similar to: Use of the "by" command for gini()

Well apparently this has nothing to do with the gini() command. I cannot get it to work for something as simple as sum() Here is the little example I am playing with, maybe someone can help me find my error: a<-c("A","B","C","A","B","C","A","A","C","B")

Hi there, I am trying to compute Gini coefficients for vectors containing income classes. The data I possess look loke this: yit <- c(135, 164, 234, 369) piit <- c(367, 884, 341, 74 ) where yit is the vector of income classes, and fit is the vector of associated frequencies.(This data is from Rustichini, Ichino and Checci (Journal of Public Economics, 1999) ). In ineq pacakge, Gini( )

Hi. I have some data from a survey w/c include income data. Was not quite sure how to generate the gini index on these data. Jose Ramon Albert Statistical Research and Training Center www.srtc.gov.ph -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info",

Hello, Thank you very much for your help. How can I draw a Lorenz curve with several replications ? Here is an example with 4 replications: hosts=c(23,31,19,10,7,7,3, 39,40,8,3,6,2,2, 47,17,8,10,6,11,1, 30,30,10,0,15,15,0) parasites=rep(seq(from=0,to=6,by=1),4) replications=c(rep(1,7),rep(2,7),rep(3,7),rep(4,7)) test <- cbind(parasites,hosts,replications) Should I

Hello dear R-help members, I would appreciate any help in understanding how the rpart function computes the "improve" (which is given in fit$split) when using the split='information' parameter. Thanks to Professor Atkinson help, I was able to find how this is done in the case that split='gini'. By following the explanation here:

If I use the Ineq library and the Gini function in this way: >Gini(c(100,0,0,0)) I obtain the result 0.75 instead of 1 (that is the perfect inequality). I think Gini's formula in Ineq is based on a formula as reported here: http://mathworld.wolfram.com/GiniCoefficient.html but in the case of perfect inequality: x_1=.......=x_n-1 =0 x_n>0 these formula are equal to 1 - 1/n, not to

Hi listers, Does it necessary to install any package in order to use the GINI or INEQ functions. If I use the following command the R tells me that didn't find the GINI function. x<-c(541, 1463, 2445, 3438, 4437, 5401, 6392, 8304, 11904, 22261) G<-gini(x) Thanks in advance, Marcio -- View this message in context:

Hello, I would like to build a Lorenz curve and calculate a Gini coefficient in order to find how much parasites does the top 20% most infected hosts support. Here is my data set: Number of parasites per host: parasites = c(0,1,2,3,4,5,6,7,8,9,10) Number of hosts associated with each number of parasites given above: hosts = c(18,20,28,19,16,10,3,1,0,0,0) To represent the Lorenz curve: I

Dear all, I am working with randomForest package and I am interested in examining the "Gini importance" measures that are used as a general indicator of feature relevance. Is there a possibility of getting the Gini measure that is being estimated in each tree by the output of the getTree() function? Thanks a lot, Chrysanthi [[alternative HTML version deleted]]

Dear List, I am unsure if this is specifically a R question or a stats question? I thought i would ask here and if i get no replies it will answer that! I am trying to calculate Gini coefficients in R, based on a slight modification of the typical equation that i have seen in a paper. -------------- next part -------------- A non-text attachment was scrubbed... Name: PastedGraphic-2.pdf Type:

Hola, paso el mini programita q estoy viendo, lo q me llama la atencion es una parte donde se definen las funciones. Probe primero meter adentro del boots la estadistica a estimar usando directamente gini(varible, pesos) pero no me dejo. Vi q en el ej del manual de boots, siempre define antes la funcion, entonces probe definir antes una funcion haciendo grini<-function(x) {gini(variable,

Hey there, I was wondering if someone could tell me if there's a package or command that allows me to compute a GINI coefficient using a vector of weights. Also the coefficient should be bias corrected. Diego Rojas [[alternative HTML version deleted]]

Dear R-users, I'm working with the Rpart package and trying to understand how the procedure select the best split in the case the method "class" and the splitting index "Gini" are used. In particular I'd like to have look to the source code that works out the best split for un unordered predictor. Does anyone can suggest me which functions in the sources I should

Dear All, I have developed a programme the anable the decomposition of the Gini index, it complets tha valuable work of Achim Zeileis, the author of the ineq package. I would like to make it to be part of all R package. How should I proceed. Must I sent it to the the Core developement team ? The proogramme is written in R. Many thanks for your advice, Best regards, Souleymane

Dear All, I wish to calculate the Gini index (ineq from same package) and some other indices for the diameter distribution of each plot (df dgtot). dgtot: IDPlot Diameter(cm) 1 4 34.0 2 4 23.0 3 4 38.0 ... 51 5 16.0 52 5 8.0 53 5 9.0 ... 5301 140 25.0 5302 140 12.0 5303 140 7.0 I use: >

Dear R helpers: I have another question regarding "R" command. It is also measuring Credit Scoring. I need to measure the classifying method for customer's credit score. (ex. regression line by Fisher) If credit card company already classify their customers credit : Good customers / Bad customers [by using regression line; ex) inside of line: Good/ outside: Bad] And I found

Hello, Is there a way to create random numbers that fit a certain specified requirement other than distributional characteristics. In particular, I would like to create simulated income distributions with certain gini coefficient Ryan -- Ryan Murphy 2012 B.A. Economics and Mathematics [[alternative HTML version deleted]]

binequality looks like just the package I need, specifically for obtaining Gini income coefficients for binned data. I have upgraded to the latest version of R, the latest version of RStudio, and updated all packages. Still I have a persistent problem using fitFunc(). To keep things simple, I am testing things using the example code in the binequality manual, page 6 (or, "?fitFunc").

Hi, I would like to change permissions of /dev/sda* and /dev/hda* files to 0644. I added the following rules to 99-udev.rules files: KERNEL=="[hs]d*", OWNER="root" GROUP="disk", MODE="0644 After restarting udev by strat_udev, I checked that permissions were changed: [root at gini rules.d]# ll /dev/sda* brw-r--r-- 1 root disk 8, 0 Sep 2 2009 /dev/sda

Hi all, I apologies in advance if I am missing something very simple here, but since I failed at resolving this myself, I'm sending this question to the list. I would appreciate any help in understanding how the rpart function is (exactly) computing the "improve" (which is given in fit$split), and how it differs when using the split='information' vs split='gini'