similar to: non permanent change of vector values

Hi All, I cannot upgrade r-base and r-recommended because the latest (latest as in it was not listed as 'upgradable' yesterday but today is) r-base-cose is 2.7.1-2hardy0 not hardy1: r-base: Depends: r-base-core (>=2.7.2-1hardy1) but 2.7.1-2hardy0 is to be installed Depends: r-recommended (=2.7.2-1hardy1) but 2.7.1-2hardy0 is to be installed r-base-core: r-recommended:

Hi All, I would like to ask the following. I have an array of data in an objetct, let's say X. I need to use a for loop on the elements of one or more columns of X and I am having a debate with a colleague about the best memory management. I believe that if I do: col1 = X[,1] col2 = X[,2] ... colx = X[,x] and then for(i in whatever){ do something using col1[i], col2[i] ... colx[i] }

Hi All, I have a vector of data, a vector of bin breakpoints and I want to put my data in the bins and then extract fanciful informations like the mean value of each bin. I know I can write my own function, but I would have thought that R should have somewhere a function that took as arguments something like (data, breaks, what to do with the data in the bins). I surey could not find it

Hi All, just a quick (?) question while I wait my code runs... I'm comparing the identity of the lines of a dataframe, doing all possible pairwise comparisons. In doing so I use identical(), but that's by the way. I'm doing a (not so) quick and dirty check, and subsetting the data as data[row.numb,] and data[a different row,] I suspect the problem there is that I load into

Hi All, I have some data I need to write as a file from R to use in a different program. My data comes as a numeric matrix of n rows and 2 colums, I need to transform each row as a two rows 1 col output, and separate the output of each row with a blanck line. Foe instance I need to go from this: V2 V3 27 2032567 19 28 2035482 19 126 2472826 19 132 2473320 19 136 2035480 135

Hi All, I am trying to build a new R package to submit, but it's failing to create a tex manual: R CMD check Biodem * checking for working latex ... OK * using log directory '/home/greatsage/Fede/R-packages/temp/Biodem.Rcheck' * checking for file 'Biodem/DESCRIPTION' ... OK * checking if this is a source package ... OK * Installing *source* package 'Biodem' ... ** R

Hi there, I hope that's not been asked ad nauseam (but I could not find it in the archives...) but, if I put a CRAN mirror in my sources.list and I try to install the latest R version for 'testing' I get the warning that the packages cannot be autenticated. I tried to figure out how to get a GPG key from the mirror I'm using (the austrian one) in case that's the solution,

Hi All, I hate to do this (because I always found the R/Debian combo exceptional and I never had the time to ontribute --sorry about that--), BUT, the latest r-cran-vr for Etch (testing) is dpkg -l | grep r-cran-vr ii r-cran-vr 7.2.29-1 GNU R package accompanying the Venables and Ripley book on S and I get the following error if I try to load MASS

Hi All, I have a list of matrices: > x [,1] [,2] [1,] 1 4 [2,] 2 5 [3,] 3 6 > y [,1] [,2] [,3] [,4] [,5] [,6] [1,] 18 21 24 27 30 33 [2,] 19 22 25 28 31 34 [3,] 20 23 26 29 32 35 > z =list(x,y) I want to create a second list that is has a subset each matrix in the list subsetting so I get the 2nd and 3rd row of each (and

Hi All, is there a way of predicting memory usage? I need to build an array of 86000 by 2500 numbers (or I might create a list of 2 by 2500 arrays 43000 long). How much memory should I expect to use/need? Cheers, Fede -- Federico C. F. Calboli Department of Epidemiology and Public Health Imperial College, St. Mary's Campus Norfolk Place, London W2 1PG Tel +44 (0)20 75941602 Fax +44

Hi All, a colleague wants to calculate the Fisher information matrix for a model he wrote (not in R). He can easily get the neg-log-likelihood and the best fit parameters at the minimum. He can also get negLLs for other parameter values too. Given these data, is there a way in R to calculate the Fisher information matrix? Best, Federico -- Federico C. F. Calboli Department of Epidemiology

Hi All, is there an equivalent of the Unix command 'less' (or 'more'), so I can look at what's inside a data.frame or a matrix without having it printed out on console? I am using R on Debian Linux and Mac OS 10.4.5 Cheers, F -- Federico C. F. Calboli Department of Epidemiology and Public Health Imperial College, St Mary's Campus Norfolk Place, London W2 1PG Tel +44

Hi All, I have the following problem: x = c(1,2) x [1] 1 2 as.matrix(x) [,1] [1,] 1 [2,] 2 BUT, if I add: y = c(3,4) as.matrix(rbind(x,y)) [,1] [,2] x 1 2 y 3 4 It does not transpose. Since I will need as.matrix() for a list of data that is in one or more lines, I need as.matrix to behave in a consisten fashions, so I get as.matrix(x, whatever) [,1] [,2] x 1

Hi All, I am using plot(x, type = 'l') for some plotting, but I would like rounded edges rather than jagged edges in the plot (purely for aestetic reasons). How could I achieve that? Cheers, Federico -- Federico C. F. Calboli Department of Epidemiology and Public Health Imperial College, St Mary's Campus Norfolk Place, London W2 1PG Tel +44 (0)20 7594 1602 Fax (+44) 020

Hi All, I am (almost) successfully using apply() to apply a function recursively on a data matrix. The function is question is as.genotype() from the library 'genetics' apply(subset(chr1, names$breed == 'lab'),2,as.genotype,sep ="") Unfortuantely apply puts it's results into a matrix object rather than a data frame, tranforming my factors into numerics and

Hi All, I have two data frames. The first contains data about a number of individuals, coded in the first column with a name, in an order I find convenient. The second contains different data about the same indivduals, in a different order. Both data frame have the individual names in the first column. I need to reorder the second data frame so the rows are rearranged in the same manner as

Hi everyone, I would like to find out when and where exactly I get the following warning in a piece of code I've written: Error in "[<-"(`*tmp*`, iseq, value = numeric(0)) : nothing to replace with The code is a for () loop performing a somewhat trivial calculation, modulated by a number of logical if(){} else(){} conditions, involving the creation of a number of

Hi All, is there a function in R that allows me to work with fractions without transforming them to floats (or whatever) in between? Something that would calculate something like: (1/2 + 1/8) * 1/2 = 5/16 without ever transforming to 0.5 and 0.125? Best, Federico -- Federico C. F. Calboli Department of Epidemiology and Public Health Imperial College, St Mary's Campus Norfolk Place,

Dear All, I saved by mistake the environment I was working in after typing q(), and now I get the annoying message: [Previously saved workspace restored] I have already deleted all the objects in the environment, saving it as an empty environment, so it's just a matter of nitpicking I suppose. The message does not appear if I start R from any other place in the directory tree. I am

Have a look at merge. Ciao Vittorio >----Messaggio originale---- >Da: f.calboli at imperial.ac.uk >Data: 23-giu-2006 18.10 >A: "r-help"<r- help at stat.math.ethz.ch> >Ogg: [R] rearranging data frame rows > >Hi All, > >I have two data frames. The first contains data about a number of individuals, >coded in the first column with a name, in an order