similar to: making a Time of Day axis

Hello there, Using R 2.4.0 on Solaris (Unix): I am trying to control the X axis range on a simple time of day plot. I made a test program (below) that gets file time stamp information from the files in the directory where R starts. The goal of the test program is to plot the time of day of file creation on an x axis that spans a user-specified range (like 12:00:00 to 15:00:00). If I allow

Just installed Rcmdr on a Linux box. When I exit from both Rcmdr and R together from the regular Rcmdr exit menu, it leaves my xterm with "stty -echo", so that nothing that is typed appears. If I exit only Rcmdr, and then exit R normally, everything is okay (stty echo). Other than that minor irritant, everything seems to work just fine. Linux 2.6.16-gentoo-r3 Athlon 64 X2 3800+ R

I was just looking for an easy way to convert between COM datetime and chron datetime (both ways.) I found examples on the list, but they involved origin. Does anyone have functions for converting COM datetime <-> chron datetimethat work "safely"? David L. Reiner > -----Original Message----- > From: Gabor Grothendieck [mailto:ggrothendieck@gmail.com] >

Hi everyone, Once again I am stuck with a problem I can't seem to figure out. I suppose this learning curve levels off eventually, lol. I am learning on my own with absolutely no background in programming, so if I seem to request help a lot it's not because I am seeking others to do the work for me. I need to assign one of two arrival times to the 'ARRIVE' variable of my

Hi, Is there some alternative to cumsum for chron objects? I have data frames that contain some chron objects that look like this: DateTime 13/10/03 12:30:35 NA NA NA 15/10/03 16:30:05 NA NA ... and I've been trying to replace the NA's so that a date/time sequence is created starting with the preceding available value. Because the number of rows with NA's following each available

I am was going to look at the as.yearmon function in the zoo package and write a as.day function to aggregate a time series of 96 observations per day into the mean for each day, but I don't know how to look at the code so that I can convert it into something I can use. On top of that I believe that it is probably an S3 method and I haven't quite gotten that far in my programming

I know that this is correct: library(chron) x = dates("01-03-04", format="d-m-y", out.format="day mon year") print(x) It gives me the string "01 Mar 2004" which is correct. I also know that I can say: print(day.of.week(3,1,2004)) in which case he says 1, for today is monday. My question is: How do I combine these two!? :-) I have a

# chron library(chron) fmt.chron <- function(x) { chron(sub(" .*", "", x), gsub(".* (.*)", "\\1:00", x)) } z1 <- read.zoo(SC3.csv, sep = ",", header = TRUE, FUN = fmt.chron) z2 <- read.zoo(SC2.csv, sep = ",", header = TRUE, FUN = fmt.chron) z3<-c(z1, z2) write.table(z3, sep="," , "SC.csv") How do you

I've always found the chron library to be useful for tasks like this: > x <- round(runif(10)*100000, digits=0) > y <- as.Date(x, origin="1970-01-01") > library(chron) > days(y) [1] 7 25 26 25 10 24 1 31 12 8 31 Levels: 1 < 2 < 3 < 4 < 5 < 6 < 7 < 8 < 9 < 10 < 11 < 12 < 13 < ... < 31 Notice that it returns the days as

I would like to merge zoo objects that are stored in a list into one big zoo object with one index for all of the observations. I have created the list (74 dataframes) with the code below, and have tried the do.call(merge, foo) in the call and the output is not what I expected. Any help would be greatly appreciated. Stephen Sefick ###################################################level logger

Hi, Whats the easiest way to set a desired interval for tics on axes in R ? And will the 'grid' command put gridlines on all tics automatically ? I tend to get stuck with graphs with ranges 0-1 with only 2 tics and 2 gridlines in the 0-1 range, while I would like 10 tics (or every 0.1) tnx, Piet please reply to pvremortNOSPAM at vub.ac.be

hello I think I've found a bug I don't know if it's a chron bug or a R one. (05/12/05 23:00:00) +1/24 gives (05/12/05 24:00:00) instead of (05/13/05 00:00:00) it looks like the same but it's not because when you get the date of this datetime it says day 12 instead of 13. Please, forward it to the place where this bugs are supposed to be posted. cheers -- View this message

Dear list, I'm writing a function to re-grid a data set from finer to coarser resolutions in R as follows (I use this function with sapply/apply): gridResize <- function(startVec = stop("What's your input vector"), to = stop("Missing 'to': How long do you want the fnial vector to be?")){ from <- length(startVec) shortVec<-numeric() tics <- from*to

Question: 1: What is .Mod and .Tod video? 2: How to convert .Mod and .Tod video to AVI, MPG, WMV, MPEG? Answer: 1: .Mod and .Tod videos are mainly produced by digital harddisk camcorder such as JVC camcorder and so on. It is not common video formats and can only be played on some special players. 2:Tipard Mod Converter (http://www.tipard.com/mod-converter.html)Windows and Tipard Mod Converter for

DateTime RM61 11/30/2006 12:31 NA 11/30/2006 12:46 NA 11/30/2006 13:01 2646784125 11/30/2006 13:16 NA 11/30/2006 13:31 NA 11/30/2006 13:46 NA 11/30/2006 14:01 2666435177 11/30/2006 14:16 NA 11/30/2006 14:31 NA 11/30/2006 14:46 NA 11/30/2006 15:01 2653041914 11/30/2006 15:16 NA 11/30/2006 15:31 NA 11/30/2006 15:46 NA 11/30/2006 16:01 2693126189 11/30/2006 16:16 NA 11/30/2006 16:31 NA 11/30/2006

Hi! Is not there an standard R function to retrieve the day of the year (since 1st Jan of the same year)? I know I can make my own using julian, but find it weird that having days(), months() etc doy() does not exist as an standard function. Also, is the following not a bit inconsistent? > a <- chron("20100506",format="ymd") > a [1] 100506 > years(a) [1] 2010

There must be a simple answer to this. I'm running ubuntu gutsy, currently have 2.7.2 loaded, but the update tools refuse to update it, and don't tell me why. With apt-get I get : [668 ~]$ sudo apt-get -u -V --simulate dist-upgrade Reading package lists... Done Building dependency tree Reading state information... Done Calculating upgrade... Done The following packages have been

Hi All, I am attempting to work with some data from loggers. I have read in a .csv exported from MS Access that already has my dates and times (in 24 clock format), (with StringsAsFactors=FALSE). > head(tdata) LogData date time 1 77.16 2008/04/24 02:00 2 61.78 2008/04/24 04:00 3 75.44 2008/04/24 06:00 4 89.43 2008/04/24

It seems is.weekend() is unsure ? # Start R 1.9.0 with --vanilla on windows xp # load package chron > table(is.weekend(sapply(1:100, function(i){Sys.sleep(0.05);Sys.time()}))) FALSE TRUE 68 32 > date() [1] "Wed May 26 11:18:56 2004" > version _ platform i386-pc-mingw32 arch i386 os mingw32 system i386, mingw32

Hello all, I don' like to have ( ) around my datetime, when send the csv file to somebody. How to remove it? >library(chron) >mydate <- c("2009-05-03","2009-06-07") >mytime <- c("10:30:00","10:20:00") >mydatetime <- chron(dates=mydate,times=mytime,format=c("y-m-d","h:m:s")) >write.csv(mydatetime)