Displaying 20 results from an estimated 4000 matches similar to: "interpreting significance of path coefficients from sem() output"
2008 Jul 06
2
Issue with postscript figures using WinAnsi encoding
Hi there,
I've hit a bump in writing postscript files with special characters in
the WinAnsi encoding on a windows machine.
Here's some sample code:
###########################################
postscript(file = "test.eps", encoding="WinAnsi.enc",
width = 3, height = 5.5, onefile = TRUE, horizontal=FALSE, family =
"sans",
title =
2008 Jul 09
2
sorting a data frame by rownames
Hi there,
I'm sure there's an easy answer to this, and I can't wait to see it.
The question: is there an easy way to sort a data frame by it's row names?
My dilemma:
I've had to pull apart a data frame, run it through a loop to do some
calculations and generate new variables, and then re-construct the chunks
back into a data frame at the end.
Doing this preserves the row
2008 Jul 15
2
extracting elements from print object of Manova()
Hi there,
Does anyone know how to extract elements from the table returned by Manova()?
Using the univariate equivalent, Anova(), it's easy:
a.an<-Anova(lm(y~x1*x2))
a.an$F
This will return a vector of the F-values in order of the terms of the model.
However, a similar application using Manova():
m.an<-Manova(lm(Y~x1~x2))
m.an$F
Returns NULL. So does any attempt at calling the
2008 Jul 15
1
manipulating (extracting) data from distance matrices
Hi all,
Does anyone have any tips for extracting chunks of data from a distance matrix?
For instance, if one was interested in only a subset of distance
comparisons (i.e., that of rows 4 thru 6, and no others), is there a
simple way to pull that data out?
>From some playing around with an example (below), I've been able to
figure out that a distance matrix in R is stored as a single
2007 Apr 05
1
Indexing in anova summary output of the form: summary(aov(y ~ x1, Error = (x1/x2)))
Hi, there
I'm trying to get the value of the Mean Square from the ANOVA model
summary that comes from specifying the error term, and am wondering if
one can actually do this ( I know it's possible when using anova(lm)
objects and the like, but I'm having a tough time with it under this
framework). There does appear to be some indexing in the output of this
type, but perhaps not
2007 Feb 12
1
Trying to replicate error message in subset()
Hi, there
I am trying to replicate an error message in subset() to see what it is
that I'm doing wrong with the datasets I am trying to work with.
Essentially, I am trying to pass a string vector to subset() in order to
select a specific collection of cases (i.e., I have data for these cases in
one table, and want to select data from another table that match up with
the cases in the
2007 Jan 23
1
How to evaluate an lm() object for generating warning statement in a function
Hi, there
I tried this post on R-help but did not generate any replies, so I thought
I might try the waters here since it's a more programming-based group.
I have written a function that will allow me to calculate the variance
components for a model II (random effects) single factor ANOVA (perhaps
this is
me re-inventing the wheel, but I handn't yet come across anything in R that
does
2007 Feb 01
2
Losing factor levels when moving variables from one context to another
Hi, there
I'm currently trying to figure out how to keep my "factor" levels for a
variable when moving it from one data frame or matrix to another.
Example below:
vec1<-(rep("10",5))
vec2<-(rep("30",5))
vec3<-(rep("80",5))
vecs<-c(vec1, vec2, vec3)
resp<-rnorm(2,15)
dat<-as.data.frame(cbind(resp, vecs))
2007 Jan 22
0
Advice on an appropriate condition for warning in a function
Hi, there
I have written a function that will allow me to calculate the variance
components for a model II (random effects) single factor ANOVA (perhaps this is
me re-inventing the wheel, but I handn't yet come across anything in R that
does this for me, but I'm sure people will let me know from this posting if
there are). The function takes as it's argument an object which holds
2018 Jan 06
4
Error occurring in "emmeans" package for the two data sets I used. Please help.
I am a Professor of Statistics at Indira Gandhi Krishi Vishwavidyalaya,
Raipur, India. While teaching in class about analysis of variance using R,
I was doing a one-way analysis for the two data-sets given below in the
R-class. I got a typical error in "emmeans" package, please help:
Data-set-1:
--------------
Medley and Clements (1998) investigated the impact of zinc contamination
(and
2018 Jan 08
0
[FORGED] Error occurring in "emmeans" package for the two data sets I used. Please help.
On 07/01/18 02:19, Akhilesh Singh wrote:
> I am a Professor of Statistics at Indira Gandhi Krishi Vishwavidyalaya,
> Raipur, India. While teaching in class about analysis of variance using R,
> I was doing a one-way analysis for the two data-sets given below in the
> R-class. I got a typical error in "emmeans" package, please help:
>
> Data-set-1:
> --------------
2018 Jan 10
0
[FORGED] Error occurring in "emmeans" package for the two data sets I used. Please help.
Thanks for your kind reply. Problem is solved. However, it's "confidence
interval / treatment comparison plot" is not taking main title. And the
fonts of axes labels can not be changed using 'cex' parameter. I will
appreciate if you could help in this matter too.
Dr. A. K. Singh
On 09-Jan-2018 8:18 PM, "Sal Mangiafico" <salvatore.s.mangiafico at gmail.com>
2007 Jan 26
1
plotting results from tapply
Hi, there
I'm trying to plot what is returned from a call to tapply, and can't figure
out how to do it. My guess is that it has something to do with the
inclusion of row names when you ask for the values you're interested in,
but if anyone has any ideas on how to get it to work, that would be
stellar. Here's some example code:
y1<-rnorm(40, 2)
x1<-rep(1:2, each=20)
2008 Jul 09
1
matplot help
Hi,
My question is how do I gain control over what values the X and Y axis show. Below is a sample plot I have made and want the X axis to represent a time vector with values taking the form Q1.60, Q2.60, Q3.60...Q1.90..etc...Currently the X axis starts with value 0 and increases by 1 through the end of the sample.
win.graph()
matplot(v.0,log.diff.v.6,type="l",lty=1, col=2,
2004 Mar 04
3
Testing significance in a design with unequal but proportional sample sizes
Hi, all
I have a rather un-ideal dataset that I am trying to work with, and would
appreciate any advice you have on the matter.
I have 4 years worth of data taken at 3 depth-zones from which samples have
been taken at random. I am looking at the abundance of organism A between depth
zones and across years, and am interested in the possible interaction of
organism A distributions shifting
2004 Jul 29
1
Kudos to the R support team
Hi there,
I just wanted to take a quick second to thank everyone who maintains this
service- just in case you don't hear it enough, there are a plethora of people
who rely on this service (as evidenced by the help archives), and even if they
don't say it, are greatly thankful for what you do here. Not only are you
providing a service to people who are learning R, but indeed helping
2003 Jun 30
3
if else statements in R
Hi, there
I am a grad student struggling to get my syntax right in a model I am
building in R.
I am trying to specify a variable,W, in a loop, such that on the first
iteration, it is equal to Wo, my starting value, which I have already
specified with
Wo<-9.2
On any other iteration other than the first, I want W to equal the
previous value of W in the iteration. plus an increment from
2008 Feb 24
2
mixed model nested ANOVA (part two)
First of all thank you for the responses. I appreciate the
suggestions i have received thus far.
Just to reiterate
I am trying to analyze a data set that has been collected from a
hierarchical sampling design. The model should be a mixed model
nested ANOVA. The purpose of my study is to analyze the variability
at each spatial scale in my design (random factors, variance
components), and say
2008 Jul 15
4
Iterations
I have a command that reads in some data:
x <- read.csv("Sales2007.dat", header=TRUE)
Then I try to organize the data:
sc <- split(x, list(x$Category, x$SubCategory), drop=TRUE)
Then I want to iterate through the data. I was able to get the following to run on the R console:
for(i in 1:length(sc))
{
sum(sc[[i]]$Quantity)
}
But notiing is primted on the console. I find
2008 May 09
3
Query: how to add quotes when importing a txt file
Dear R users,
I have a txt file of the form
10092007 24.62 24.31 24.90
11092007 19.20 23.17 22.10
13092007 24.71 27.33 23.10
14092007 27.33 27.90 24.10
15092007 28.22 28.55 24.30
16092007 28.53 29.24 27.40
17092007 24.19 30.64 26.80
18092007 22.60 20.62 28.40
19092007 8.89 1.70 14.70
20092007 21.27 2.92 17.30
21092007 22.38 24.72 8.80
22092007 23.94 24.73 20.40
23092007 25.33 25.12 22.60