by M$ Office - dos_mode returning r
Hi all, I'd appreciate any pointers or advise regarding the following issue with files written by M$ Office on Samba 3.0.32 on snv_98 (OpenSolaris) on a ZFS filesystem: samba share: [sharename] read only = No browseable = yes writeable = yes directory mask = 0770 create mask = 0770 delete readonly = Yes acl check permissions =
2007 Jul 19
3
Can I test if there are statistical significance between different rows in R*C table?
Dear friends, My R*C table is as follow: better good bad Goup1 16 71 37 Group2 0 4 61 Group3 1 6 57 Can I test if there are statistical significant between Group1 and Group2, Group2 and Group3, Group1 and Group2, taking into the multiple comparisons? The table can be set up using the following program: a<-matrix(data=c(16,71,37,0,4,61,1,6,57),nrow=3,byrow=TRUE) Thanks
2009 Aug 28
1
how to explain the interaction terms regarding "treatment contrast" of lm model
Dear list, I am confused on how to explain the interaction term in the context of "treatment contrast". for example, I have an data frame as below: sub group val 1 a group1 3.685625 2 a group1 3.407445 3 a group1 4.040920 4 a group1 2.890875 5 b group1 3.853280 6 b group1 4.113585 7 b group1 3.043250 8 b group1 3.800920 9 c group1 5.394305 10 c
2004 May 23
1
A (maybe)_ easy solution to global login script for group checking
Hello While searching the archives and googling for : -login script to map drives according to group membership I saw lots of complicated solutions (on-the-fly scripts, group directories) etc. but the following works very well for me: I downloade dthe ifmember.exe from the microsoft website, and stuck it in the netlogon directory (not the scripts directory)
2011 Apr 06
2
Layout within levelplot from the lattice package
Hi, I'm a novice with levelplot and need some assistance! Basically, I want a window which contains 6 levelplots of equal size presented in 3 columns and 2 rows. I've tried to approach it two ways. The first way leads to this question: Is there any way to concatenate levelplots from a factor vertically as opposed to horizontally? I'd like to pair the levelplots by factor.2 on
2011 Jul 06
1
How to compare ratio from multiple groups?
If I have 3 groups,and for each group,I get the ratio(e.g. incidence rate). Now I wanna compare 3 ratio pairwise,and get the corresponding p values,i.e: group1 vs group2 ,p value=? group1 vs group3 ,p value=? group2 vs group3 ,p value=? Which statistical test should be used? Thanks a lot for your help. [[alternative HTML version deleted]]
2007 Oct 31
3
thicker axis in levelplot
Dear R-help community, I need to find out how to make the black axis line around my plot thicker in levelplot, I cannot find the correct command in ?levelplot or ?par - or if it is there I cannot get it to work - any help would be more that appreciated! Here's an example script - I would want the code for making the axis bordering the plot thicker: x<- seq(pi/4, 5*pi,length=100)
2007 Oct 30
2
flexible processing
Hello, unfortunately, I don't know a better subject. I would like to be very flexible in how to process my data. Assume the following dataset: par1 <- seq(0,1,length.out = 100) par2 <- seq(1,100) fac1 <- factor(rep(c("group1", "group2"), each = 50)) fac2 <- factor(rep(c("group3", "group4", "group5", "group6"), each =
2012 Jan 06
1
Can levelplot colorkeys display a logarithmic scale evenly?
I'm using the {lattice} "levelplot" function to make a (more or less) 2-d histogram, and for the most part it's working fine with my data. However, I can't get the color key to do what I need. I can give it labels and custom cutoffs, but my cutoff lines (and hence my labels) aren't evenly spaced, instead they're more-or-less logarithmic, starting at
2010 Nov 11
1
exploratory analysis of large categorical datasets
Dear List, I am looking to perform exploratory analyses of two (relatively) large datasets of categorical data. The first one is a binary 80x100 matrix, in the form: matrix(sample(c(0,1),25,replace=TRUE), nrow = 5, ncol=5, dimnames = list(c( "group1", "group2","group3", "group4","group5"), c("V.1", "V.2", "V.3",