similar to: How to extract diagonals

Hello Stephen, I am happy that you help me. Thanks a million. It is a good feeling that you confirm my assumption that dsvdis is not able to deal with missing data, because it says me that I am not completely incapable. Okay now I have the problem what to do. I used this function ´cause there is an option to weight columns differently what I haven´t found in other functions. But now I

Hello you all! I am a completely new user of R and I have a problem to solve. I am using Mac OS X on a PowerBook. I have a table that looks like this: species X1 X2 X3 X4 X5 X6 X7 X8 X9 X10 X11 X12 X13 X14 X15 X16 X17 X18 X19 X20 X21 1 Anth_cap1 1 0 0 1 0 1 0 0 1 0 0 0 0 0 0 0 1 0 0 0 1 2 Anth_crin1 1 0 0 1 0 1 0 0 1 0 1

Hello and sorry that I still haven?t found a solution for my problem. I need to extract the lower and upper triangle from a square matrix including the diagonal. This diagonal is not zero in that special case. I tried with as.dist w<-as.dist(w, diag = TRUE) > w 1 2 3 4 5 1 0 2 2 0 3 3 8 0 4 4 9 14 0 5 5 10 15 20 0 but found no way to keep the diagonal that is in the

Hi, I need to run a PCoA (PCO) for a data set wich has both positive and negative values for variables. I  could not find any distancecoefficient other than euclidean distace running for the data set. Are there any other coefficient works with negtive values.Also I cannot get summary out put (the eigen values) for PCO as for PCA.   Thanks. Dilshan [[alternative HTML version deleted]]

Hello, (Power Book G4, Mac OS X, R 2.5.0) I would like to repeat the function range for 85 Vectors (V1-V85). I tried with this code: i<-0 > repeat { + i<-i+1 + if (i<85) next + range (Vi, na.rm = TRUE) + if (i==85) break + } I presume that the Vi is wrong, because in this syntax i is not known as a variable. But I don´t know how to say that it is a variable here. Would be nice if

When I try to load the DCluster package I get the following error message (R 2.5.1; PowerBook G4; Mac OS X 10.4.10) (Load needed package) Lade nötiges Paket: spdep (error: package spdep could not been loaded) Fehler: Paket 'spdep' konnte nicht geladen werden (additional warning message) Zusätzlich: Warning message: (There is no package spdep in:.....) es gibt kein Paket 'spdep'

Hello R users, I am a newby using R 2.5.0 on a Apple Power Book G4 with Mac OS X 10.4.10. Sorry that I ask again such stupid questions, but I haven´t found how to label the points created with plot3d (rgl). Hope somebody can help me. Thanks in advance. Birgit Birgit Lemcke Institut für Systematische Botanik Zollikerstrasse 107 CH-8008 Zürich Switzerland Ph: +41 (0)44 634 8351

Hello members of the mailinglist! I am running R 2.6.0 GUI 1.21 (4815) (4815) on a PPC with Mac OS X 10.4. I just tried to use the R commander. I followed these instructions: 4) Start R (e.g. double-click the R icon in /Applications). 5) Start X11 (e.g. click the X11 button on the R Console or double- click the X11 icon in /Applications/Utilities). 6) Close the X11 terminal (optional). 7) Type

Hello Members, I try to convert variables in a data.frame (bract.awn) in the class ordered. str(bract.awn) 'data.frame': 348 obs. of 2 variables: $ bracts.length.relative.to.flower...............Min: Factor w/ 4 levels "1","2","3","4": 2 3 3 3 3 2 1 4 3 2 ... $ bract.awn.relative.to.body.................Max : Factor w/ 4 levels

R version 2.6.2 PowerBook G4 Hello R User, I try to perform an ANCOVA using the glm function. I have a dataset with continuous and categorical data (explanatory variables) and my response variable is also binary categorical. Fehler: NA/NaN/Inf in externem Funktionsaufruf (arg 4) Zus?tzlich: Warning messages: 1: In Ops.factor(y, mu) : - nicht sinnvoll f?r Faktoren (makes no sense for

Dear all, (Mac OS X 10.4.11, R 2.6.0) I have a quantitative dataset with a lot of Na?s in it. So many, that it is not possible to delete all rows with NA?s and also not possible, to delete all variables with NA?s. Is there a function for a principal component analysis, that can deal with so many NA?s. Thanks in advance Birgit Birgit Lemcke Institut f?r Systematische Botanik

Hello R-user! I am running R 2.7.0 on a Power Book (Tiger). (I am still R and statistics beginner) I try to find the most important variables to divide my dataset as given in a categorical variable using randomForest. Is randomForest() able to deal with count data? Or is there no difference because only the ranks are used in the trees? Thanks in advance Birgit Birgit Lemcke Institut f?r

Hello R-user community! I am running R 2.7.0 on a Power Book (Tiger). (I am still R and statistics beginner) I did the following : pdf("InLnegthMaxHomogeneity.pdf") boxplot(inflorescence_length_Max~Sex, main="Bartletts Homogeneity for inflorescence length",data=FemMal_Sex) Homo<-bartlett.test(FemMal_Sex$inflorescence_length_Max,FemMal_Sex$Sex) text( 2, 500,

Hello! I am R beginner and I have a question obout a simple matching. I have to datasets that i read in with: MalVar29_37<-read.table("MalVar29_37.csv", sep = ";") FemVar29_37<-read.table("FemVar29_37.csv", sep = ";") They look like this and show binary variables: V1 V2 V3 V4 V5 V6 V7 V8 V9 1 0 0 0 0 0 1 0 0 0 2 0 0 0 0 0 1

Hello R users, I am a newby using R 2.5.0 on a Apple Power Book G4 with Mac OS X 10.4.10. when I use the write.table function, I always get the output in Unix linebreaks that I have to change to McIntosh linebreaks to be able to Import the data in Excel 2004 for Mac. Is there a possibility to do this automatically in R and respectively in the write.table function? Thanks in advance.

Hello I need a tiny peace of help. (PPC Mac Os X 10.4.10; R 2.5.1) I have a data.frame with numeric and factor variables. I would like to convert same of the factors to ordered factors. I tried with: attach (table) as.ordered (V3) but this gives me only the V3 Vector as ordred back but in the data.frame (str(Table)) it is still not ordered. How can I do that? Thanks for your help. I am

Hello R user and helper! I would like to get a 3d plot with coloured points. I did that: colors<-c(rep("2",7), rep("3",12), rep("4", 24), rep("5", 13), rep ("6", 8), rep("7", 51), rep("8", 1), rep("9", 15), rep("10", 53), rep ("11",3), rep("12",3), rep("13", 8),

Hi there, I would like to find a more efficient way of permuting the rows and columns of a symmetrical matrix that represents ecological or actual distances between objects in space. The permutation is of the type used in a Mantel test. Specifically, the permutation has to accomplish something like this: Original matrix addresses: a11 a12 a13 a21 a22 a23 a31 a32 a33 Example

Hello R-user! I am running R 2.7.0 on a Power Book (Tiger). (I am still R and statistics beginner) I tried rfImpute (randomForest) and as far as I understood should it replace NA`s using a proximity matrix: > set.seed(100000) > Subset5Imputed<-rfImpute(Sex~., data=Subset5) ntree OOB 1 2 300: 11.78% 12.36% 11.21% ntree OOB 1 2 300: 12.07% 12.64%

Hello R-user! I am running R 2.7.0 on a Power Book (Tiger). (I am still R and statistics beginner) I try to find the most important variables to divide my dataset as given in a categorical variable. code: Test.rf4<-randomForest(Sex~.,na.action=na.roughfix, data=Subset4, importance=TRUE, proximity=TRUE, ntree=10000, do.trace=1000, keep.forest=FALSE) My dataset contains also ordered