similar to: datetime on x-axis of plot

Hello, I'm new to R and would like to know how to create a vector of "rolling sums". (I have seen the Rmetrics package and the rollMean function and I would like to do the same thing except Sum instead of Mean.) I imagine someone has done this, I just can't find it anywhere. Example: x <- somevector #where x is 'n' entries long #what I would like to do is: x1

On 2016-05-25 19:13, Kelly Lesperance wrote: > Hdparm didn?t get far: > > [root at r1k1 ~] # hdparm -tT /dev/sda > > /dev/sda: > Timing cached reads: Alarm clock > [root at r1k1 ~] # Hi Kelly, Try running 'iostat -xdmc 1'. Look for a single drive that has substantially greater await than ~10msec. If all the drives except one are taking 6-8msec, but one is very

I am trying to export a dateframe created in R: > Duration_summary V1 2.5 % 97.5 % V4 2.5 % 97.5 % [1,] 1 0.46076018 1.128776 1.000000 0.5280828 0.9576338 [2,] 0 0.00000000 0.000000 1.000000 0.1741793 1.2352705 [3,] 1 0.46566719 1.313711 1.000000 0.7233312 1.4097987 [4,] 1 0.38866371 2.453226 0.976024 0.6377314 1.3493957 [5,] 1 0.08894066 1.036830

Hi, I'm stuck on creating a plot with x tick labels for every Nth tick mark - how is that done? I don't see a simple solution to this in help(plot) or help(par) and what I've tried is not working, eg, the following does not work, although it seems intuitive to me that it should work: x <- seq(-100,1000,25) y <- x * x % find all the x values that are multiples of 100 tmp <-

Hello I have the following problem : The dataframe TEST has multiple lines for a same person because : there are differents values of Nom or differents values of Prenom but the values of Matricule or Sexe or Date.de.naissance are the same. TEST <- structure(list(Matricule = c(66L, 67L, 67L, 68L, 89L, 90L, 90L, 91L, 108L, 108L, 108L), Nom = structure(c(1L, 2L, 2L, 4L, 8L, 5L, 6L, 9L, 3L, 3L,

If I have 2 data frames; df1: dim(df1) = (1,10) df2: dim(df2) = (2000,10) Both with column header names, how do I multiply them together please. I.e create a dateframe dim() = (2000,1) Many Thanks in advance Glenn [[alternative HTML version deleted]]

Hi all, I am trying to to merge two data.frames(kk and ff) like > kk a b d 1 1 4 7 2 2 5 8 3 3 6 9 > ff a b d 1 2 5 8 2 3 6 9 3 4 7 1 and g<-rbind(kk,ff) is working perfectly and giving results but if any of the column name changed then its giving "Error in match.names(clabs, names(xi)) : names do not match previous names" like > kk a b d 1 1 4 7 2 2 5 8 3 3

I am trying to do post-hoc tests associated with a repeated measures analysis with on factor nested within respondents. The factor (SOI) has 17 levels. The overall testing is working fine, but I can''t seem to get the multiple comparisons to work. The first step is to "stack" the data. Then I used "lme" to specify and test the overall model. Finally

Dear all, i have a programming problem that should be simple, though i am stuck with it. Please note that this is not a specific geonames problem, though i use it as an example - it´s just a basic problem with lapply. I use the geonames webservices with the R geonames packages which works almost smoothly. I have a vector of Zipcodes and i want to do a geonames lookup for all of them, which

Dear Professor Revelle and R-helpers, This is a two-part question: the first part is general, and the second is specific to the psych package. First question: In the past I've constructed composite variables from questionnaire data by using rowMeans(), and then correlating items with the scale using cor() as an informal check for "bad" items. Over the weekend I decided to take a

useR's, I am trying to find a quick way to change some values in a list that are subject to a condition to be NA. Consider the 3x1 matrix: delta <- matrix(c(2.5,2.5,1), nrow = 1) And consider the list named v that has 3 elements > v v[[1]] [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] [,13] [,14] [1,] 4.25 3.25 2.25 1.25 0.25 0.75 1.75 2.75 3.75 4.25

Dear R helpers I have following dataset rate_number = matrix(c(5, 15, 60, 15, 5, 0, 20, 60, 20,0, 10, 20, 40, 20, 10), nrow = 5, ncol = 3) range_mat = matrix(c(6.25, 6.75, 7.25, 8.75, 9.25, 9.75, 8.5, 9, 9.5, 10.5, 11, 11.5, 4.25, 4.75, 5.25, 5.75, 6.25, 6.75), nrow = 6, ncol = 3) > rate_number        [,1]   [,2]   [,3] [1,]    5     0      10 [2,]   15   20      20 [3,]   60   60      40

Hello, Using the dataset below I produce a soil.texture plot (R code for this included at the end). One will notice I have plotted the points based on whether or not they are in a region called 'upstream' or 'downstream'. I'm curious if there is a way to somehow extract counts of the number of points (red points and blue points) falling within each classification (e.g. silty

Hi everybody, I would like to ask if it is possible using pdf function or some other to print plots in cycle such that every new plot is on new page. like this pdf(file="D:/Plot.pdf",width = 9.25,height=9.25, family="Helvetica",pointsize=8,bg="white") for (i in 1:10){ x <- seq(1,40,1) y <- 2*x+1+5*rnorm(length(x)) hist(y,freq = FALSE) plot(density(y)) }

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Dear R users, A have a dataframe (matrix) with two collumns (plot, and diameter (d)). I want all diameters values for different combination of plots. For example I want all d values for all posible combination, 100C2 (all d values for plot 1 with all d values in the plot 2.......with all d values from plot 1 with all d values from plot 100, ...... with all d values from plot 99 with all d values

Hello R-helpers: I have data like this: sample replicate height weight age A 1.00 12.0 0.64 6.00 A 2.00 12.2 0.38 6.00 A 3.00 12.4 0.49 6.00 B 1.00 12.7 0.65 4.00 B 2.00 12.8 0.78 5.00 C 1.00 11.9 0.45 6.00 C 2.00 11.84 0.44 2.00 C 3.00 11.43 0.32 3.00 C 4.00 10.24 0.84 4.00 D

Hi! These days I have been having trouble with a test that tried to test DateTime functionality. I have discovered that a NULL DateTime is auto-type casted to NIL by Rails. My problem here is that I have a field :datetime and I want to allow NULL datetimes but not wrong datetimes. With this validation if deadline is wrong or if is is blank it returns true. How I can accomplish this? protected def

Hi, I'm having especially hard time today and couldn't find any clue/answer through the internet. ?I hope you can help. I'm in a process of writing a script to estimate error correction model, and I was following an example in Bernhard Pfaff's Analysis of Integrated and Cointegrated Time Series with R. ?I have the following price data: > head(series,15) ?? ? ? ? ? PX_SETTLE

I got the code for how to do regression without an intercept out of the back of my book and the next part of the homework asks me to do it with an intercept. The problem is, Q1 disappears whenever I try. Here is my code: Without the intercept: load("tsa3.rda") > > Q=factor(rep(1:4,21)) > reg=lm(log(jj)~0+trend+Q,na.action=NULL) > model.matrix(reg) trend Q1 Q2 Q3 Q4 1