Displaying 20 results from an estimated 90 matches similar to: "Plotting Dendrogram Help Getting Plot to Display Neatly"
2005 Dec 16
2
dendrogram branches with different lty
Dear r-list,
I am trying to visually seperate the two main clusters of a dendrogram.
The idea is to use:
'edgePar=list(lty=3)' for 'dend1[[1]]' and
'edgePar=list(lty=1)' for 'dend1[[2]]'
I have not found a way to solve this. Any suggestions?
Patrick
hc <- hclust(dist(USArrests), "ave")
(dend1 <- as.dendrogram(hc))
par(mfrow=c(2,2))
plot(dend1)
2011 Dec 12
1
how to colour labels (each label with a colour) in a dendrogram?
Hello to all,
I still have this doubt.
I'd like to colour the different labels of my dendrogram each one with a
different colour. How can I do? I guess I could do using *edgetext* and
then *t.col* or* lab.col* but I don't know how to add edgetext to my
dendrogram. Can you help me please?
Example:
require(graphics); require(utils)
hc <- hclust(dist(USArrests), "ave")
(dend1
2005 Jul 11
1
indexing into and modifying dendrograms
I would like to be able to exert certain types of control over the
plotting of dendrograms (representing hierarchical clusterings) that I
think is best achieved by modifying the dendrogram object
prior to plotting. I am using the "dendrogram" class and associated
methods.
Define the cluster number of each cluster formed as the corresponding
row of the merge object. So, if you are
2008 Jun 02
1
Plotting horizontal dendrograms
I am using hclust and plot to produce dendrograms. Using my input data I am
able to complete an analysis and obtain a vertical plot.
I want to be able to plot the dendrogram horizontally.I am using version 2.6
of R and have updated my packages recently.
Using the sample script for dendrograms I can produce a horizontal plot
using the instruction horiz = TRUE in plot().
When I use the same
2007 Oct 26
2
cut.dendrogram and cutree
Hi!
In the example:
hc <- hclust(dist(USArrests), "ave")
dend1 <- as.dendrogram(hc)
dend2 <- cut(dend1, h=70)
Do the branches "Branch 1", "Branch 2", "Branch 2"...in dend2$upper
str(dend2$upper)
--[dendrogram w/ 2 branches and 4 members at h = 152]
|--[dendrogram w/ 2 branches and 2 members at h = 77.6]
| |--leaf "Branch 1" (h=
2008 Sep 04
1
text file imported incorrectly
Dear R-users,
When I tried to import a text file (tab delimited) which has 2000+ rows with the following command (With the importData in S, it works though),
x <- read.table(textfile, sep= "\t", skip=5, stringAsFactors=F)
I received the following warning message: Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings,: number of items read is not a multiple of
2007 Jun 13
2
Formatted Data File Question for Clustering -Quickie Project
I am trying to learn how to format Ascii data files for scan or read
into R.
Precisely for a quickie project, I found some code (at end of this
email) to do exactly what I need:
To cluster and graph a dendrogram from package (stats).
I am stuck on how to format a text file to run the script.
I looked at the dataset USArrests (which would be replaced by my data
and labels) using UltraEdit. That
2011 Dec 09
1
how to add an edgetext to a dendrogram?
Hello to all,
I'd like to colour the different labels of my dendrogram. How can I do? I
guess I could to using *edgetext* and then* t.col* or *lab.col* but I don't
know how to add edgetext to my dendrogram. Can you help me please?
Example:
require(graphics); require(utils)
hc <- hclust(dist(USArrests), "ave")
plot(dend1)
labels (USArrests) [[1]] # to know how many cities
2003 Mar 24
1
how to show a section of a matrix neatly (or row by row) that satisfies some condition
Hi all,
I want to show the rows of a matrix (100x3) of which some of its elements satisfy a certain condition. In particular, how can I display the 2 rows of my matrix one after the
other and not all all elements of column 1 first, then column 2 and so on. See the following.
> finest[finest[,1] > 10^3]
[1] 4.960632e+13 3.612619e+04 7.668204e+12 1.001911e+04 8.886153e-01
[6]
2003 Mar 24
0
how to show a section of a matrix neatly (or row by row ) that satisfies some condition
You're missing a comma in the subscript. The comma tells it that your test
is for the appropriate rows.
You want: finest[finest[,1] > 10^3,]
Hope this helps,
Matt Wiener
-----Original Message-----
From: Edmond Ng [mailto:Edmond.Ng at lshtm.ac.uk]
Sent: Monday, March 24, 2003 2:40 PM
To: r-help at stat.math.ethz.ch
Subject: [R] how to show a section of a matrix neatly (or row by row)
2013 May 29
1
remove rails application safely and neatly on debian server
Hi all, maybe it will be a strange question but as a sysadmin , I have to
move a rails application with his environnement from a server to
another(vps) . I would like know how can I clean correctly and safely the
old server (the application is using bundle and erbenv and stuff). i would
like to know how I can remove all code and library safely.
Thanks
Aina Anjary Fenomamy
--
You received
2011 Jan 25
1
dendrogram plot does not draw long labels ?
Hello,
It seems that the plot function for dendrograms does not draw labels when
they are too long.
> hc <- hclust(dist(USArrests), "ave")
> dend1 <- as.dendrogram(hc)
> dend2 <- cut(dend1, h=70)
> dd <- dend2$lower[[1]]
> plot(dd) # first label is drawn
> attr(dd[[1]], "label") <- "aaaaaaaaaaaaaaaaaa"
> plot(dd) # first label is
2012 Apr 30
2
Generate Dendrogram
Hi
I have a distance matrix which is computed by user defined method. I
would like to plot the dendrogram. I would like to use different color
and want the leaves laying down bottom.
The script like this. I am not familiar with R. I followed the example
shown in
http://stat.ethz.ch/R-manual/R-devel/library/stats/html/dendrogram.html
dist.obj <- as.dist(matrix.distance)
hc.obj <-
2002 Mar 05
1
no labels when plotting dendrograms
I'd like to be able to cut dendrograms at a height I specify
and then plot the resulting subtrees. I wanted to use the
dendrogram object for this purpose because there doesn't seem
to be a canned way to cut a hclust object and get a list of
hclust objects, but there is a function (cut) that does that
for dendrograms. The problem I'm having is that when I plot
a dendrogram, I
2013 May 01
1
help understanding hierarchical clustering
Hi All,
i've problem to understand how to work with R to generate a hierarchical clustering
my data are in a csv and looks like :
idcode,count,temp,sal,depth_m,subs
16001,136,4.308,32.828,63.46,47
16001,109,4.31,32.829,63.09,49
16001,107,4.302,32.822,62.54,47
16001,87,4.318,32.834,62.54,48
16002,82,4.312,32.832,63.28,49
16002,77,4.325,32.828,65.65,46
16002,77,4.302,32.821,62.36,47
2004 May 19
7
Help with hclust() and plot()
Hi
When I use plot(hclust(dist..)...)...) etc to create a dendrogram of a
hierarchial cluster analysis, I end up with a vertical tree. What do I
need to do to get a horizontal tree?
Also, my users are used to seeing trees who's leaves all "end" at the
same place (eg. Like in minitab). Is this possible in R?
Thanks
Mick
Michael Watson
Head of Informatics
Institute for Animal
2012 Oct 24
0
recursive function on a structured list of lists (dendrogram)
Dear all,
I have been trying the following without avail and would be very grateful for any help. From a dendrogram (recursive list of lists with some structure), I would like to obtain some information of the component lists and of the enclosing list at the same time. In dendrogram-speech I basically would like the label of the leaf and the height of the enclosing branch.
A dendrogram example
2009 Nov 05
0
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2012 May 24
4
Manually modifying an hclust dendrogram to remove singletons
Dear R-Help,
I have a clustering problem with hclust that I hope someone can help
me with. Consider the classic hclust example:
hc <- hclust(dist(USArrests), "ave")
plot(hc)
I would like to cut the tree up in such a way so as to avoid small
clusters, so that we get a minimum number of items in each cluster,
and therefore avoid singletons. e.g. in this example, you can see
2009 Nov 16
0
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BIOMETRICS...
THE WINTER 2010 BIOMETRICS SUMMIT:
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Practical Implementation Strategies, Market Trends
And Best Practices In Government And Business
--------------------
February 22-25, 2010 - Miami, FL