similar to: Retain names in conversion of matrix to vector

Listers, I have created a cross-tab matrix using the following code: S <- c(1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,1,2,3,1,1,2,3,1,2,2) F <- c(1,2,3,1,2,3,1,1,1,1,2,3,1,1,3,2,2,2,1,2,3,1,1,1,1,2,3,3,1,3,1,3,1,1,2,3,1,1,3,2,3,2,1,1,1,2,3,1,1,2) table(S,F) fF <-factor(F, labels = c("Dem","Ind","Rep")) fS <-factor(S,

Hola, Estoy tratando de crear una matriz cuadrada, binaria y no tengo idea por dónde comenzar. Los datos que tengo son patentes e inventores por patente, las patentes las identifico por su código y a los inventores por nombre y también los tengo codificados. Deseo hacer una matriz de nxn en donde los renglones son inventores de la A a la Z y columnas son los mismos inventores de la A a la Z,

Dear R-listers, I am trying to assign colnames to a data frame within a loop, but I keep getting a "target of assignment expands to non-language object"-error. I need to split up a large dataset into about 20 smaller ones, and I would like to assign colnames within the loop, so I won't have to type the same thing 20 times over. I have concocted this really goofy example which

Hi Guys, I have this part of a program: library(survival) Gastric <- cbind.data.frame(Gp=c(rep(1,45),rep(0,45)), ### 2nd gp 0 time=c(1,63,105,129,182,216,250,262,301,301,342,354,356,358, 380,383, 383,388,394,408,460,489,499,523,524,535,562,569,675,676, 748,778,786,797,955,968,1000,1245,1271,1420,1551,1694,2363,2754,2950,

Hola, no encuentro el momento en el que se relacionan los inventores, es decir, lo que relaciona a dos o más inventores es la patente. Primero, ¿cómo debo ordenar los datos? Tengo 1813 número de patentes, es decir, la matriz es de dimension 1813 x 1813. Tengo varios órdenes en los datos, por ejemplo, el primer arreglo es por patente, en las columnas tengo ?no. de patente?, ?inventor 1?,

Dear all: This is one of those "should be easy" problems that I'm having great difficulty solving. I have a vector containing ID codes, and I need to generate a 3-column matrix that contains all possible combinations of three. For example, my ID vector looks like this: A B C D E I need to generate a matrix that looks like this: A B C A B D A B E A C B A C D A C E A D B A D C A D E

Hi, I would like to generate a correlation matrix with a particular structure. For example, a 3n x 3n matrix : A_(nxn) aI_(nxn) bI_(nxn) aI_(nxn) A_(nxn) cI_(nxn) aI_(nxn) cI_(nxn) A_(nxn) where - A_(nxn) is a *specified* symmetric, positive definite nxn matrix. - I_(nxn) is an identity matrix of order n - a, b, c are (any) real numbers Many attempts have been unsuccessful because a

I just installed R-devel to check my package before submitting. I got an error in my vignette in regards to as.vector. When I looked at the code for as.vector in R-devel it is standardGeneric for "as.vector" defined from package "base" function (x, mode) standardGeneric("as.vector") <environment: 0x0918ad70> Methods may be defined for arguments: x, mode Use

Dear listers, After activating the name space for my bioconductor package (prada) I successfully ran R CMD check. However when loading the package in R and running the examples the imported function brewer.pal from package RColorBrewer is not found. I can directly call brewer.pal from the RColorBrewer name space typing RColorBrewer::brewer.pal, but it is not imported into my prada name space. When

Dear listers, After activating the name space for my bioconductor package (prada) I successfully ran R CMD check. However when loading the package in R and running the examples the imported function brewer.pal from package RColorBrewer is not found. I can directly call brewer.pal from the RColorBrewer name space typing RColorBrewer::brewer.pal, but it is not imported into my prada name space. When

Dear Listers, I am trying to match tables that DO NOT have the same length. The tables result from the function "table()" so they look like this: table 1 2 3 4 3 5 7 table 2 1 2 3 6 4 5 I need the following output: (NOTICE THE ZEROS) 1 2 3 4 table1 0 3 5 7 table2 6 4 5 0 Unfortunately, I was not successful using "match()". Previous postings explain how to do

Dear Listers: I have a couple of data frames to report and each corresponds to different condtions, e.g. conditions=c(10, 15, 20, 25). In this examples, four data frames need to be exported in a "pretty" report. I knew Perl has some module for exporting data to Excel and after googling, I found R does not. So I am wondering if there is a package in R for generating good reports. I

I spent a lot of time searching and came up empty handed on the following query. Is there an equivalent to rowSums that does product or cumulative product and avoids use of apply or looping? I found a rowProd in a package but it was a convenience function for apply. As part of a likelihood calculation called from optim, I?m computing products and cumulative products of rows of matrices with

The code below create an nxn upper triangular matrix of one's. I'm stuck on finding a more efficient vectorized way - Thanks. --Dale n <- 9 data <- matrix(data=NA, nrow=n, ncol=n) data for (i in 1:n) { data[,i] <- c(rep(1,i), rep(0,n-i)) } data

Dear list, I'm trying to download a text file directly from the internet using the RCurl package and the command getURL. Duncan Lang graciously helped me solve the first step in this problem using the following command: ################# txtfile <- getURL('ftp://ftp.wcc.nrcs.usda.gov/data/snow/snow_course/table/history/idaho/13e19.txt', ftp.use.epsv = FALSE) #################

Any insight into the behavior of "by" in the following case would be appreciated. There is a note in the help details for "by" about documenting behavior since v2.7 but I don't entirely understand what it is saying. I'm using R2.7.2 Windows. I'm interested if the following behavior was a change or whether it has always worked this way. I looked at

Hi, I tried looking through google search on whether there's a way to computer the median for each row of a nxn matrix and return the medians for each row for further computation. And also if the number of columns in the matrix are even, how could I specify which median to use? Thank you very much! -- Edward Chen [[alternative HTML version deleted]]

Dear Listers, I am wondering how to convert multiple dummy variables to 1 factor variable. Thanks. wensui

Dear Rusers, Trying to reduce my for loops addiction, could somebody tell me if there are ways to simplify (and perhaps accelerate ?) the following line for (i in 1:N) for (j in 1:N) m[i,j] = b[i]-b[j]; (where m is a NxN matrix and b a vector of length N) Thanks for any hint.

> S-Plus has the function AggregateSeries() whose name is self > explanatory. For instance one can derive monthly series from daily > ones by specifying end-of-period, averages, sums, etc. I looked for > a similar function in the packages "its" and "tseries", but found > nothing. I also help.searched() for aggregate to no avail. Would > anybody be so kind